用JAXB从对象生成XML

 import java.io.FileOutputStream;

 import javax.xml.bind.JAXBContext;
 import javax.xml.bind.Marshaller;
 import javax.xml.bind.annotation.XmlRootElement;

 public class JavaToXMLDemo {
   public static void main(String[] args) throws Exception {
     JAXBContext context = JAXBContext.newInstance(Employee.class);

     Marshaller m = context.createMarshaller();
     m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

     Employee object = new Employee();
     object.setCode("CA");
     object.setName("Cath");
     object.setSalary(300);

     m.marshal(object, System.out);

   }
 }

 

 

 @XmlRootElement
 class Employee {
   private String code;

   private String name;

   private int salary;

   public String getCode() {
     return code;
   }

   public void setCode(String code) {
     this.code = code;
   }

   public String getName() {
     return name;
   }

   public void setName(String name) {
     this.name = name;
   }

   public int getSalary() {
     return salary;
   }

   public void setSalary(int population) {
     this.salary = population;
   }
 }

 

 

运行结果:

 <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
 <employee>
     <code>CA</code>
     <name>Cath</name>
     <salary>300</salary>
 </employee>