HDU3631

hdu3631 Shortest Path （floyd 插点法）

ShortestPath题意：给n、m、q，表示n个点m条边q个询问每个询问两种方式0x，表示标记x，如果已经被标记就输出ERROR!Atpointx1xy，表示输出x到y的最短距离，要求x和y都及其最短路径上的点都被标记过，如果x或y没有被标记输出ERROR!Atpathxtoy，如果x到y之间没有路径就输出NosuchpathSampleInput51010126335045725336963
这有点难啊·2020-09-15 03:42

hdu3631 Shortest Path

#include#include#include#includeusingnamespacestd;constintINF=1b?b:a;}voidfloyd(intk){inti,j;for(i=0;iC)path[A][B]=path[B][A]=C;为初始化前的条件，其作用与path[A][B]=Min(path[A][B],C);相同，但也不能用。。。为什么。。。
Flynn_curry·2020-09-15 02:39

hdu 3631 多源最短路

/* * hdu3631/win.cpp * Created on: 2011-9-6 * Author : ben */#include <cstdio>#in
·2015-11-11 15:27

HDU3631：Shortest Path(Floyd)

Problem Description When YY was a boy and LMY was a girl, they trained for NOI (National Olympiad in Informatics) in GD team. One day, GD team’s coach, Prof. GUO asked them to solve the following sh
·2015-11-09 13:25

[hdu3631]背包或中途相遇法

暴力的背包： 1 #pragma comment(linker, "/STACK:10240000,10240000") 2 3 #include <iostream> 4 #include <cstdio> 5 #include <algorithm> 6 #include <cstdlib>
·2015-11-02 16:32

HDU3631 Shortest Path 【Floyd】

ShortestPathTimeLimit:3000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):3938    AcceptedSubmission(s):930ProblemDescriptionWhenYYwasaboyandLMYwasagirl,theytrainedforN
u012846486·2014-07-28 12:00

HDU3631：Shortest Path(Floyd)

ProblemDescriptionWhenYYwasaboyandLMYwasagirl,theytrainedforNOI(NationalOlympiadinInformatics)inGDteam.Oneday,GDteam’scoach,Prof.GUOaskedthemtosolvethefollowingshortest-pathproblem.Thereisaweighteddir
libin56842·2013-12-10 19:00

hdu3631 floyd

ShortestPathTimeLimit:3000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):3229    AcceptedSubmission(s):767ProblemDescriptionWhenYYwasaboyandLMYwasagirl,theytrainedforN
JustSteps·2013-04-06 19:00

hdu 3631 Shortest Path

点击打开链接hdu3631思路：最短路+floyd分析：1题目给的n #include #include #include usingnamespacestd; #defineMAXN310 #defineINF0xFFFFFFF
cgl1079743846·2012-10-19 17:00
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