Increasing 第9页

Longest Increasing Subsequence-最长子序列|动态规划

原题链接：300.LongestIncreasingSubsequence【思路1-Java】T=O(n2)|M=O(n)建立一个大小与nums长度相等的数组maxLens，用于记录每个nums最长长度，即maxLens[i]表示nums第0个到第i个元素中以nums[i]为最大值的最长子序列长度（注意序列的最后一个值为nums[i]）：publicclassSolution{publicintl

Code_Granker·2020-07-02 02:12

Longest Increasing Subsequence 解题报告（Python & C++）

：fuxuemingzhu个人博客：http://fuxuemingzhu.cn/目录题目描述题目大意解题方法日期题目地址：https://leetcode.com/problems/longest-increasing-subsequence

负雪明烛·2020-07-02 00:01

leetcode_Longest Increasing Subsequence

描述：Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattheremayb

mnmalist·2020-07-01 22:36

LeetCode -- Longest Increasing Subsequence

题目描述：Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattherema

_iorilan·2020-07-01 21:33

Longest Increasing Subsequence 解题报告

300.LongestIncreasingSubsequenceMySubmissionsQuestionTotalAccepted:17302TotalSubmissions:51952Difficulty:MediumGivenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Giv

bruce128·2020-07-01 19:19

LeetCode 300 Longest Increasing Subsequence

题目描述Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattheremay

_我们的存在·2020-07-01 15:03

Longest Increasing Subsequence

300.LongestIncreasingSubsequence原题目链接题解1：直接DP（Accepted）LIS算是动态规划中的经典题目了，在笔者看到的每一个讲解动态规划的题目中都会有此题的出现。在这里简单整理一下思路和转移方程。根据之前的原则，DP中求什么就设什么。我们设dp[i]是在0～i上的LIS的长度。我们现在需要考虑初始条件和转移方程。初始条件：在最开始时，dp[i]=1代表序列中只

BIurryface·2020-07-01 08:38

leetcode[300] Longest Increasing Subsequence

题目：给定一个无序的整数数组，找到其中最长上升子序列的长度。输入：整数数组输出：最长上升子序列的长度思路：动态规划为了探究从较短的上升子序列到较长的上升子序列的关系，我们关注较短的上升子序列的结尾，因此，定义dp[i]为以num[i]为结尾的最长上升子序列的长度。递推关系式：代码：classSolution{public:intlengthOfLIS(vector&nums){intsize=nu

Kobe Forever·2020-07-01 03:27

【leetcode】673 最长递增子序列的个数（动态规划）

题目链接：https://leetcode-cn.com/problems/number-of-longest-increasing-subsequence/题目描述给定一个未排序的整数数组，找到最长递增子序列的个数

zjwreal·2020-06-30 18:35

LintCode 397 [Longest Increasing Continuous Subsequence]

原题给定一个整数数组（下标从0到n-1，n表示整个数组的规模），请找出该数组中的最长上升连续子序列。（最长上升连续子序列可以定义为从右到左或从左到右的序列。）样例给定[5,4,2,1,3],其最长上升连续子序列（LICS）为[5,4,2,1],返回4.给定[5,1,2,3,4],其最长上升连续子序列（LICS）为[1,2,3,4],返回4.解题思路正序逆序各求一个最长序列的值，取最大一个全局变量r

Jason_Yuan·2020-06-30 08:57

Increasing Triplet Subsequence (M)

IncreasingTripletSubsequence(M)题目Givenanunsortedarrayreturnwhetheranincreasingsubsequenceoflength3existsornotinthearray.Formallythefunctionshould:Returntrueifthereexistsi,j,ksuchthatarr[i]mid，说明就能构成严格

墨云黑·2020-06-30 06:00

Python中的math库

importmathdefmain():money_everyweek=10#每周存入的金额i=1#第几周increasing_money=10#每周递增的金额end_week=52#总共存52周saving_money

kate zhu·2020-06-29 07:54

增加堆内存的大小 - 提防眼镜蛇效应

>>>增加堆内存的大小-提防眼镜蛇效应原文:http://plumbr.eu/blog/increasing-heap-size-beware-of-the-cobra-effect"眼镜蛇效应"起源于当时英国统治印度殖民地的轶事

Msro·2020-06-28 12:55

Longest Increasing Subsequence

Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattheremaybemo

weixin_34125592·2020-06-28 11:53

897. 递增顺序查找树-未解决

897.递增顺序查找树https://leetcode-cn.com/contest/weekly-contest-100/problems/increasing-order-search-tree/packagecom.test

weixin_33831673·2020-06-28 06:36

递增顺序查找树(Increasing Order Search Tree)

目录题目描述：示例：解法：题目描述：给定一个树，按中序遍历重新排列树，使树中最左边的结点现在是树的根，并且每个结点没有左子结点，只有一个右子结点。示例：输入：[5,3,6,2,4,null,8,1,null,null,null,7,9]5/\36/\\248//\179输出：[1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]1\2

weixin_30412167·2020-06-27 19:44

递增顺序查找树(Increasing Order Search Tree)

897.递增顺序查找树897.IncreasingOrderSearchTree题目描述给定一个树，按中序遍历重新排列树，使树中最左边的结点现在是树的根，并且每个结点没有左子结点，只有一个右子结点。LeetCode897.IncreasingOrderSearchTree示例:输入:[5,3,6,2,4,null,8,1,null,null,null,7,9]5/\36/\\248//\179输出

weixin_30394981·2020-06-27 19:35

POJ - 1239 Increasing Sequences （DP）

题意：给定数字组成的字符串，将其划分为严格递增的序列。且第一个数最大，最后一个数最小。分析：因为要满足两个条件，所以进行两次dp，第一次dp[i]计算到i为止的最小长度，且满足单调递增，那么此时最后一个数就保证了最小，第二次从后往前计算此时dp[i]表示从i开始的最大长度，且满足单调递增，那么此时的第一个数就最大。#include#include#include#include#include#i

Combatting·2020-06-25 18:54

Leetcode 897.递增顺序查找树（Increasing Order Search Tree）

Leetcode897.递增顺序查找树1题目描述（Leetcode题目链接）给你一个树，请你按中序遍历重新排列树，使树中最左边的结点现在是树的根，并且每个结点没有左子结点，只有一个右子结点。输入：[5,3,6,2,4,null,8,1,null,null,null,7,9]5/\36/\\248//\179输出：[1,null,2,null,3,null,4,null,5,null,6,nul

就叫昵称吧·2020-06-25 16:54

Longest Increasing Subsequence（最长上升子序列 LIS）

300.LongestIncreasingSubsequence题目描述和难度题目描述：给定一个无序的整数数组，找到其中最长上升子序列的长度。示例:输入:[10,9,2,5,3,7,101,18]输出:4解释:最长的上升子序列是 [2,3,7,101]，它的长度是4。说明:可能会有多种最长上升子序列的组合，你只需要输出对应的长度即可。你算法的时间复杂度应该为O(n2)。进阶:你能将算法的时间复杂度

liweiwei1419·2020-06-24 10:43

Increasing Triplet Subsequence

Description:Givenanunsortedarrayreturnwhetheranincreasingsubsequenceoflength3existsornotinthearray.Formallythefunctionshould:Returntrueifthereexistsi,j,ksuchthatarr[i]&nums){intn1=INT_MAX,n2=INT_MAX;f

黑山老水·2020-06-24 02:19

【简单】897. 递增顺序查找树

来源：leetcode链接：https://leetcode-cn.com/problems/increasing-order-search-tree/【提示】给定树中的结点数介于1和100之间每个结点都有一个从

小学三年级01班·2020-06-24 02:23

Reveal Cards In Increasing Order 按递增顺序显示卡牌

Inadeckofcards,everycardhasauniqueinteger.Youcanorderthedeckinanyorderyouwant.Initially,allthecardsstartfacedown(unrevealed)inonedeck.Now,youdothefollowingstepsrepeatedly,untilallcardsarerevealed:Take

Grandyang·2020-06-22 11:00

Longest Increasing Subsequence

LeetCode300.LongestIncreasingSubsequenceSolution1：我的答案暴力搜索，时间复杂度O(n2)O(n2)classSolution{public:intlengthOfLIS(vector&nums){intn=nums.size(),res=1;if(!n)return0;if(n==1)return1;//注意：这种对数组初始化的方式只会初始化第一个

Allenlzcoder·2020-06-21 16:34

LeetCode 897. 递增顺序查找树

原题目：https://leetcode-cn.com/problems/increasing-order-search-tree/思路：中序遍历，之后重建树代码：classSolution{public

庾信平生最萧瑟·2020-06-21 06:11

Longest Increasing Subsequence 解题报告

Description:Givenasequenceofintegers,findthelongestincreasingsubsequence(LIS).YoucodeshouldreturnthelengthoftheLIS.Example:For[5,4,1,2,3],theLISis[1,2,3],return3For[4,2,4,5,3,7],theLISis[2,4,5,7],retu

黑山老水·2020-06-21 01:31

Longest Increasing Subsequence

DescriptionGivenasequenceofintegers,findthelongestincreasingsubsequence(LIS).YoucodeshouldreturnthelengthoftheLIS.找出最长的递增子序列，遍历数组，如果是以当前元素为起点的话，那么比如说，{1，4，2，3，5}这个数组，处理起来就比较麻烦。不妨换个思路：以当前元素作为序列的结尾，看它前面

Jain_Shaw·2020-05-19 10:00

Longest Increasing Subsequence

Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattheremaybemo

aemaeth·2020-04-14 08:42

leetcode 300 最长上升子序列

地址：https://leetcode-cn.com/problems/longest-increasing-subsequence/大意：给定一个数组，找到最长上升子序列//时间复杂度O(n^2)，动态规划

一只小白的进修路·2020-04-12 01:00

Leetcode - Increasing Triplet Subsequence

Mycode:publicclassSolution{publicbooleanincreasingTriplet(int[]nums){intmin=Integer.MAX_VALUE,secondMin=Integer.MAX_VALUE;for(intnum:nums){if(numsecondMin)returntrue;}returnfalse;}}reference:https://d

Richardo92·2020-04-06 02:33

Longest Continuous Increasing Subsequence

DescriptionGivenanunsortedarrayofintegers,findthelengthoflongestcontinuousincreasingsubsequence(subarray).Example1:Input:[1,3,5,4,7]Output:3Explanation:Thelongestcontinuousincreasingsubsequenceis[1,3,

Nancyberry·2020-04-05 17:13

Minimum Swaps To Make Sequences Increasing

题目WehavetwointegersequencesAandBofthesamenon-zerolength.WeareallowedtoswapelementsA[i]andB[i].Notethatbothelementsareinthesameindexpositionintheirrespectivesequences.Attheendofsomenumberofswaps,AandBa

BLUE_fdf9·2020-04-04 09:00

Longest Increasing Subsequence

问题描述Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.示例Example:Input:[10,9,2,5,3,7,101,18]Output:4Explanation:Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthi

saki_xiong·2020-04-04 05:12

Day 44:)Discuss the benefits and dangers brought by the increasing use of robots.

Withthedevelopmentofartificialintelligencerobot,increasinglyuseofrobotswillfreehumanbeingsfrommonotonouslaborwork,entitlingthemwithmoreamusementtime.However,robotusingisadoubleedgedsword.Excessivedepe

archi姗·2020-04-02 23:09

Longest Increasing Continuous Subsequence(最长上升连续子序列)

问题Giveanintegerarray，findthelongestincreasingcontinuoussubsequenceinthisarray.Anincreasingcontinuoussubsequence:Canbefromrighttoleftorfromlefttoright.Indicesoftheintegersinthesubsequenceshouldbecontin

天街孤独·2020-04-02 07:02

Longest Increasing Continuous Subsequence

EasyGiveanintegerarray，findthelongestincreasingcontinuoussubsequenceinthisarray.Anincreasingcontinuoussubsequence:Canbefromrighttoleftorfromlefttoright.Indicesoftheintegersinthesubsequenceshouldbecont

greatfulltime·2020-03-26 09:05

Tai Chi attracts increasing number of fans in U.S.

ATaiChienthusiastpractisesdoublebroadswordsataTaiChiworkshopinLasVegas,theUnitedStates,Oct.20,2018.Foundinmanycommunitycenters,healthclubsandstudiosintheUnitedStates,TaiChihasafavorablereputationthank

深圳陈自强太极学堂·2020-03-25 05:16

Longest Increasing Path in a Matrix

题目来源给一个矩阵，求里面的最长递增路径长度。看到这道题就想到微软面试的那道题目。先把所有元素排序，然后找到各个元素，通过周边比它大的元素的最长递增路径长度来设定它的最长递增路径长度。最后再遍历一遍得到答案。代码如下：classSolution{public:intlongestIncreasingPath(vector>&matrix){introws=matrix.size();if(rows

我叫胆小我喜欢小心·2020-03-24 05:30

76. 最长上升子序列

https://en.wikipedia.org/wiki/Longest_increasing_subsequence样例给出[5,4,1,2,3]，LIS是[1,2,3]，返回3给出

6默默Welsh·2020-03-23 10:04

Longest Increasing Subsequence

题目要求：Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Forexample,Given[10,9,2,5,3,7,101,18],Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis4.Notethattherema

Jarryd·2020-03-22 06:46

【Spark实战】Spark操作HBase问题：java.io.IOException: Non-increasing Bloom keys

1问题描述在使用SparkBulkLoad数据到HBase时遇到以下问题：17/05/1914:47:26WARNscheduler.TaskSetManager:Losttask0.0instage12.0(TID79,bydslave5,executor3):java.io.IOException:Non-increasingBloomkeys:80a01055HAXMTXG10100001K

_和_·2020-03-20 23:01

Longest Increasing Subsequence

问题描述：Givenanunsortedarrayofintegers,findthelengthoflongestincreasingsubsequence.Example:Input:[10,9,2,5,3,7,101,18]Output:4Explanation:Thelongestincreasingsubsequenceis[2,3,7,101],thereforethelengthis

牛奶芝麻·2020-03-20 01:04

longest increasing subsequence nlogn 算法

O(n^2)算法逻辑：贪心+二分搜索数据定义补充：开一个栈，将a[0]入栈，每次取栈顶元素top和读到的元素ai做比较，如果a[i]>top则将a[i]入栈；如果a[i]<=top则二分查找栈中的比a[i]大的第1个数，并用a[i]替换它。最长序列长度即为栈的大小top。这是很好理解的，对于x和y，如果x

走出幻觉走向成熟·2020-03-18 06:13

Longest Continuous Increasing Subsequence

题目Givenanunsortedarrayofintegers,findthelengthoflongestcontinuousincreasingsubsequence(subarray).Example1:Input:[1,3,5,4,7]Output:3Explanation:Thelongestcontinuousincreasingsubsequenceis[1,3,5],itslen

BLUE_fdf9·2020-03-16 08:03

Number of Longest Increasing Subsequence

题目Givenanunsortedarrayofintegers,findthenumberoflongestincreasingsubsequence.Example1:Input:[1,3,5,4,7]Output:2Explanation:Thetwolongestincreasingsubsequenceare[1,3,4,7]and[1,3,5,7].Example2:Input:[2,

BLUE_fdf9·2020-03-11 14:03

Increasing Decreasing String

1.原题链接：https://leetcode.com/problems/increasing-decreasing-string/2.解题思路直观的想法是：用有序map记录字母和字母出现的次数按照题目描述的方式

wengle·2020-03-08 20:00

算法原型--最长递增子序列(Binary Search DP)

[leetcode300]https://leetcode.com/problems/longest-increasing-subsequence/题目扩展俄国沙皇问题方法一：O(n^2)算法流程：使用一个数组

futurehau·2020-03-08 09:35

LeetCode #897 Increasing Order Search Tree 递增顺序查找树

Description:Givenabinarysearchtree,rearrangethetreeinin-ordersothattheleftmostnodeinthetreeisnowtherootofthetree,andeverynodehasnoleftchildandonly1rightchild.Example:Example1:Input:[5,3,6,2,4,null,8,1

air_melt·2020-03-05 09:00

Longest Increasing Subsequence

d[i]i为结尾的最长递增子序列，d[0]=1,d[i]算出[0,i)找出d[i]>d[[0,i)],同时d[[0,i)]中的最大值加一然后算出最大的d[]intlengthOfLIS(int*nums,intnumsSize){int*lis,i,j,max=0;lis=(int*)malloc(sizeof(int)*numsSize);/*InitializeLISvaluesforalli

larrymusk·2020-03-01 11:54

最长上升子序列 Longest Increasing Subsequence

https://leetcode-cn.com/probl...这道题目用暴力是O（n^2)使用保存序列尾部元素的思路可以优化到O（nlogn）暴力O(n^2)classSolution:deflengthOfLIS(self,nums:List[int])->int:ifnotnums:return0dp=[1]*len(nums)foriinrange(1,len(nums)):forjinr

sxwxs·2020-02-27 14:12

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