K&R C Bible Increment and Decrement Operators

Increment and Decrement Operators

C provides two unusual operators for incrementing and decrementing variables. The increment operator ++

adds 1 to its operand, while the decrement operator -- subtracts 1. We have frequently used ++ to increment

variables, as in

if (c == '/n')

++nl;

The unusual aspect is that ++ and -- may be used either as prefix operators (before the variable, as in ++n),

or postfix operators (after the variable: n++). In both cases, the effect is to increment n. But the expression

++n increments n before its value is used, while n++ increments n after its value has been used. This means

that in a context where the value is being used, not just the effect, ++n and n++ are different. If n is 5, then

x = n++;

sets x to 5, but

x = ++n;

sets x to 6. In both cases, n becomes 6. The increment and decrement operators can only be applied to

variables; an expression like (i+j)++ is illegal.

In a context where no value is wanted, just the incrementing effect, as in

if (c == '/n')

nl++;

prefix and postfix are the same. But there are situations where one or the other is specifically called for. For

instance, consider the function squeeze(s,c), which removes all occurrences of the character c from the

string s.

/* squeeze: delete all c from s */

void squeeze(char s[], int c)

{

int i, j;

for (i = j = 0; s[i] != '/0'; i++)

if (s[i] != c)

s[j++] = s[i];

s[j] = '/0';

}

Each time a non-c occurs, it is copied into the current j position, and only then is j incremented to be ready

for the next character. This is exactly equivalent to

if (s[i] != c) {

s[j] = s[i];

j++;

}

Another example of a similar construction comes from the getline function that we wrote in Chapter 1,

where we can replace

if (c == '/n') {

s[i] = c;

++i;

}

by the more compact

if (c == '/n')

s[i++] = c;

As a third example, consider the standard function strcat(s,t), which concatenates the string t to the

end of string s. strcat assumes that there is enough space in s to hold the combination. As we have written

it, strcat returns no value; the standard library version returns a pointer to the resulting string.

/* strcat: concatenate t to end of s; s must be big enough */

void strcat(char s[], char t[])

{

int i, j;

i = j = 0;

while (s[i] != '/0') /* find end of s */

i++;

while ((s[i++] = t[j++]) != '/0') /* copy t */

;

}

As each member is copied from t to s, the postfix ++ is applied to both i and j to make sure that they are in

position for the next pass through the loop.

Exercise 2-4. Write an alternative version of squeeze(s1,s2) that deletes each character in s1 that

matches any character in the string s2.

Exercise 2-5. Write the function any(s1,s2), which returns the first location in a string s1 where any

character from the string s2 occurs, or -1 if s1 contains no characters from

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