HDU 1012 u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 24219    Accepted Submission(s): 10729

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

   
   
   
   

    
    
    
    n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
   
   
   
   

 

Source

Greater New York 2000

 

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注意输出格式

#include<stdio.h>
int main ()
{
	printf("n e\n");
	printf("- -----------\n");
	printf("0 1\n");
	printf("1 2\n");
	printf("2 2.5\n");
	printf("3 2.666666667\n");
	printf("4 2.708333333\n");
	double a[20]={1,1};
	int i , j;
	for(i = 2; i <= 10; i++)
		a[i] = a[i-1]*i;
 	for(i = 5; i < 10; i++)
	{
		double temp = 0;
		for(j = 0; j <= i; j++)
			temp +=	1.0/a[j];
		printf("%d ",i);
		printf("%11.9lf\n",temp);
	}
	return 0;
}