project欧拉第六题

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

求1至100自然数的和的平方与平方的和之差

答案：25164150

python code:

    print  sum(x for x in xrange(101))**2-reduce(lambda x,y:x+y*y, xrange(101))