{function_2();int[]arr={56,65,11,98,57,43,16,18,100,200};int[]newArray=test(arr);System.out.println(Arrays.toString

1、优化过的快速排序法int[]array={11,12,232,32,23,18,34};Arrays.sort(array);//升序System.out.println(Arrays.toString

publicstaticvoidmain(String[]args){int[]a={1,32,5,3,2,74,23};quickSort(a,0,a.length-1);System.out.println(Arrays.toString

=request.getParameterMap();Setkeys=paramMap.keySet();for(Stringkey:keys){System.out.println(key+":"+Arrays.toString

Arrays:工具类int[]arr={34,56,78,89};Arrays.toString(arr);//吧数组中的数据转成字符串//数组转集合String[]a={"hello","hello2

publicclassDelTest{@Testpublicvoidtest1(){String[]ids={"1","2","4"};//(1,2,3)//第一步把ids转成字符串System.out.println(Arrays.toString

;Classb=newArrayList().getClass();a==b:-->trueclassWang{}Listlist=newArrayList();System.out.println(Arrays.toString

publicstaticvoidmain(String[]args){int[]a={2,51,3,8,5,16,9};mergeSort(a,0,a.length-1);System.out.println(Arrays.toString

publicstaticvoidmp(inta[]){intswap=0;for(inti=0;ia[i]){swap=a[i];a[i]=a[j];a[j]=swap;}}}System.out.println(Arrays.toString

]args){System.out.println("原数组：");int[]arr={10,8,15,16,6,9,1,7,11,20,12,5};//示例数组System.out.println(Arrays.toString

String[]args){int[]arr={11,2,9,4,5};int[]brr=newint[10];//排序ShortDemo(arr);//打印排序后数组System.out.println(Arrays.toString

根据对象获取类3Classa=o.getClass();4//获取所有访问权限为public的属性5Field[]f1=a.getFields();6System.out.println("公共属性:"+Arrays.toString

publicstaticvoidmain(String[]args){int[]arr={22,54,-1,33,66,99,22,35,0,2};System.out.println("排序前的数组："+Arrays.toString

publicclassBubbleSort{publicstaticvoidmain(String[]args){int[]arr={3,4,2,9,10,15,11,0,1};System.out.println(Arrays.toString

doublearray[]={0.78,0.17,0.39,0.26,0.72,0.94,0.26,0.12,0.23,0.68};bucketSort(array);System.out.println(Arrays.toString

String[]cArray=newString[]{"a","b","c","d","e"};2打印一个arrayint[]intArray={1,2,3,4,5};StringintArrayString=Arrays.toString

publicList>fourSum(int[]nums,inttarget){Arrays.sort(nums);//System.out.println(Arrays.toString(nums))

使用Arrays.toString输出数组中的内容。输入样例：512ab453输出样例：java.lang.NumberFormatExcep

int[]arr={1,2,3};Integer[]arr2={4,5,6};String[]str={"1","2"};System.out.println(Arrays.toString(arr

“a”,“b”,“c”};-Stringstrings=newString[10];获得指定索引位置的元素strings[5]设置指定索引位置的元素strings[5]=“hello”输出数组中的元素Arrays.toString

publicclassTestDoubleColor{publicstaticvoidmain(String[]args){int[]r=readyArray(33);int[]b=readyArray(16);System.out.println(Arrays.toString

一个个比较过去缺点交换次数过多publicstaticvoidmain(String[]args){Integer[]a=newInteger[]{3,6,2,9,4};sort(a);System.out.println(Arrays.toString

确实也如此：这道题比较特别的地方是用一个int数组state来记录哪些数已经被用过，哪些数没有，然后map里面做记忆化搜索时用string来代表这个state，StringcurtState=Arrays.toString

4、Arrays.toString(数组名);该方法按顺序把多个数组元素连接在一起，包含数组的前后中括号，多个元素之间使用逗号和空格隔开。5、Java中方法的重载？如果

publicclassSortTest{publicstaticvoidmain(String[]args){int[]arr={2,5,3,1,4};System.out.println("排序前："+Arrays.toString

可以看出一个程序员的编程思想的深度，就拿最简单的冒泡排序来说，请看下面代码：方式一：publicstaticvoidbubbleSortV1(int[]arr){System.out.println("冒泡排序前："+Arrays.toString

publicclassRadixSort{publicstaticvoidmain(String[]args){int[]arr={23,435,1,45,666,85,30,77};System.out.println("排序前:"+Arrays.toString

将数组第一个数作为有序数组，后面的数据依次往有序数据中插入*稳定排序*/publicstaticvoidinsertSort(int[]arr){System.out.println("插入排序前："+Arrays.toString

[]={75,70,85,80,60,100,90};//757060808510090==>607075808510090QuickSort(arr,0,6);System.out.println(Arrays.toString

关注点：两层循环，循环次数length-1，优化标识flag减少循环次数publicstaticvoidbubbleSort(int[]arr){System.out.println("冒泡排序前："+Arrays.toString

args){int[]a={23,4,56,2,7,18,9};for(inti=0;ia[j+1]){t=a[j];a[j]=a[j+1];a[j+1]=t;}}}System.out.println(Arrays.toString

importjava.util.Arrays;classlesson6{publicstaticvoidmain(String[]args){intarray[]={2,3,1,5,4,6};System.out.println(Arrays.toString

LotteryDrawResultVOresult=newLotteryDrawResultVO();    result.setOpencode("2,3,1");     StringopenCode=Arrays.toString

插入排序：代码：publicstaticvoidmain(String[]args){int[]a=suiji();System.out.println(Arrays.toString(a));System.out.println

if(arr==null||arr.lengtharr[j+1]){temp=arr[j];arr[j]=arr[j+1];arr[j+1]=temp;}}}maopaosortTv.setText(Arrays.toString

toCharArray()//获得字符串对应的char数组Arrays.sort()//数组排序Arrays.toString(char[]a)//数组转成字符串charA

publicstaticvoidmain(String[]args){int[]arr={10,9,8,7,6,5,4,3,2,1};selectionSort(arr);System.out.println(Arrays.toString

PostMapping("/v1")publicListarr01(@RequestParam("ids[]")String[]ids){System.out.println("v1------>"+Arrays.toString

{for(intj=0;ja[i]){minPos=i;}}//switchinttmp=a[j];a[j]=a[minPos];a[minPos]=tmp;//System.out.println(Arrays.toString

publicvoidbubbleSort(int[]a){for(inti=0;ia[j+1]){inttmp=a[j+1];a[j+1]=a[j];a[j]=tmp;stop=false;}//System.out.println(Arrays.toString

1,78,56,213,86,5642,8,89,456,345,234,7};demo.quickSort(arr,0,arr.length-1);//demo.bubbleSort(arr);System.out.println(Arrays.toString

Stringhql="fromPrivilege";Queryquery=session.createQuery(hql);Listlist=query.list();System.out.println(Arrays.toString

关键字修饰成员变量和成员方法.png静态static内存图.png静态代码块静态代码块.pngArrays数组工具类int[]num={2,1,0,12,8,5,7,15};//返回字符串Stringstring=Arrays.toString

int[]array={3,8,5,65,34,27};System.out.println(array.toString());System.out.println(Arrays.toString(array

如果仅仅为了打印数组，不需要把数组转换成List，可以使用Arrays.toString()方法。2.List转换成数组List转换成数

而一开始asList的设计时用于打印数组而设计的，但jdk1.5开始，有了另一个比较更方便的打印函数Arrays.toString(),于是打印不再使用asList()，而asList()恰巧可用于将数组转为集合

而一开始asList()的设计时用于打印数组而设计的，但jdk1.5开始，有了另一个比较更方便的打印函数Arrays.toString(),于是打印不再使用asList()，而asList()恰巧可用于将数组转为集合

;//也可这样定义获得数组元素的个数：arry.length2.增强的for循环：for(variable:collection)statement//定义变量暂存collection（数组）中的元素Arrays.toString

oldArr={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5};int[]newArr=clearZero(oldArr);System.out.println("新数组的元素："+Arrays.toString

importjava.util.Arrays;publicclassMergeSort{publicstaticvoidmain(String[]args){int[]arr1={4,2,6,3,5};System.out.println(Arrays.toString