第一感觉,step跟mod的最大公约数应该为1,这样就满足了,尝试了一下,AC,但是不懂解释,钥匙比赛能有这感觉多好。。
#include <stdio.h> int gcd(int a, int b) { return b == 0 ? a : gcd(b, a % b); } int main() { int step, mod; while(~scanf("%d%d", &step, &mod)) { printf("%10d%10d ", step, mod); if(gcd(step, mod) == 1) printf("Good Choice/n/n"); else printf("Bad Choice/n/n"); } return 0; }
其实数据量不大,枚举也能过。
#include <stdio.h> #include <string.h> bool isVis[100001]; int gcd(int a, int b) { return b == 0 ? a : gcd(b, a % b); } int main() { int step, mod; while(~scanf("%d%d", &step, &mod)) { printf("%10d%10d ", step, mod); memset(isVis, false, sizeof(isVis)); isVis[0] = true; int seed = 0; int count = 1; while(true) { int tmp = (seed + step) % mod; if(isVis[tmp]) break; count++; isVis[tmp] = true; seed = tmp; } if(count == mod) printf("Good Choice/n/n"); else printf("Bad Choice/n/n"); } return 0; }