13届浙江省省赛 A题 Apples and Ideas

"If you have an apple and I have an apple and we exchange these apples then you and I will still each have one apple. But if you have an idea and I have an idea and we exchange these ideas, then each of us will have two ideas." - George Bernard Shaw

Now Alice has A apples and B ideas, while Bob has C apples and D ideas, what will they have if they exchange all things?

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

The only line contains four integers A, B, C, D (0 <= A, B, C, D <= 100) - as the problem described.

Output

For each test case, output two lines. First line contains two integers, indicating the number of Alice's apples and ideas; second line contains two integers, indicating the number of Bob's apples and ideas.

Sample Input

4
0 0 5 30
20 25 20 0
20 25 20 15
20 25 25 30

Sample Output

5 30
0 30
20 25
20 25
20 40
20 40
25 55
20 55

大概题意：苹果相加则是苹果，点子相加则是和；

题解：idea是和 ； appl则分别为两项的值，而表达式为， c , b+d ; a ,b+d ;

AC代码：

#include <bits/stdc++.h>
using namespace std ;
int dp1[50000], dp2[50000];
int main()
{
    int t  ;
    int flag;
    while(cin>>t)
    {
        memset(dp1,0,sizeof(dp1));
        memset(dp2,0,sizeof(dp2));
        int a , b , c  , d ;
        flag = 0 ;
        for(int i = 0 ; i < t ; i++)
        {
            cin>>a>>b>>c>>d;
            int sum = b+d;
            dp1[flag] = c;
            dp2[flag] = sum;
            flag++;
            dp1[flag] = a;
            dp2[flag] = sum;
            flag++;
        }
        for(int i = 0 ; i < flag ; i++)
        {
            printf("%d %d\n",dp1[i],dp2[i]);
        }
    }
    return 0 ;
}