Input
Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.
Output
For each problem instance, output consists of one line. This line should be one of the following three:
Sorted sequence determined after xxx relations: yyy...y.
Sorted sequence cannot be determined.
Inconsistency found after xxx relations.
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.
Sample Input
4 6
A<B
A<C
B<C
C<D
B<D
A<B
3 2
A<B
B<A
26 1
A<Z
0 0
Sample Output
Sorted sequence determined after 4 relations: ABCD.
Inconsistency found after 2 relations.
Sorted sequence cannot be determined.
思路:拓扑排序,判断是否出现环,或者能排出序列,当出现多于一个入度为0的点则为不确定。
#include<iostream> #include<cstring> #include<algorithm> #include<vector> #include<cstdio> using namespace std; const int mm=1100; char out[mm]; bool vis[77]; vector<int >mp[77]; int cu[mm],cun[mm],n,m,pos; bool yes; int topsort() { for(int i=0;i<30;i++) cu[i]=cun[i]; int top=-1,ttnum=0; for(int i=0;i<n;i++) if(cu[i]==0) cu[i]=top,top=i; if(cu[top]!=-1)yes=1;///只要入度为0的点多于1个那么就是不确定序列,但人需要判断是否有环 for(int i=0;i<n;i++) { if(top==-1)return 0; else { int num=top;top=cu[top]; pos+=sprintf(out+pos,"%c",char('A'+num)); for(int j=0;j<mp[num].size();j++) if(--cu[mp[num][j]]==0) cu[mp[num][j]]=top,top=mp[num][j]; if(top>=0&&cu[top]!=-1)yes=1; } }return 1; } int main() { while(cin>>n>>m) { if(n==0&&m==0)break; char sss,u,v; memset(cun,0,sizeof(cun)); memset(mp,0,sizeof(mp)); memset(vis,0,sizeof(vis)); int ans=0,z=0,pp=0; for(int i=0;i<m;i++) { cin>>u>>sss>>v; cun[v-'A']++;mp[u-'A'].push_back(v-'A'); if(!vis[v-'A'])vis[v-'A']=1,pp++; if(!vis[u-'A'])vis[u-'A']=1,pp++;///判断不同的字符数是否刚好为n个 if(ans==0) {pos=0;yes=0;///yes是真说明拓扑排序的序列仍是不确定,但需要看看是否有环,无环则continue; if(topsort()){if(yes)continue;if(pp==n)ans=1,z=i+1;} else ans=-1,z=i+1; } } if(ans==1)cout<<"Sorted sequence determined after "<<z<<" relations: "<<out<<".\n"; else if(ans==-1)cout<<"Inconsistency found after "<<z<<" relations.\n"; else cout<<"Sorted sequence cannot be determined.\n"; } }