打印最新同一时间的日志信息

有如下的日志/var/log/message.log，要求把最新时间的日志打印出来。

Time,Entity,Severity,Node,Desc
00:00:01 04/25/2016 ,Node,Info,0,IMG Control Link is Up
00:00:01 04/25/2016 ,Node,Info,0,HostAlarm(Software License Verified)
00:00:01 04/25/2016 ,Node,Info,0,HostAlarm(Software Versions Matched)
11:16:45 04/25/2016 ,Node,Info,0,IMG Control Link is Up
11:16:45 04/25/2016 ,Node,Info,0,HostAlarm(Software License Verified)
11:16:45 04/25/2016 ,Node,Info,0,HostAlarm(Software Versions Matched)
12:11:46 04/25/2016 ,Node,Info,0,IMG Control Link is Up
12:11:46 04/25/2016 ,Node,Info,0,HostAlarm(Software License Verified)
12:11:46 04/25/2016 ,Node,Info,0,HostAlarm(Software Versions Matched)

比如，这里最新时间的日志应该是：

12:11:46 04/25/2016 ,Node,Info,0,IMG Control Link is Up
12:11:46 04/25/2016 ,Node,Info,0,HostAlarm(Software License Verified)
12:11:46 04/25/2016 ,Node,Info,0,HostAlarm(Software Versions Matched)

将这一段打印出来，命令精简越好。

grep "`grep [^0-9] /var/log/message.log |cut -d , -f 1|uniq|tail -1`" /var/log/message.log

grep "`grep [^0-9] /var/log/message.log |awk -F ',' '{print $1}'|uniq |tail -1`" /var/log/message.log

grep "`tail -1 /var/log/message.log |awk -F ',' '{print $1}'`" /var/log/message.log

我感觉写的好臃肿，但是目前是实现了。在改进吧。