链接:
原题:
You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string.
Given two stringssandt, you have to decide whethersis a subsequence oft, i.e. if you can remove characters fromtsuch that the concatenation of the remaining characters iss.
Input Specification
The input contains several testcases. Each is specified by two stringss, tof alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF.
Output Specification
For each test case output, ifsis a subsequence oft.
Sample Input
sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter
Sample Output
Yes
No
Yes
No
/* * UVa: 10340 - All in All * Time: 0.008s * Author: D_Double */ #include<iostream> #include<cstdio> #include<cstring> using namespace std; char str1[1000000], str2[1000000]; bool judge(){ int pos=0, i; for(i=0; i<strlen(str1); ++i){ bool flag=false; while(pos < strlen(str2)){ if(str2[pos]==str1[i]) break; ++pos; } if(pos==strlen(str2)) return false; ++pos; } if(i==strlen(str1)) return true; return false; } int main(){ while(scanf("%s %s",str1,str2)!=EOF){ if(judge()) printf("Yes\n"); else printf("No\n"); } return 0; }
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原创http://blog.csdn.net/shuangde800,By D_Double (转载请标明)