leetcode -- Contains Duplicate III -- 重点，medium题目

https://leetcode.com/problems/contains-duplicate-iii/

思路1 sorting

参考http://yucoding.blogspot.hk/2015/10/leetcode-question-contains-duplicate-iii.html

思路就是带着index一起，先对value进行排序，然后从左到右用p scan，然后对i = p + 1, 再scan后面的数，如果val的差已经大于t那么就不用继续往后scan了。这里复杂度应该还是O(n^2)

class Solution(object):
    def search(self, l, t, k):
        po = 0
        while po < len(l):
            i = po + 1
            while i < len(l):
                if abs(l[i][0] - l[po][0]) <= t and abs(l[i][1] - l[po][1]) <= k:
                    return True
                else:
                    if abs(l[i][0] - l[po][0]) > t:
                        break
                    else:
                        i +=1
            po += 1
        return False    

    def containsNearbyAlmostDuplicate(self, nums, k, t):
        """ :type nums: List[int] :type k: int :type t: int :rtype: bool """
        pp = sorted(zip(nums, range(len(nums))), key= lambda x:x[0])
        return self.search(pp,t ,k )

思路2 sliding windows

参考http://bookshadow.com/weblog/2015/06/03/leetcode-contains-duplicate-iii/

这个思路还没理解。再看看