leetcode278---First Bad Version

问题描述：

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

有n个版本的产品[1, 2, ..., n]，如果从i开始是次品，则后边的全是次品，找到第一个次品。

问题求解：

// Forward declaration of isBadVersion API.
bool isBadVersion(int version);

class Solution {
public:
    int firstBadVersion(int n) {
        if(n==1) return 1;
        int low=1, high=n;
        while(low < high)
        {
            int mid=low + (high-low)/2;//avoid overflow
            if(isBadVersion(mid))
            {
                high=mid;
            }
            else
            {
                low=mid+1;
            }
        }
        return low;//！！！
    }
};