发现了一个Nginx的LUA脚本:lua-resty-rabbitmqstomp,可以让Nginx通过LUA脚本访问RabbitMQ消息队列,这个脚本是通过stomp协议连接RabbitMQ的stomp适配器,来pub/sub消息的
关于RabbitMQ-STOMP安装使用相关内容可以参见:RabbitMQ STOMP Adapter
关于Nginx-LUA模块安装使用参见:LAMP架构演进到LAMPGC,再演进到LNMLGC
关于STOMP协议相关资料参见这里:
STOMP官方英文协议1.1版
STOMP协议学习与实战-1.1版
STOMP官方英文协议1.2版
STOMP协议说明书-1.2版
nginx配置:
location /rabbitmq { lua_code_cache off; content_by_lua_file conf/rabbitmq.lua; }
rabbitmq.lua源码如下,该脚本简单的实现pub一个消息然后再sub该消息,set_timeout(60000)表示sub消息如果没有消息时等待60S超时
local strlen = string.len local json = require "json" local rabbitmq = require "rabbitmqstomp" local mq, err = rabbitmq:new() if not mq then return end mq:set_timeout(60000) local ok, err = mq:connect { host = "127.0.0.1", port = 61613, username = "guest", password = "guest", vhost = "/" } if not ok then return end ngx.log(ngx.INFO, "Connect: " .. "OK") local msg = {key="value1", key2="value2"} local headers = {} headers["destination"] = "/queue/my_queue" headers["receipt"] = "msg#1" headers["app-id"] = "luaresty" headers["persistent"] = "true" headers["content-type"] = "application/json" local ok, err = mq:send(json.encode(msg), headers) if not ok then return end ngx.log(ngx.INFO, "Published: " .. json.encode(msg)) local headers = {} headers["destination"] = "/queue/my_queue" headers["persistent"] = "true" headers["id"] = "123" local ok, err = mq:subscribe(headers) if not ok then return end local data, err = mq:receive() if not data then return end ngx.log(ngx.INFO, "Consumed: " .. data) ngx.header.content_type = "text/plain"; ngx.say(data); local headers = {} headers["persistent"] = "true" headers["id"] = "123" local ok, err = mq:unsubscribe(headers) local ok, err = mq:set_keepalive(10000, 10000) if not ok then return end