HDU 4975 (杭电多校 #10 1005题)A simple Gaussian elimination problem.(网络流之最大流)

题目地址:HDU 4975

对这题简直无语。。。本来以为这题要用什么更先进的方法,结果还是老方法,这么卡时间真的好吗。。。。比赛的时候用了判环的方法,一直TLE。。后来换了矩阵DP的方式,加了加剪枝就过了。。无语了。。

代码如下:

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <stdlib.h>
#include <math.h>
#include <ctype.h>
#include <queue>
#include <map>
#include <set>
#include <algorithm>

using namespace std;
const int INF=0x3f3f3f3f;
int head[1010], source, sink, nv, cnt, vis[610][600], mp[600][600];
int cur[1010], num[1010], d[1010], pre[1010];
int a[600], b[600];
struct node
{
    int u, v, cap, next;
} edge[1000000];
void add(int u, int v, int cap)
{
    edge[cnt].v=v;
    edge[cnt].cap=cap;
    edge[cnt].next=head[u];
    head[u]=cnt++;

    edge[cnt].v=u;
    edge[cnt].cap=0;
    edge[cnt].next=head[v];
    head[v]=cnt++;
}
void bfs()
{
    memset(num,0,sizeof(num));
    memset(d,-1,sizeof(d));
    queue<int>q;
    q.push(sink);
    d[sink]=0;
    num[0]=1;
    while(!q.empty())
    {
        int u=q.front();
        q.pop();
        for(int i=head[u]; i!=-1; i=edge[i].next)
        {
            int v=edge[i].v;
            if(d[v]==-1)
            {
                d[v]=d[u]+1;
                num[d[v]]++;
                q.push(v);
            }
        }
    }
}
int isap()
{
    memcpy(cur,head,sizeof(cur));
    int flow=0, u=pre[source]=source, i;
    bfs();
    while(d[source]<nv)
    {
        if(u==sink)
        {
            int f=INF, pos;
            for(i=source; i!=sink; i=edge[cur[i]].v)
            {
                if(f>edge[cur[i]].cap)
                {
                    f=edge[cur[i]].cap;
                    pos=i;
                }
            }
            for(i=source; i!=sink; i=edge[cur[i]].v)
            {
                edge[cur[i]].cap-=f;
                edge[cur[i]^1].cap+=f;
            }
            flow+=f;
            u=pos;
        }
        for(i=cur[u]; i!=-1; i=edge[i].next)
        {
            if(d[edge[i].v]+1==d[u]&&edge[i].cap)
                break;
        }
        if(i!=-1)
        {
            cur[u]=i;
            pre[edge[i].v]=u;
            u=edge[i].v;
        }
        else
        {
            if(--num[d[u]]==0) break;
            int mind=nv;
            for(i=head[u]; i!=-1; i=edge[i].next)
            {
                if(mind>d[edge[i].v]&&edge[i].cap)
                {
                    mind=d[edge[i].v];
                    cur[u]=i;
                }
            }
            d[u]=mind+1;
            num[d[u]]++;
            u=pre[u];
        }
    }
    return flow;
}
bool panduan(int n,int m)
{
    memset(vis,0,sizeof(vis));
    int i, j, k;
    for(i=1;i<=n;i++)
    {
        if(a[i]==0||a[i]==9*m) continue ;
        for(j=1;j<=m;j++)
        {
            if(b[j]==0||b[j]==9*n) continue ;
            for(k=j+1;k<=m;k++)
            {
                int t1=0, t2=0;
                if(mp[i][j]&&mp[i][k]!=9)
                {
                    if(vis[j][k]) return 1;
                    t1=1;
                }
                if(mp[i][k]&&mp[i][j]!=9)
                {
                    if(vis[k][j]) return 1;
                    t2=1;
                }
                if(t1) vis[k][j]=1;
                if(t2) vis[j][k]=1;
            }
        }
    }
    return 0;
}
int read()
{
    int x = 0;
    char ch = ' ';
    while(ch < '0' || ch > '9') ch = getchar();
    while(ch >= '0' && ch <= '9') x = x * 10 + ch - '0', ch = getchar();
    return x;
}
int main()
{
    int t, i, j, n, m, sum1, sum2, num=0;
    t=read();
    while(t--)
    {
        num++;
        n=read();
        m=read();
        sum1=sum2=0;
        memset(head,-1,sizeof(head));
        cnt=0;
        source=0;
        sink=n+m+1;
        nv=sink+1;
        for(i=1; i<=n; i++)
        {
            a[i]=read();
            sum1+=a[i];
        }
        for(i=1; i<=m; i++)
        {
            b[i]=read();
            sum2+=b[i];
        }
        printf("Case #%d: ",num);
        if(sum1!=sum2)
        {
            puts("So naive!");
            continue ;
        }
        for(i=1; i<=n; i++)
        {
            add(source,i,a[i]);
            for(j=1; j<=m; j++)
            {
                add(i,j+n,9);
            }
        }
        for(i=1; i<=m; i++)
        {
            add(i+n,sink,b[i]);
        }
        int ans=isap();
        if(ans!=sum1)
        {
            puts("So naive!");
            continue ;
        }
        for(i=1;i<=n;i++)
        {
            for(j=head[i];j!=-1;j=edge[j].next)
            {
                int v=edge[j].v;
                if(v>n&&v<=n+m)
                    mp[i][v-n]=9-edge[j].cap;
            }
        }
        if(panduan(n,m))
        {
            puts("So young!");
        }
        else
            puts("So simple!");
    }
    return 0;
}


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