poj 1000 入门题

A+B Problem Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 412305   Accepted: 231456 Description Calculate a+b Input Two integer a,b (0<=a,b<=10) Output Output a+b Sample Input 1 2 Sample Output 3 Hint Q: Where are the input and the output?  A: Your program shall always  read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout.  You  shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer".  User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer"if you try to do so.  Here is a sample solution to problem 1000 using C++/G++:  #include <iostream> using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b << endl; return 0; } It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error.  Here is a sample solution to problem 1000 using C/GCC:  #include <stdio.h> int main() { int a,b; scanf("%d %d",&a, &b); printf("%d\n",a+b); return 0; } Here is a sample solution to problem 1000 using Pascal:  program p1000(Input,Output); var a,b:Integer; begin Readln(a,b); Writeln(a+b); end. Here is a sample solution to problem 1000 using Java:  Now java compiler is jdk 1.5, next is program for 1000  import java.io.*; import java.util.*; public class Main { public static void main(String args[]) throws Exception { Scanner cin=new Scanner(System.in); int a=cin.nextInt(),b=cin.nextInt(); System.out.println(a+b); } } Old program for jdk 1.4  import java.io.*; import java.util.*; public class Main { public static void main (String args[]) throws Exception { BufferedReader stdin = new BufferedReader( new InputStreamReader(System.in)); String line = stdin.readLine(); StringTokenizer st = new StringTokenizer(line); int a = Integer.parseInt(st.nextToken()); int b = Integer.parseInt(st.nextToken()); System.out.println(a+b); } } Here is a sample solution to problem 1000 using Fortran:  PROGRAM P1000 IMPLICIT NONE INTEGER :: A, B READ(*,*) A, B WRITE(*, "(I0)") A + B END PROGRAM P1000 Source POJ

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ac代码

#include <stdio.h>

int main()
{
	int a,b,ans;
	
	while(~scanf("%d%d",&a,&b))
	{
		ans=a+b;
		
		printf("%d\n",ans);
	}
	
	return 0;
}