ACM-The Famous Clock

描述

Mr. B, Mr. G and Mr. M are now in Warsaw, Poland, for the 2012’s ACM-ICPC World Finals Contest. They’ve decided to take a 5 hours training every day before the contest. Also, they plan to start training at 10:00 each day since the World Final Contest will do so. The scenery in Warsaw is so attractive that Mr. B would always like to take a walk outside for a while after breakfast. However, Mr. B have to go back before training starts, otherwise his teammates will be annoyed. Here is a problem: Mr. B does not have a watch. In order to know the exact time, he has bought a new watch in Warsaw, but all the numbers on that watch are represented in Roman Numerals. Mr. B cannot understand such kind of numbers. Can you translate for him?

输入
Each test case contains a single line indicating a Roman Numerals that to be translated. All the numbers can be found on clocks. That is, each number in the input represents an integer between 1 and 12. Roman Numerals are expressed by strings consisting of uppercase ‘I’, ‘V’ and ‘X’. See the sample input for further information.
输出
For each test case, display a single line containing a decimal number corresponding to the given Roman Numerals.
样例输入
I
II
III
IV
V
VI
VII
VIII
IX
X
XI
XII
样例输出
Case 1: 1
Case 2: 2
Case 3: 3
Case 4: 4
Case 5: 5
Case 6: 6
Case 7: 7
Case 8: 8
Case 9: 9
Case 10: 10
Case 11: 11
Case 12: 12


代码:

01. #include <stdio.h>
02. #include <string.h>
03. int main()
04. {
05. int n=0;
06. char a[5];
07. while(scanf("%s",a)!=EOF)
08. {
09. n++;
10. printf("Case %d: ",n);
11. if(strcmp(a,"I")==0)
12. printf("1\n");
13. else if(strcmp(a,"II")==0)
14. printf("2\n");
15. else if(strcmp(a,"III")==0)
16. printf("3\n");
17. else if(strcmp(a,"IV")==0)
18. printf("4\n");
19. else if(strcmp(a,"V")==0)
20. printf("5\n");
21. else if(strcmp(a,"VI")==0)
22. printf("6\n");
23. else if(strcmp(a,"VII")==0)
24. printf("7\n");
25. else if(strcmp(a,"VIII")==0)
26. printf("8\n");
27. else if(strcmp(a,"IX")==0)
28. printf("9\n");
29. else if(strcmp(a,"X")==0)
30. printf("10\n");
31. else if(strcmp(a,"XI")==0)
32. printf("11\n");
33. else if(strcmp(a,"XII")==0)
34. printf("12\n");
35. }
36. return 0;
37. }


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