Anyone

WP7真机调试socket遇到的连接问题，做个记载

If anyone is following this thread.
·2015-10-31 19:41

奥巴马2008.11.4总统选举获胜演讲

Obama, as prepared for deliveryElection NightTuesday, November 4th, 2008Chicago, Illinois If there is anyone
·2015-10-31 18:06

How to ask a Question?

One day I was sitting in class, minding my own business when the teacher said: "Does anyone have
·2015-10-31 18:06

UVA 11732 Trie树应用

strcmp() Anyone?
·2015-10-31 15:05

Pair Programming 1 ---------Mine ++(Yun Ouyang & Yu Liu)

If anyone feels
·2015-10-31 14:29

32-8 Responding to Congratulations on a Promotion

The Letter: Dear Pauline: I can't think of anyone I'd rather have a letter from on my promotion than
·2015-10-31 13:17

An Introduction to ARM Assembly Language

This document is intended for anyone who occasionally needs to debug compiled ARM code at the assembly
·2015-10-31 11:33

Bitcoin

 is an experimental, decentralized digital currency that enables instant payments to anyone
·2015-10-31 11:21

Change Has Come to America

If there is anyone out there who still doubts that America is a place where all things are possible;
·2015-10-31 11:09

constellio——基于solr的开源搜索引擎系统源码研究（四）

* * This copyrighted material is made available to anyone
·2015-10-31 10:38

constellio——基于solr的开源搜索引擎系统源码研究（三）

* * This copyrighted material is made available to anyone wishing
·2015-10-31 10:38

constellio——基于solr的开源搜索引擎系统源码研究（五）

* * This copyrighted material is made available to anyone wishing to use, modify,
·2015-10-31 10:38

《老友记》的100句经典台词

我不会轻易放过她的2、It could happen to anyone./ It happens to anybody./ That happens.
·2015-10-31 10:48

******Can anyone explain me what do you mean by CreateControl

from: http://social.msdn.microsoft.com/Forums/en/winforms/thread/eebdfa0d-696e-43c4-bcfc-7aabe027a44f     Hi..i would like to know what is CreateControl() method.I have gone through
·2015-10-31 10:31

UpperCase for ALL Text Editors

  FROM: http://community.devexpress.com/forums/p/62366/211324.aspx Hi, Does anyone know
·2015-10-31 10:29

c#创建access查询

accomplish creating queries in Access using C# so I thought I would post my solution to this in case anyone
·2015-10-31 10:24

【青春励志】当幸福来敲门——我的考研故事

“When I started, I had no support from anyone, no education, no money.I was like a stone with no soul
·2015-10-31 09:01

[爆炸旧闻]Crazy Eddie离开CEGUI工程

Paul (CrazyEddie) has left the project, deleting his sourceforge accounts without notifying anyone on
·2015-10-31 08:19

制作你的第一个HTML 5游戏

Be Creating Download Source Files Demo View It Online HTML5 is growing up faster than anyone
·2015-10-30 15:36

“Failed to upload *.app on Device ” Error in iPhone

Anyone facing
·2015-10-30 13:22

jsp jsp:useBean 在第二个jsp页面访问第一个jsp页面中产生的ArrayList

i would like to do the following but i cannot access the ArrayList viathe JSP. could anyone help?
·2015-10-30 11:17

Implementing an XML-RPC Service with ASP.NET MVC

In case anyone is interested this is how to do it Define an interface for your XML-RPC
·2015-10-27 15:24

Photon——Cached Events 缓存事件

     Usually, the operation   RaiseEvent  sends your event to anyone
·2015-10-23 08:54

pclose : no child process

I'm stumped and I thought I'd see if anyone in the communityhas an idea.
·2015-10-23 08:30

Anyone can cook

昨天看了《美食总动员》，又称料理鼠王。 真好看！很多年不看动画片的LG，都连连夸好看！     这个片子拍的真好，故事情节丰富，思想境界也比较高，是寓教寓乐的动画片。值得推荐！！！     要是我也有那样一只神奇的小老鼠，一只长的好看的、聪明可爱的、会做无数美食的小老鼠，那是一件多么美好的事情呀！   
·2015-10-21 13:39

content in map

Has anyone started to play around with adding rich content (i.e.
·2015-10-21 13:03

Using Pointers in C#

Anyone who has done a fair amount of work in C or C++ would not have been able to
·2015-10-21 11:49

每日英语：First Offer: Take It Or Keep Waiting?

Anyone who has searched for a job fresh out of college knows how difficult it is to get that first job
·2015-10-21 11:20

有关封装的一点事

We don’t want anyone else to depend on them…Why, then, do so many programmers automatically add gettters
·2015-10-21 10:51

不做办公室的Gossip Girl

A：Yes, but let's step into my office so we don't disturb anyone else. What is it?
·2015-10-21 10:41

uva 11732 "strcmp()" Anyone?(字典树)

给n个字符串，问两两比较字典序大小，总共所需比较次数。将所有字符串依次插入字典树里面。记val[i]表示经过结点i的字符串数目，End[i]表示以结点i结尾的字符串数目。则每次插入时，可以知道当前结点已经经过的字符串数目，结果累加2*val[i]，到最后一个结点时，累加之前以当前结点结尾的字符串数目。注意，一开始插入的时候需要比较s[0]和t[0]，即一开始两个字符串就存在一次比较，因此需要加上v
u014679804·2015-09-18 12:00

UVA 11732-"strcmp()" Anyone?-trie（左儿子右兄弟表示法(省空间)）

本题数据略大，显然不能用普通的儿子节点法建立trie，因此采用左儿子右兄弟表示法建树，其实就是二叉树表示法，本质就是把原来的26叉树转成2叉树，时间复杂度常数增大，空间复杂度尽可能减小我们知道26叉树中，如果数据不那么变态，应该是大部分节点都是浪费掉的，而使用二叉树建树，能充分利用空间，缺点就是原来访问某个节点的子节点如果查询子节点中有没‘a’字符，我们只需要访问ch[u][0]即可，O（1），而
viphong·2015-09-11 10:00

uva_11732_"strcmp()" Anyone?(字典树)

"strcmp()"Anyone?
jhgkjhg_ugtdk77·2015-09-08 21:00

linux 程序 打开 /dev/mem permission denied

链接：http://www.element14.com/community/thread/19995/l/anyone-know-how-to-access-raspi-gpio-without-sudo
风竹夜·2015-06-12 15:09

汉诺塔的C语言实现

implementation of hanoi game  * file name: hanoi.c  * author: John Woods  * date: 2015/05/30  * statement: anyone
小强零号·2015-05-30 22:00

Zookeeper 内建ACL访问控制权限代码

这里我只用了基于用户名密码的digest 模式，还有world auth  ip 三种模式ZooKeeper有下列内建模式：world  有独立id，anyone，代表任何用户。
杨小杨·2015-05-26 14:00

or the solution to anyone e

ThatmarkcameasRoserosetomeetKellyManski'sleftwingcornerkickAaronHernandezindictedontwocountsoffirstdegreemurder20AaronHernandezindictedontwocountsoffirstdegreemurder2012doublehomicideMore>>Hernandezat
lluggg847·2015-05-26 11:00

数据结构：栈（用数组实现）

stack with array list  * file name: ArrayStack.c  * author: John Woods  * date: 2015/5/10  * statement: anyone
小强零号·2015-05-10 11:00

数据结构：栈（用链表实现）

 stack with linked list  * file name: stack.c  * author: John Woods  * date: 2015/5/9  * statement: anyone
小强零号·2015-05-09 21:00

数据结构：链表

file is the implementation of the Linked List   * author: John Woods  * date: 2015/5/7  * statement: anyone
小强零号·2015-05-08 19:00

数据结构：顺序表

 this c file is a implementation of linear list  * author: John Woods  * date: 2015/5/3  * exclaim: anyone
小强零号·2015-05-06 15:00

Zookeeper中ACL（访问控制列表）

Zookeeper提供了几种认证方式 * world：有个单一的ID，anyone，表示任何人。 * auth：不使用任何ID，表示任何通过验证的用户（是通过ZK验证的用户？
zhaoshijie·2015-04-10 17:00

Uva 11732 "strcmp()" Anyone? (字典树）

两个字符串匹配时，如果对应位置相同，则需要比较两次（第二次判断是否为'\0'），若失败只需比较一次。因此，把所有字符串建成一个字典树，每个节点用num记录有多少个字符串经过这里。那么对于这个位置，考虑匹配成功的情况，共发生num×（num-1）/2×2次比较。对于这个节点的每一个后继结点，设该节点的num值为tnum，那么在前驱节点上有num-tnum个和该节点字符不相同的字符，比较的次数为（nu
Baoli1008·2015-03-18 19:00

UVA 11732("strcmp()" Anyone?-Trie与左兄弟右儿子)

“strcmp()”Anyone?
nike0good·2015-03-04 18:00

UVA 11732 "strcmp()" Anyone? Trie树 + 树的左儿子右兄弟存储法

题目大意：在C/C++的函数比较的STL中存在这样的字符串比较函数：intstrcmp(char*s,char*t) { inti; for(i=0;s[i]==t[i];i++) if(s[i]=='\0') return0; returns[i]-t[i]; }现在有N个给出的字符串(N #include #include #include #include #include #include
u013738743·2015-02-12 17:00

linux下VMWare 端口映射与转发的例子

去控制的方法在这个版本上不可行1、进入下面目录/etc/vmware/vmnet8/nat/nat.conf2、编辑这个文件，在文件的最后可以看到：[incomingtcp]#Usethesewithcare-anyone
45571845·2015-01-26 18:00

How Much Does it Cost to Get a Pilot License?

The feat of flying has long been a dream of many, young and old, and thanks to modern technology, anyone
dandada·2015-01-26 17:00

0~255整数转化为二进制序列

-----------------//Author:心海//Date:2013-12-02//Blog:http://blog.sina.com.cn/u/2116533530//Copyright:anyone
Godwin_Q·2015-01-01 21:06

关于Rails性能调整

touseframework,Railsisaprettycomplexbeast.Overtheyearsithasprogressedfromaseeminglysimpleframeworkthat“anyone
mot·2014-12-27 00:00

A tcpdump Tutorial and Primer[reproduced]

Having a solid grasp of this über-powerful application is mandatory for anyone desiring a thoro
jimmee·2014-12-24 22:00
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