几种常见的【排序】与【数据结构】

(一)常见排序


import java.util.Arrays;

public class Sort {
//快速排序
    private static int partition(int[] arr, int low, int hight) {
        int pivotkey = arr[low];
        while (low < hight) {
            while (low < hight && pivotkey <= arr[hight])
                --hight;
            int temp1 = arr[low];
            arr[low]=arr[hight];
            arr[hight]=temp1;
            //arr[low] = arr[hight];
            while (low < hight && pivotkey >= arr[low])
                ++low;
            int temp2 = arr[low];
            arr[low]=arr[hight];
            arr[hight]=temp2;
            //arr[hight] = arr[low];
        }
        return low;
    }
//快速排序
    public static void qSort(int[] arr, int low, int hight) {
        if (low < hight) {
            int pivotkey = partition(arr, low, hight);
            qSort(arr, low, pivotkey - 1);
            qSort(arr, pivotkey + 1, hight);
        }
    }
//插入排序
    public static int[] insertOrder(int a[]){
        for (int i = 1; i < a.length; i++) {
            int k = a[i];
            int j;
            for (j = i - 1; j >= 0 && k < a[j]; j--) {
                a[j + 1] = a[j];
            }
            a[j + 1] = k;
            //System.out.println(Arrays.toString(a));
        }
        return a;
    }
    //冒泡排序
    public static int[] maopao(int[] a){

        for(int i=0;i<a.length-1;i++){//i 代表伦次
            for(int j=0;j<a.length-i-1;j++){//j和j+1代表相邻元素
                if(a[j]>a[j+1]){
                    int temp = a[j];
                    a[j]= a[j+1];
                    a[j+1]=temp;
                }
            }
            //System.out.println(Arrays.toString(a));
            //Arrays.sort(a);
        }
        return a;
    }
    //选择排序
    public int[] selectOrder(int arr[] ) {
        for (int i = 0; i <arr.length; i++) {
            int max = arr[i];
            for (int j = i + 1; j < arr.length; j++) {
                if (arr[j] < max) {
                    int temp = arr[j];
                    arr[j] = max;
                    max = temp;
                    arr[i] = max;
                }
            }
        }
        return arr;
    }

    // 二分查找
        public void binarySearch() {
            int b[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16 };
            int start = 0;
            int end = b.length - 1;
            int mid;
            int target = 1;
            while (true) {
                mid = ((end + start) / 2);
                if (b[mid] == target) {
                    System.out.println(mid);
                    break;
                }
                if (target < b[mid]) {
                    end = mid;
                }
                if (target > b[mid]) {
                    start = mid + 1;
                }

            }
        }

    public static void main(String args[]) {
        int Arr[] = { 10, 30, 20, 50, 90, 80, 60, 40, 70 };
        System.out.println(Arrays.toString(Arr));
        qSort(Arr, 0, Arr.length -1);
        System.out.println(Arrays.toString(Arr));
    }
}
希尔排序:
算法思想

它是对插入插入排序的改进

搜索维基百科可知 
希尔排序,也称递减增量排序算法
假设有这样一组数[ 13 14 94 33 82 25 59 94 65 23 45 27 73 25 39 10 ] 
,我们分别以步长为531进行排序(希尔排序最后的步长一定是1)

步长为5,我们可以得到如下数据, 
13 14 94 33 82 
25 59 94 65 23 
45 27 73 25 39 
10
然后 按照列排序 
10 14 73 25 23 
13 27 94 33 39 
25 59 94 65 82 
45

将上述四行数字,依序接在一起时我们得到:[ 10 14 73 25 23 13 27 94 33 39 25 59 94 65 82 45 ].这时10已经移至正确位置了,然后再以3为步长进行排序: 
10 14 13 
25 23 33 
27 25 59 
39 65 73 
45 94 82 
94 
-最后以1步长进行排序(此时就是简单的插入排序了)。

public static void shellPass(Integer[] array, int d) {
for (int i = d; i < array.length; i++) {
int temp = array[i];
int j = i - d;
while (j >= 0 && array[j] > temp) {
array[j + d] = array[j];
j -= d;
}
array[j + d] = temp;
}
}

public static void shellSort(Integer[] data) {
int increment = 12;
do {
increment = increment / 3 + 1;
shellPass(data, increment);
} while (increment > 1);

}

(二)常见数据结构
2.1 graph
2.1.1图节点

public class GraphNode {
    int val;
    GraphNode next;
    GraphNode[] neighbors;
    boolean visited;

    GraphNode(int x) {
        val = x;
    }

    GraphNode(int x, GraphNode[] n){
        val = x;
        neighbors = n;
    }

    public String toString(){
        return "value: "+ this.val; 
    }
}

2.1.2队列


public class Queue {
     GraphNode first, last;

        public void enqueue(GraphNode n){
            if(first == null){
                first = n;
                last = first;
            }else{
                last.next = n;
                last = n;
            }
        }

        public GraphNode dequeue(){
            if(first == null){
                return null;
            }else{
                GraphNode temp = new GraphNode(first.val, first.neighbors);
                first = first.next;
                return temp;
            }   
        }
}

2.1.3测试类

public class GraphTest {
    public static void main(String[] args) {
        GraphNode n1 = new GraphNode(1); 
        GraphNode n2 = new GraphNode(2); 
        GraphNode n3 = new GraphNode(3); 
        GraphNode n4 = new GraphNode(4); 
        GraphNode n5 = new GraphNode(5); 

        n1.neighbors = new GraphNode[]{n2,n3,n5};
        n2.neighbors = new GraphNode[]{n1,n4};
        n3.neighbors = new GraphNode[]{n1,n4,n5};
        n4.neighbors = new GraphNode[]{n2,n3,n5};
        n5.neighbors = new GraphNode[]{n1,n3,n4};

        breathFirstSearch(n1, 5);
    }

    public static void breathFirstSearch(GraphNode root, int x){
        if(root.val == x)
            System.out.println("find in root");

        Queue queue = new Queue();
        root.visited = true;
        queue.enqueue(root);

        while(queue.first != null){
            GraphNode c = (GraphNode) queue.dequeue();
            for(GraphNode n: c.neighbors){

                if(!n.visited){
                    System.out.print(n + " ");
                    n.visited = true;
                    if(n.val == x)
                        System.out.println("Find "+n);
                    queue.enqueue(n);
                }
            }
        }
    }
}

2.2link
2.2.1链表实例节点

public class Node {
    int val;
    Node next;

    Node(int x) {
        val = x;
        next = null;
}
}

2.3Queue
2.3.1队列节点

public class Node {
    int val;
    Node next;

    Node(int x) {
        val = x;
        next = null;
}
}

2.3.2队列操作类


public class Queue {
    Node first, last;

    public void enqueue(Node n){
        if(first == null){
            first = n;
            last = first;
        }else{
            last.next = n;
            last = n;
        }
    }

    public Node dequeue(){
        if(first == null){
            return null;
        }else{
            Node temp = new Node(first.val);
            first = first.next;
            return temp;
        }   
    }
}

2.4stack
2.4.1栈的节点

public class Node {
    int val;
    Node next;

    Node(int x) {
        val = x;
        next = null;
}
}

2.4.2栈的操作类


public class Stack {
    Node top; 

    public Node peek(){
        if(top != null){
            return top;
        }

        return null;
    }

    public Node pop(){
        if(top == null){
            return null;
        }else{
            Node temp = new Node(top.val);
            top = top.next;
            return temp;    
        }
    }

    public void push(Node n){
        if(n != null){
            n.next = top;
            top = n;
        }
    }
}

2.5Tree
2.5.1数的节点

public class TreeNode {
    int value;
    TreeNode left;
    TreeNode right;
}

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