hdu 1198 深搜

//直接打表了,connect[x][y][z]表示x的z方向上的y,他们之间是否连通,x,y的取值为0-10,
//分别代表那11中类型,z表示方向0表示右方,1表示上方,2表示左方,3表示下方
//7236312	2012-11-23 22:37:23	Accepted	1198	15MS	1552K	2455 B	G++	chen 
#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int N,M;
int connect[11][11][4]={
    {{0,0,0,0},{0,0,1,0},{0,1,0,0},{0,1,1,0},{0,1,0,0},{0,0,1,0},{0,0,1,0},{0,1,0,0},{0,1,1,0},{0,1,1,0},{0,1,1,0}},
    {{1,0,0,0},{0,0,0,0},{1,1,0,0},{0,1,0,0},{0,1,0,0},{1,0,0,0},{1,0,0,0},{1,1,0,0},{1,1,0,0},{0,1,0,0},{1,1,0,0}},
    {{0,0,0,1},{0,0,1,1},{0,0,0,0},{0,0,1,0},{0,0,0,1},{0,0,1,0},{0,0,1,1},{0,0,0,1},{0,0,1,0},{0,0,1,1},{0,0,1,1}},
    {{1,0,0,1},{0,0,0,1},{1,0,0,0},{0,0,0,0},{0,0,0,1},{1,0,0,0},{1,0,0,1},{1,0,0,1},{1,0,0,0},{0,0,0,1},{1,0,0,1}},
    {{0,0,0,1},{0,0,0,1},{0,1,0,0},{0,1,0,0},{0,1,0,1},{0,0,0,0},{0,0,0,1},{0,1,0,1},{0,1,0,0},{0,1,0,1},{0,1,0,1}},
    {{1,0,0,0},{0,0,1,0},{1,0,0,0},{0,0,1,0},{0,0,0,0},{1,0,1,0},{1,0,1,0},{1,0,0,0},{1,0,1,0},{0,0,1,0},{1,0,1,0}},
    {{1,0,0,0},{0,0,1,0},{1,1,0,0},{0,1,1,0},{0,1,0,0},{1,0,1,0},{1,0,1,0},{1,1,0,0},{1,1,1,0},{0,1,1,0},{1,1,1,0}},
    {{0,0,0,1},{0,0,1,1},{0,1,0,0},{0,1,1,0},{0,1,0,1},{0,0,1,0},{0,0,1,1},{0,1,0,1},{0,1,1,0},{0,1,1,1},{0,1,1,1}},
    {{1,0,0,1},{0,0,1,1},{1,0,0,0},{0,0,1,0},{0,0,0,1},{1,0,1,0},{1,0,1,1},{1,0,0,1},{1,0,1,0},{0,0,1,1},{1,0,1,1}},
    {{1,0,0,1},{0,0,0,1},{1,1,0,0},{0,1,0,0},{0,1,0,1},{1,0,0,0},{1,0,0,1},{1,1,0,1},{1,1,0,0},{0,1,0,1},{1,1,0,1}},    
    {{1,0,0,1},{0,0,1,1},{1,1,0,0},{0,1,1,0},{0,1,0,1},{1,0,1,0},{1,0,1,1},{1,1,0,1},{1,1,1,0},{0,1,1,1},{1,1,1,1}}
};
int dir[4][2]={{0,1},{-1,0},{0,-1},{1,0}};
int mat[550][550];
int visited[550][550];


void dfs(int a,int b){
        visited[a][b]=1;
        for(int i=0;i<4;i++){
            int m=a+dir[i][0];
            int n=b+dir[i][1];
            if(m<M&&m>=0&&n<N&&n>=0&&visited[m][n]==0){
                if(connect[mat[a][b]][mat[m][n]][i]==1)
                    dfs(m,n);
            }
        }
}

int main(){
    while(scanf("%d%d",&M,&N)!=EOF){
        if(M<0||N<0)
            break;
        memset(visited,0,sizeof(visited));
        getchar();
        char a;
        for(int i=0;i<M;i++){
            for(int j=0;j<N;j++){
                scanf("%c",&a);
                mat[i][j]=a-'A';
            }
            getchar();
        }
        int res=0;
        for(int j=0;j<M;j++){
            for(int k=0;k<N;k++){
                if(visited[j][k]==0){
                    dfs(j,k);
                    res++;
                }
            }
        }
        printf("%d\n",res);
    }
    return 0;
}

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