Anagrams

LeetCode 438: Find All Anagrams in a String

题目描述：hhttps://leetcode.com/problems/find-all-anagrams-in-a-string/题目本身并不难，这里主要比较两种方法在时间上的差异：方法一：每次去s中与
豆瓣酱1991·2020-06-27 03:19

LeetCode 49 [Group Anagrams]

原题给出一个字符串数组S，找到其中所有的乱序字符串(Anagram)。如果一个字符串是乱序字符串，那么他存在一个字母集合相同，但顺序不同的字符串也在S中。对于字符串数组["eat","tea","tan","ate","nat","bat"]返回[["ate","eat","tea"],["nat","tan"],["bat"]]解题思路首先，注意返回结果中，子字符串数组内要保持有序，所以第一步先
Jason_Yuan·2020-06-27 02:15

Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theorderofyouroutputdo
Heisenberg-William·2020-06-26 07:01

Find All Anagrams in a String

//438Givenastringsandanon-emptystringp,findallthestartindicesofp'sanagramsins.StringsconsistsoflowercaseEnglishlettersonlyandthelengthofbothstringssandpwillnotbelargerthan20,100.Theorderofoutputdoesno
极速魔法·2020-06-26 01:37

Group Anagrams 字母异位词分组（Java）

题目：Givenanarrayofstrings,groupanagramstogether.Example:Input:[“eat”,“tea”,“tan”,“ate”,“nat”,“bat”],Output:[[“ate”,“eat”,“tea”],[“nat”,“tan”],[“bat”]]Note:Allinputswillbeinlowercase.Theorderofyouroutpu
volador_r·2020-06-25 21:54

Group Anagrams【Python字典操作】

Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theorderofyouroutputdo
qyx_1995·2020-06-25 04:17

Group Anagrams 解题报告

题目链接：https://leetcode.com/problems/anagrams/Givenanarrayofstrings,groupanagramstogether.Forexample,given
小榕流光·2020-06-24 23:38

49.Group Anagrams

49.GroupAnagrams题目描述：Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]题目大意：给定一个sting数组，将字母颠倒后相等的字符串组
OovEver·2020-06-24 16:14

Group Anagrams 解题报告

:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]思路：两个单词属于同一anagrams
魔豆Magicbean·2020-06-24 13:01

Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theorderofyouroutputdo
liff_lee·2020-06-24 12:32

LeetCode每日一题：anagrams

Givenanarrayofstrings,returnallgroupsofstringsthatareanagrams.Note:Allinputswillbeinlower-case.问题分析这题不太理解：Anagrams—LeetCode-CodeGanker
yoshino·2020-06-24 07:34

Group Anagrams

tea”,“tan”,“ate”,“nat”,“bat”],Return:[[“ate”,“eat”,”tea”],[“nat”,”tan”],[“bat”]]思路1，使用前面的题目来判断两个字符串是否为anagrams
liuchongee·2020-06-24 06:50

Group Anagrams （Java实现）

原题：Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]题目大意：给出一个字符串数组，将其按照组成字母相同这一条件来分组，即组成字符串的字符完全相同的字
fyy607·2020-06-23 09:45

(map)Group Anagrams

思想：将每个字符串转成数组进行sort，将sort得到的结果作为key值，value值就是相应的使用这些字符的字符串构成的数组。/***@param{string[]}strs*@return{string[][]}*/vargroupAnagrams=function(strs){//定义一个map，key是排序的str值，value是数组letmap=newMap();//遍历数组strs.f
Ching_Lee·2020-06-23 08:05

leetcode之Find All Anagrams in a String（438）

题目：给定一个字符串s和一个非空字符串p，找到s中所有是p的字母异位词的子串，返回这些子串的起始索引。字符串只包含小写英文字母，并且字符串s和p的长度都不超过20100。说明：字母异位词指字母相同，但排列不同的字符串。不考虑答案输出的顺序。示例1:输入:s:"cbaebabacd"p:"abc"输出:[0,6]解释:起始索引等于0的子串是"cba",它是"abc"的字母异位词。起始索引等于6的子串
崔先生的博客·2020-06-23 01:32

Find All Anagrams in a String在字符串中寻找同构体(Sliding Window)

问题描述：  Givenastringsandanon-emptystringp,findallthestartindicesofp’sanagramsins.  StringsconsistsoflowercaseEnglishlettersonlyandthelengthofbothstringssandpwillnotbelargerthan20,100.  Theorderofoutput
Shauna_Wu·2020-06-22 05:48

Group Anagrams (Medium) (cpp)

Leetcode49.GroupAnagrams(Medium)(cpp)Tag:HashTable,StringDifficulty:Medium/*49.GroupAnagrams(Medium)Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],R
Niko_Ke·2020-06-22 02:28

Find All Anagrams in a String

可以用字典做也可以用再加个函数判断是否是AnagramsclassSolution:deffindAnagrams(self,s,p):""":types:str:typep:str:rtype:List[int]"""ifs=="":return[]res=[]lp=len(p)ls=len(s)iflp>ls:return[]pdict={}sdict={}foriinrange(lp):if
Neekity·2020-06-22 02:18

leetcode-滑动窗口（双指针-代码有套路-附总结代码）总结-满足条件-破坏条件（76，438，3,209有模板(别人总结的很好，学习一波)）

滑动窗口：（其实可以理解为双指针）参考自原作者链接：https://leetcode-cn.com/problems/find-all-anagrams-in-a-string/solution/hua-dong-chuang-kou-tong-yong-si-xiang-jie-jue-zi
LLM1602·2020-06-21 23:06

Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Forthereturnvalue,eachinnerlist'selementsmustf
EbowTang·2020-06-21 19:22

Group Anagrams

属于hashTable题目描述：Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theord
每天开心成为别人的望尘莫及·2020-06-21 05:09

Find All Anagrams in a String

packageLeetCode_438/***438.FindAllAnagramsinaString*https://leetcode.com/problems/find-all-anagrams-in-a-string
johnny_zhao·2020-06-20 15:00

Leetcode: Group Anagrams

听说这是一个高频考题哈哈从给的array里，把是anagram的组成一个list。这个题看起来简单，做起来也没那么简单。很明显，如果第一个元素和后面的一个一个比，okay，可以知道anagramof第一个元素。然后你在从第二个元素开始，又和后面所有比一遍。。但是这么做后面的元素和之前是anagram会多数一遍，而且这个速度也太慢了。于是乎，我就想到了用hashset和hashtable搭配来解决的
98Future·2020-04-06 10:10

Find All Anagrams in a String

找到字符串中所有字母易位词。给定一个字符串s和一个非空字符串p，找到s中所有是p的字母异位词的子串，返回这些子串的起始索引。例子，Example1:Input:s:"cbaebabacd"p:"abc"Output:[0,6]Explanation:Thesubstringwithstartindex=0is"cba",whichisananagramof"abc".Thesubstringwit
朝鲜冷面杀手·2020-04-03 14:00

Group Anagrams

DescriptionGivenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlower-case.Solutio
Nancyberry·2020-04-02 00:54

Group Anagrams

classSolution(object):defgroupAnagrams(self,strs):""":typestrs:List[str]:rtype:List[List[str]]"""anagram_dict,result=collections.defaultdict(list),[]forstringinstrs:sorted_str=''.join(sorted(string))a
阿团相信梦想都能实现·2020-03-31 20:40

[LeetCode 438] Find All Anagrams in a String (easy)

Givenastringsandanon-emptystringp,findallthestartindicesofp'sanagramsins.StringsconsistsoflowercaseEnglishlettersonlyandthelengthofbothstringssandpwillnotbelargerthan20,100.Theorderofoutputdoesnotmatt
蓝眼睛灰·2020-03-29 16:24

Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theorderofyouroutputdo
Super_Alan·2020-03-26 22:54

HackerRank:Strings: Making Anagrams Python3

题目Aliceistakingacryptographyclassandfindinganagramstobeveryuseful.Weconsidertwostringstobeanagramsofeachotherifthefirststring'sletterscanberearrangedtoformthesecondstring.Inotherwords,bothstringsmustc
流浪山人·2020-03-26 08:02

Group Anagrams

publicclassSolution{publicList>groupAnagrams(String[]strs){List>res=newArrayListmap=newHashMapsub=newArrayList<>();sub.add(str);res.add(sub);map.put(s,res.size()-1);}}returnres;}}
夜皇雪·2020-03-26 07:22

Group Anagrams

Medium好几个String,HashMap的API不是很熟悉，但非常实用，记一下吧：char[]和String的互相转换char[]chas=s.toCharArray();StringkeyStr=String.valueOf(chas);遍历hashmap的所有keymap.keySet()将map.values()以ArrayList>类型返回这里主要是要知道ArrayList的一个构造
greatfulltime·2020-03-26 04:36

6.28 ctAndSay & anagrams & simplifyPath & lenOfLastWord

注重medium先不做hard吧-todoanagram写过了1]CountandSay**1.naive的模拟，73%**stringcountAndSay(intn){if(n(),*i));findif(iteratorstart,iteratorend,unaryoperation):within[first,end),->returntheiteratorpointingtothefir
陈十十·2020-03-22 06:59

Anagrams

Givenanarrayofstrings,returnallgroupsofstringsthatareanagrams.NoticeAllinputswillbeinlower-caseExampleGiven["lint","intl","inlt","code"],return["lint","inlt","intl"].Given["ab","ba","cd","dc","e"],ret
蓝眼睛灰·2020-03-21 17:30

Leetcode - Group Anagrams

Mycode:importjava.util.ArrayList;importjava.util.Arrays;importjava.util.HashMap;importjava.util.List;publicclassSolution{publicList>groupAnagrams(String[]strs){if(strs==null)returnnull;ArrayList>resul
Richardo92·2020-03-20 04:52

[HashTable]049 Group Anagrams

分类：HashTable考察知识点：HashTable数组遍历最优解时间复杂度：O(mnlogn)*49.GroupAnagramsGivenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","ta
野生小熊猫·2020-03-19 06:44

Find All Anagrams in a String

p.length()，用来表示目前窗口中的字符和p的差异度（由于窗口最大时（为p.length()）才有可能使NumberOfDeference为0，所以NumberOfDeference为0时窗口中与p为Anagrams
ifeelok0319·2020-03-18 18:39

算法9 Group Anagrams

题目：给出一组字符串，把字母相同顺序不同的词分成一类例如，给出：["eat","tea","tan","ate","nat","bat"],返回：[["ate","eat","tea"],["nat","tan"],["bat"]]思路：对数组遍历，取出每个字符串进行排序，将排序过后相同的字符串作为Map的key传入，然后value传入排序之前的字符串的集合。代码：publicList>group
holmes000·2020-03-18 03:57

Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlower-case.题意：把应用同样字母的单词，放在一个
关玮琳linSir·2020-03-17 22:14

[LintCode] Substring Anagrams

不是专门刷LintCode也没时间没耐心，只是刷贴吧看到这个问题就看了一下发现Python真的太棒了。SubstringAnagrams.png网上有符合要求的代码，反正也只是简单难度。我自己随便思考出来的方法似乎会超时，见求教各位，这题怎么搞？一贴。总之就是由于无序而转为统计每个字符出现的个数并比较。这个思路的C++11版代码，没测试是否超时#include#include#include#in
碎冰op·2020-03-13 03:55

Find All Anagrams in a String

题目来源一道滑动窗口问题，我一开始想着用一个哈希表存储p各个字母出现的频次，然后滑动窗口对其进行加减操作，当每一个字母都是0的时候，是我们想要的。代码如下：classSolution{public:vectorfindAnagrams(strings,stringp){vectormaps(26,0);vectorcom(maps);vectorres;intn1=s.size(),n2=p.si
我叫胆小我喜欢小心·2020-03-11 05:04

049 Group Anagrams

Givenanarrayofstrings,groupanagramstogether.Example：Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note：Allinputswillbeinlowercase.Theorderofyouroutputdo
烟雨醉尘缘·2020-03-09 01:53

Group Anagrams

题目Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlower-case.答案classSolution{
BLUE_fdf9·2020-03-06 20:31

LC49.Group Anagrams

思路：把每个词都按字母进行排序，放进map中，看结果是否相同。所以map中存的是字符串，有该字符串顺序的词（是一个list，每次遇到有一样顺序的词都加到list后面）输出之前还要讲每个列表按照内部的词排序一下。（用collections.sort()）思路即：单词按字母排序。列表按单词排序。知识点：字符串排序？将其先转成char数组，对数组排序再转回字符串转char数组？char[]carr=st
夫复何言酱K·2020-03-05 00:57

Anagrams

题目Givenanarrayofstrings,groupanagramstogether.Forexample,given:["eat","tea","tan","ate","nat","bat"],Return:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlower-case.频度：4解题之法classSol
时光杂货店·2020-03-01 05:08

Making Anagrams

packagemainimport"fmt"funcmain(){//Enteryourcodehere.ReadinputfromSTDIN.PrintoutputtoSTDOUTvars1,s2stringfmt.Scanln(&s1)fmt.Scanln(&s2)arr1:=make([]int,26)//arr2:=make([]int,26)for_,val:=ranges1{arr1[
luomoxyz·2020-03-01 03:29

Amazon-Find All Anagrams in a String (Easy)

Givenastringsandanon-emptystringp,findallthestartindicesofp'sanagramsins.StringsconsistsoflowercaseEnglishlettersonlyandthelengthofbothstringssandpwillnotbelargerthan20,100.Theorderofoutputdoesnotmatt
海生2018·2020-02-28 13:01

Group Anagrams/字母异位词分组

Givenanarrayofstrings,groupanagramstogether.Example:Input:["eat","tea","tan","ate","nat","bat"],Output:[["ate","eat","tea"],["nat","tan"],["bat"]]Note:Allinputswillbeinlowercase.Theorderofyouroutputdo
袁凪炎·2020-02-28 05:36

Group Anagrams

Medium用char[]排序后的新string做key来建立hashMap.最后把每个key的所有value加到List里的list就行classSolution{publicList>groupAnagrams(String[]strs){List>res=newArrayList>map=newHashMap());}map.get(chars).add(str);}for(Stringke
greatfulltime·2020-02-21 03:54

Group Anagrams python

49.GroupAnagramspython题目：https://leetcode.com/problems/anagrams/难度:Medium我又来使用我的取巧神奇python大法``classSolution
oo上海·2020-02-18 19:24

Find All Anagrams in a String

Leetcode438Givenastringsandanon-emptystringp,findallthestartindicesofp'sanagramsins.StringsconsistsoflowercaseEnglishlettersonlyandthelengthofbothstringssandpwillnotbelargerthan20,100.Theorderofoutput
尚无花名·2020-02-18 12:38
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