C#判断一个string是否可以为数字

方案一：TryCatch(执行效率不高)
private   bool  IsNumberic( string  oText)
{
          try
         {
                  int var1=Convert.ToInt32 (oText);
                  return true;
         }
          catch
         {
                  return false;
         }
}

方案二：正则表达式(推荐)
a)
using  System;
using  System.Text.RegularExpressions;

public   bool  IsNumber(String strNumber)
{
           Regex objNotNumberPattern=new Regex("[^0-9.-]");
           Regex objTwoDotPattern=new Regex("[0-9]*[.][0-9]*[.][0-9]*");
           Regex objTwoMinusPattern=new Regex("[0-9]*[-][0-9]*[-][0-9]*");
           String strValidRealPattern="^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$";
           String strValidIntegerPattern="^([-]|[0-9])[0-9]*$";
           Regex objNumberPattern =new Regex("(" + strValidRealPattern +")|(" + strValidIntegerPattern + ")");

           return !objNotNumberPattern.IsMatch(strNumber) &&
                  !objTwoDotPattern.IsMatch(strNumber) &&
                  !objTwoMinusPattern.IsMatch(strNumber) &&
                  objNumberPattern.IsMatch(strNumber);
}

b)
public   static   bool  IsNumeric( string  value)
{
         return Regex.IsMatch(value, @"^[+-]?/d*[.]?/d*$");
}
public   static   bool  IsInt( string  value)
{
         return Regex.IsMatch(value, @"^[+-]?/d*$");
}
public   static   bool  IsUnsign( string  value)
{
         return Regex.IsMatch(value, @"^/d*[.]?/d*$");
}


方案三：遍历
a)
public   bool  isnumeric( string  str)
{
    char[] ch=new char[str.Length];
    ch=str.ToCharArray();
    for(int i=0;i    {
        if(ch[i]<48 || ch[i]>57)
            return false;
    }
    return true;
}

b)
public   bool  IsInteger( string  strIn)  {
        bool bolResult=true;
        if(strIn=="") {
               bolResult=false;
        }
        else {
              foreach(char Char in strIn) {
                         if(char.IsNumber(Char))
                                continue;
                         else {
                                 bolResult=false;
                                 break;
                         }
              }
        }
        return bolResult;
}

c)
public   static   bool  isNumeric( string  inString)
{
        inString=inString.Trim();
        bool haveNumber=false;
        bool haveDot=false;
        for(int i=0;i        {
               if (Char.IsNumber(inString[i]))
                {
                        haveNumber=true;
                }
                else if(inString[i]=='.')
                {
                        if (haveDot)
                        {
                                return false;
                         }
                         else
                         {
                                haveDot=true;
                          }
                }
                else if(i==0)
                {
                          if(inString[i]!='+'&&inString[i]!='-')
                          {
                                  return false;
                          }
                }
                else
                {
                          return false;
                 }
                if(i>20)
                {
                          return false;
                 }
         }
         return haveNumber;
       }


 

方案四：改写vb的IsNumeric源代码(执行效率不高)

// 主调函数
public   static   bool  IsNumeric( object  Expression)
{
      bool flag1;
      IConvertible convertible1 = null;
      if (Expression is IConvertible)
      {
            convertible1 = (IConvertible) Expression;
      }
      if (convertible1 == null)
      {
            if (Expression is char[])
            {
                  Expression = new string((char[]) Expression);
            }
            else
            {
                  return false;
            }
      }
      TypeCode code1 = convertible1.GetTypeCode();
      if ((code1 != TypeCode.String) && (code1 != TypeCode.Char))
      {
            return Utils.IsNumericTypeCode(code1);
      }
      string text1 = convertible1.ToString(null);
      try
      {
            long num2;
            if (!StringType.IsHexOrOctValue(text1, ref num2))
            {
                  double num1;
                  return DoubleType.TryParse(text1, ref num1);
            }
            flag1 = true;
      }
      catch (Exception)
      {
            flag1 = false;
      }
      return flag1;
}

// 子函数
//  return Utils.IsNumericTypeCode(code1);
internal   static   bool  IsNumericTypeCode(TypeCode TypCode)
{
      switch (TypCode)
      {
            case TypeCode.Boolean:
            case TypeCode.Byte:
            case TypeCode.Int16:
            case TypeCode.Int32:
            case TypeCode.Int64:
            case TypeCode.Single:
            case TypeCode.Double:
            case TypeCode.Decimal:
            {
                  return true;
            }
            case TypeCode.Char:
            case TypeCode.SByte:
            case TypeCode.UInt16:
            case TypeCode.UInt32:
            case TypeCode.UInt64:
            {
                  break;
            }
      }
      return false;
}
 

// -----------------
// StringType.IsHexOrOctValue(text1, ref num2))
internal   static   bool  IsHexOrOctValue( string  Value,  ref   long  i64Value)
{
      int num1;
      int num2 = Value.Length;
      while (num1 < num2)
      {
            char ch1 = Value[num1];
            if (ch1 == '&')
            {
                  ch1 = char.ToLower(Value[num1 + 1], CultureInfo.InvariantCulture);
                  string text1 = StringType.ToHalfwidthNumbers(Value.Substring(num1 + 2));
                  if (ch1 == 'h')
                  {
                        i64Value = Convert.ToInt64(text1, 0x10);
                  }
                  else if (ch1 == 'o')
                  {
                        i64Value = Convert.ToInt64(text1, 8);
                  }
                  else
                  {
                        throw new FormatException();
                  }
                  return true;
            }
            if ((ch1 != ' ') && (ch1 != '/u3000'))
            {
                  return false;
            }
            num1++;
      }
      return false;
}
// ----------------------------------------------------
//  DoubleType.TryParse(text1, ref num1);
internal   static   bool  TryParse( string  Value,  ref   double  Result)
{
      bool flag1;
      CultureInfo info1 = Utils.GetCultureInfo();
      NumberFormatInfo info3 = info1.NumberFormat;
      NumberFormatInfo info2 = DecimalType.GetNormalizedNumberFormat(info3);
      Value = StringType.ToHalfwidthNumbers(Value, info1);
      if (info3 == info2)
      {
            return double.TryParse(Value, NumberStyles.Any, info2, out Result);
      }
      try
      {
            Result = double.Parse(Value, NumberStyles.Any, info2);
            flag1 = true;
      }
      catch (FormatException)
      {
            flag1 = double.TryParse(Value, NumberStyles.Any, info3, out Result);
      }
      catch (Exception)
      {
            flag1 = false;
      }
      return flag1;
}

方案五： 直接引用vb运行库(执行效率不高)

方法： 首先需要添加Visualbasic.runtime的引用
 代码中Using Microsoft.visualbasic;
 程序中用Information.isnumeric( " ddddd " );