Problem
Given a list of space separated words, reverse the order of the words. Each line of text contains L
letters and W
words. A line will only consist of letters and space characters. There will be exactly one space character between each pair of consecutive words.
Input
The first line of input gives the number of cases, N.
N test cases follow. For each test case there will a line of letters and space characters indicating a list of space separated words. Spaces will not appear at the start or end of a line.
Output
For each test case, output one line containing "Case #x: " followed by the list of words in reverse order.
Limits
Small dataset
N = 5
1 ≤ L ≤ 25
Large dataset
N = 100
1 ≤ L ≤ 1000
Sample
Input |
Output |
3 |
Case #1: test a is this |
我的代码:
#include <cstdio> #include <iostream> #include <string> using namespace std; //#define SMALL #define LARGE void main() { #ifdef SMALL freopen("B-small-practice.in","r",stdin); freopen("B-small-practice.out","w",stdout); #endif #ifdef LARGE freopen("B-large-practice.in","r",stdin); freopen("B-large-practice.out","w",stdout); #endif string re_Line[1000]; int N; cin>>N; char t; getchar(t);//No.1 for(int i=0;i<N;i++) { string Line; char temp[1000]; getline(cin,Line);//No.2 int k=0,start=0; for(int j=0;j<Line.size();j++) { temp[j-start]=Line[j]; if(Line[j]==' ') { temp[j-start]='\0'; start=j+1; re_Line[k] = temp; k++; } if(j==Line.size()-1) { temp[j-start+1]='\0'; re_Line[k] = temp; k++; } } cout<<"Case #"<<i+1<<": "; for(int count=k-1;count>=1;count--) { cout<<re_Line[count]<<' '; } cout<<re_Line[count]<<endl; } }
关于C++标准库申明头文件的时候是没有.h的,从C标准库继承过来的头文件可以在前面加c,比如ctype.h在C++标准库就是cctype。然后C++标准库需要申明这个头文件的命名空间 std