The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of points on a plane.
Each of the next n lines contains two real coordinates xi and yi of the point, specified with exactly 2 fractional digits. All coordinates are between - 1000 and 1000, inclusive.
Output a single real number θ — the answer to the problem statement. The absolute or relative error of your answer should be at most10 - 2.
8 -2.14 2.06 -1.14 2.04 -2.16 1.46 -2.14 0.70 -1.42 0.40 -0.94 -0.48 -1.42 -1.28 -2.16 -1.62
5.410
5 2.26 1.44 2.28 0.64 2.30 -0.30 1.58 0.66 3.24 0.66
5.620
8 6.98 2.06 6.40 1.12 5.98 0.24 5.54 -0.60 7.16 0.30 7.82 1.24 8.34 0.24 8.74 -0.76
5.480
5 10.44 2.06 10.90 0.80 11.48 -0.48 12.06 0.76 12.54 2.06
6.040
8 16.94 2.42 15.72 2.38 14.82 1.58 14.88 0.50 15.76 -0.16 16.86 -0.20 17.00 0.88 16.40 0.92
6.040
7 20.62 3.00 21.06 2.28 21.56 1.36 21.66 0.56 21.64 -0.52 22.14 2.32 22.62 3.04
6.720
#include<stdio.h> #include<iostream> #include<string.h> #include<string> #include<ctype.h> #include<math.h> #include<set> #include<map> #include<vector> #include<queue> #include<bitset> #include<algorithm> #include<time.h> using namespace std; void fre() { freopen("c://test//input.in", "r", stdin); freopen("c://test//output.out", "w", stdout); } #define MS(x,y) memset(x,y,sizeof(x)) #define MC(x,y) memcpy(x,y,sizeof(x)) #define MP(x,y) make_pair(x,y) #define ls o<<1 #define rs o<<1|1 typedef long long LL; typedef unsigned long long UL; typedef unsigned int UI; template <class T1, class T2>inline void gmax(T1 &a, T2 b) { if (b>a)a = b; } template <class T1, class T2>inline void gmin(T1 &a, T2 b) { if (b<a)a = b; } const int N = 0, M = 0, Z = 1e9 + 7, ms63 = 0x3f3f3f3f; int n; int main() { while (~scanf("%d", &n)) { double sum = 0, x; for (int i = 1; i <= n; ++i) { scanf("%*lf%lf", &x); sum += x; } printf("%.3f\n", 5 + sum / n); } return 0; } /* 【trick&&吐槽】 能否想到只与第二维相关呢? 毕竟一些信息是干扰信息。常有的。 */