嗯,好久没写hash了。
先处理出s3在s1和s2的位置,然后二分答案,看有没有s1和s2有没有公共子串不包含就可以了。
#include<cstdio> #include<cstring> #include<cstdlib> #include<cmath> #include<iostream> #include<algorithm> #include<vector> #define maxn 50010 #define mod 10007 using namespace std; vector<int> v[mod]; char s1[maxn],s2[maxn],s[maxn]; int hash11[maxn],hash21[maxn]; int p1[maxn]; unsigned long long p2[maxn],hash12[maxn],hash22[maxn]; int n,m; unsigned long long Hash; bool vis1[maxn],vis2[maxn]; int next1[maxn],next2[maxn]; int hash,len1,len2,len; int calc11(int l,int r) { l++;r++; return (hash11[r]-hash11[l-1]*p1[r-l+1]%mod+mod)%mod; } int calc21(int l,int r) { l++;r++; return (hash21[r]-hash21[l-1]*p1[r-l+1]%mod+mod)%mod; } unsigned long long calc12(int l,int r) { l++;r++; return hash12[r]-hash12[l-1]*p2[r-l+1]; } unsigned long long calc22(int l,int r) { l++;r++; return hash22[r]-hash22[l-1]*p2[r-l+1]; } bool query(int l,int r) { int x=calc21(l,r),y=calc22(l,r); for (int i=0;i<v[x].size();i++) if (v[x][i]==y) return 1; return 0; } bool check(int x) { if (x==0) return 0; for (int i=0;i<mod;i++) v[i].clear(); for (int i=0;i+x-1<len1;i++) if (next1[i]==len1 || i+x-1<next1[i]+len-1) v[calc11(i,i+x-1)].push_back(calc12(i,i+x-1)); for (int i=0;i+x-1<len2;i++) if (next2[i]==len2 || i+x-1<next2[i]+len-1) if (query(i,i+x-1)) return 1; return 0; } int main() { scanf("%s%s%s",s1,s2,s); len=strlen(s);len1=strlen(s1);len2=strlen(s2); for (int i=1;i<=len1;i++) hash11[i]=(hash11[i-1]*233+s1[i-1]-'a')%mod; for (int i=1;i<=len1;i++) hash12[i]=hash12[i-1]*2333+s1[i-1]-'a'; for (int i=1;i<=len2;i++) hash21[i]=(hash21[i-1]*233+s2[i-1]-'a')%mod; for (int i=1;i<=len2;i++) hash22[i]=hash22[i-1]*2333+s2[i-1]-'a'; for (int i=1;i<=len;i++) hash=(hash*233+s[i-1]-'a')%mod,Hash=Hash*2333+s[i-1]-'a'; p1[0]=1;p2[0]=1; for (int i=1;i<=max(len,max(len1,len2));i++) p1[i]=p1[i-1]*233%mod,p2[i]=p2[i-1]*2333; for (int i=0;i+len-1<len1;i++) if (calc11(i,i+len-1)==hash && calc12(i,i+len-1)==Hash) vis1[i]=1; for (int i=0;i+len-1<len2;i++) if (calc21(i,i+len-1)==hash && calc22(i,i+len-1)==Hash) vis2[i]=1; next1[len1]=len1;for (int i=len1-1;i>=0;i--) if (vis1[i]) next1[i]=i; else next1[i]=next1[i+1]; next2[len2]=len2;for (int i=len2-1;i>=0;i--) if (vis2[i]) next2[i]=i; else next2[i]=next2[i+1]; int l=0,r=min(len1,len2),ans; while (l<=r) { int mid=(l+r)/2; if (check(mid)) ans=mid,l=mid+1; else r=mid-1; } printf("%d\n",ans); return 0; }