/*What Are You Talking About Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 102400/204800 K (Java/Others) Total Submission(s): 15270 Accepted Submission(s): 4903 Problem Description Ignatius is so lucky that he met a Martian yesterday. But he didn't know the language the Martians use. The Martian gives him a history book of Mars and a dictionary when it leaves. Now Ignatius want to translate the history book into English. Can you help him? Input The problem has only one test case, the test case consists of two parts, the dictionary part and the book part. The dictionary part starts with a single line contains a string "START", this string should be ignored, then some lines follow, each line contains two strings, the first one is a word in English, the second one is the corresponding word in Martian's language. A line with a single string "END" indicates the end of the directory part, and this string should be ignored. The book part starts with a single line contains a string "START", this string should be ignored, then an article written in Martian's language. You should translate the article into English with the dictionary. If you find the word in the dictionary you should translate it and write the new word into your translation, if you can't find the word in the dictionary you do not have to translate it, and just copy the old word to your translation. Space(' '), tab('\t'), enter('\n') and all the punctuation should not be translated. A line with a single string "END" indicates the end of the book part, and that's also the end of the input. All the words are in the lowercase, and each word will contain at most 10 characters, and each line will contain at most 3000 characters. Output In this problem, you have to output the translation of the history book. Sample Input START from fiwo hello difh mars riwosf earth fnnvk like fiiwj END START difh, i'm fiwo riwosf. i fiiwj fnnvk! END Sample Output hello, i'm from mars. i like earth! Hint Huge input, scanf is recommended. Author Ignatius.L Recommend We have carefully selected several similar problems for you: 1800 1671 1247 1298 1016 */ #include<stdio.h> #include<string.h> #include<stdlib.h> struct Tree { char s[11]; bool ok; Tree * next[26]; }root; char str[3010]; void build(char *s1, char *s2) { int i, j, k, id, l; Tree *p = &root, *q; l = strlen(s2); for(i = 0; i < l; ++i)//put in { id = s2[i] - 97; if(p->next[id] == NULL) { q = (Tree *) malloc(sizeof(root)); for(j = 0; j < 26; ++j) q->next[j] = NULL; q->ok = false; p->next[id] = q; p = q; } else p = p->next[id]; } l = strlen(s1); for(i = 0; i < l; ++i) p->s[i] = s1[i]; p->s[i] = '\0'; p->ok = true; } void find(char *s1) { int i, l, id; l = strlen(s1); Tree *p = &root; for(i = 0; i < l; ++i) { id = s1[i] - 97; if(p->next[id] == NULL) break; else p = p->next[id]; } if(i == l && p->ok) { int temp = strlen(p->s); for(i = 0; i < temp; ++i) printf("%c", p->s[i]); } else { for(i = 0; i < l; ++i) printf("%c", s1[i]); } } int main() { int i, j, k; char s1[11], s2[11]; for(i = 0; i < 26; ++i) root.next[i] = NULL; while(scanf("%s", s1) != EOF) { if(strcmp(s1, "START") == 0) continue; if(strcmp(s1, "END") == 0) break; scanf("%s", s2); build(s1, s2); } getchar(); while(gets(str) != NULL) { if(strcmp(str, "START") == 0) continue; if(strcmp(str, "END") == 0) break; k = strlen(str); s2[0] = '\0'; for(i = 0;i < k; ++i) { if(str[i] >= 97 && str[i] <= 122) { for(j = i; j < k; ++j) { if(str[j] >= 97 && str[j] <= 122) { s2[j-i] = str[j]; } else { s2[j-i] = '\0'; i = j; break; } } if(j == k) { s2[j-i] = '\0'; i = j; } find(s2); if(i != k) printf("%c",str[i]);//结束处的字符 } else printf("%c", str[i]); } printf("\n"); } return 0; }
题意:给出一部分字典,再给出一段文章,分别都以“START”开始“END”结束,要求将文章中的单词翻译成字典中的单词,若是找不到则不翻译,对于空白字符和标点符号原样输出,求翻译后的文章。
思路:由于这题数据非常大,所以需要用字典树来保存字典,并且在翻译时查找单词也更加快。对于文章中的单词必须是连续的小写字母,所以可以根据这个来划分单词,然后查找输出。