hdu4267区间统计

题意:给一些数,有两种操作,一种是在[a,b] 区间内,对(i - a)% k == 0 的加value,另一种操作是询问某个位置的值。

import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.io.StreamTokenizer;
import java.math.BigInteger;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collection;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.HashSet;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.NavigableSet;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Scanner;
import java.util.Set;
import java.util.SortedSet;
import java.util.Stack;
import java.util.StringTokenizer;
import java.util.TreeSet;

public class Main {

    public static void main(String[] args) throws IOException{
           StreamTokenizer cin = new StreamTokenizer(new BufferedInputStream(System.in)); 
           InputReader in = new InputReader(System.in)  ;
           PrintWriter out = new PrintWriter(System.out) ;


           while(cin.nextToken() != cin.TT_EOF){
                new Task().solve(cin, out); 
           }

           out.flush() ; 
    }


}


class  BIT{
       int n ;
       int[] cnt ;

       BIT(int n){
           this.n = n ;   
           cnt = new int[n+1] ;
       }

       int  lowbit(int x){
            return x & (-x) ;
       }

       void add(int i , int val){
            for( ; i <= n ; i += lowbit(i)) cnt[i] += val ;
       }

       int sum(int i){
           int s = 0 ;
           for( ; i > 0 ; i -= lowbit(i)) s += cnt[i] ;
           return s ;
       }
}

class  Task{

       static int N = 50008 ;
       static int[] num = new int[N] ;

       public void solve(StreamTokenizer cin , PrintWriter out) throws IOException{
              int n = (int)cin.nval;
              for(int i = 1 ; i <= n ; i++){
                    cin.nextToken() ; num[i] = (int)cin.nval ;
              }

              BIT[][] bit = new BIT[11][10] ;

              for(int k = 1 ; k <= 10 ; k++){
                    for(int j = 0 ; j < k ; j++) bit[k][j] = new BIT(n) ;
              }

              cin.nextToken() ; int q = (int)cin.nval  ;
              while(q-- > 0){
                   cin.nextToken() ; int kind = (int)cin.nval ;
                   if(kind == 1){
                         cin.nextToken() ; int a = (int)cin.nval ;
                         cin.nextToken() ; int b = (int)cin.nval ;
                         cin.nextToken() ; int k = (int)cin.nval ;
                         cin.nextToken() ; int c = (int)cin.nval ;
                         bit[k][a%k].add(a , c) ;
                         bit[k][a%k].add(b+1, -c) ;
                   }
                   else{
                        cin.nextToken() ; int i = (int)cin.nval ; 
                        int s = num[i] ;
                        for(int k = 1 ; k <= 10 ; k++)
                            s += bit[k][i%k].sum(i)  ;
                        out.println(s);
                   }
              }
       }

}

class   InputReader{
        public BufferedReader  reader;
        public StringTokenizer  tokenizer;

        public InputReader(InputStream stream){
                    reader = new BufferedReader(new InputStreamReader(stream), 32768) ;
                    tokenizer = null ;
        }

        public String next(){
                    while(tokenizer == null || ! tokenizer.hasMoreTokens()){
                        try{
                                tokenizer = new StringTokenizer(reader.readLine());
                        }catch (IOException e) {
                                throw new RuntimeException(e);
                        }
                    }
                    return tokenizer.nextToken();  
        }

        public int  nextInt(){
                    return Integer.parseInt(next());
        }

        public long nextLong(){
                    return Long.parseLong(next());
        }

        public double nextDouble(){
                    return  Double.parseDouble(next());
        }

}

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