南邮 OJ 1682 非递减字符串问题
非递减字符串问题
时间限制(普通/Java) :
1000 MS/ 3000 MS 运行内存限制 : 81920 KByte
总提交 : 179 测试通过 : 29
总提交 : 179 测试通过 : 29
比赛描述
在非递减字符串中，
从左到右的字符依次按
ASC
码非递减排列，
例如
abcd
，
其他
4
个字符组成的非递减字符串还有
aaaa
，
aabb
，
aaab
，
abcc
等。现在假设字
符串由
a
、
b
、
c
、
d
、
e
、
f
、
g
、
h
、
i
、
j
等
10
个字符组成。请你编程确定特定长
度的非递减字符串的数目。
在非递减字符串中，
从左到右的字符依次按
ASC
码非递减排列，
例如
abcd
，
其他
4
个字符组成的非递减字符串还有
aaaa
，
aabb
，
aaab
，
abcc
等。现在假设字
符串由
a
、
b
、
c
、
d
、
e
、
f
、
g
、
h
、
i
、
j
等
10
个字符组成。请你编程确定特定长
度的非递减字符串的数目。
在非递减字符串中，从左到右的字符依次按ASC码非递减排列，例如abcd，其他4个字符组成的非递减字符串还有aaaa，aabb，aaab，abcc等。现在假设字符串由a、b、c、d、e、f、g、h、i、j等10个字符组成。请你编程确定特定长度的非递减字符串的数目。
输入
输入包括多个测试用例，首先给出测试用例数P（1≤P≤1000），接着给出P个测试用例。每一个测试用例包括一行，给出以空格分隔的两个整数，第1个整数表示测试用例序号，第二整数表示字符串的长度N（1≤N≤64）。
输出
输出包括多行，对于每个测试用例输出一行，输出以空格分隔的两个整数，第1个整数为测试用例序号，第二整数给出长度为N的非递减字符串数目。
样例输入
2
1 4
2 3
样例输出
1 715
2 220
题目来源
NUPT
#include<iostream>
#include<string>
using namespace std;
int main(){
string s[100]={"10","55","220","715","2002","5005","11440","24310","48620","92378","167960","293930","497420","817190","1307504","2042975","3124550","4686825","6906900","10015005","14307150","20160075","28048800","38567100","52451256","70607460","94143280","124403620","163011640","211915132","273438880","350343565","445891810","563921995","708930508","886163135","1101716330","1362649145","1677106640","2054455634","2505433700","3042312350","3679075400","4431613550","5317936260","6358402050","7575968400","8996462475","10648873950","12565671261","14783142660","17341763505","20286591270","23667689815","27540584512","31966749880","37014131440","42757703560","49280065120","56672074888","65033528560","74473879480","85113005120","97082021465","110524147514","125595622175","142466675900","161322559475","182364632450","205811513765","231900297200","260887834350","293052087900","328693558050","368136785016","411731930610","459856441980","512916800670","571350360240","635627275767","706252528630","783768050065","868754947060","961835834245","1063677275518","1174992339235","1296543270880","1429144287220","1573664496040","1731030945644","1902231808400","2088319702700","2290415157800","2509710226100","2747472247520","3005047770725","3283866636050","3585446225075","3911395881900","4263421511271"};
int P, i, N;
cin>>P;
while(P--){
cin>>i>>N;
cout<<i<<' '<<s[N-1]<<endl;
}
}
/*
#include<iostream>
#include<fstream>
using namespace std;
int main(){
long long a[10]={1,1,1,1,1,1,1,1,1,1}, N=100, i, j;
ofstream f("output.txt");
//n=1,线段长度；n=2,三角形面积；n=3三棱锥体积，n>3多维立体体积，可画图帮组理解
for(i=1; i<=N; i++){
for(j=1; j<10; j++){
a[j] += a[j-1];
}
f<<"\""<<a[9]<<"\",";
}
}*/