LeetCode 209. Minimum Size Subarray Sum

Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.

For example, given the array [2,3,1,2,4,3] and s = 7,
the subarray [4,3] has the minimal length under the problem constraint.


Classical two pointers problem.

#include <vector>
#include <iostream>
#include <limits>
using namespace std;

int minSubArrayLen(int target, vector<int>& nums) {
    int minLen = nums.size() + 1;  // basically any number wont reach is fine. Usually use INT_MAX
    int sum = 0;
    int i = 0, j = 0; // two pointers. One keep tracking the low scope, one tracking the high scope.
    while(i < nums.size()) {
        sum = sum + nums[i];
        while(sum >= target) {
            minLen = min(minLen, i - j + 1);
            sum = sum - nums[j];
            j++;
        }
        i++;
    }
    return minLen == nums.size() + 1 ? 0 : minLen;
}

int main(void) {
    vector<int> nums {7};
    int len = minSubArrayLen(7, nums);
    cout << len << endl;
}



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