Investigating

Codeforces Round #310 (Div. 1)——A水——Case of Matryoshkas

He is now investigating the case of vandalism at the exhibition of contemporary art.
·2015-10-31 15:10

8个实用的Linux netcat命令

Netcat or nc is a networking utility for debugging and investigating the network.
·2015-10-31 12:21

uva 11361 - Investigating Div-Sum Property(数位dp)

题意：题目大意：给出a，b，k，问说在[a,b]这个区间有多少n，满足n整除k，以及n的各个为上的数字之和也整除k。 分析：dp[i][nmod][smod]长度为i,该数对k的余数，各位和对k的余数。 #include <map> #include <set> #include <list> #include <cmath> #inc
·2015-10-30 13:06

Uva_11361 Investigating Div-Sum Property

题目链接 题意： 　　在[A,B]区间内找出满足条件的数有多少个。 　　条件：这个数本身 能够整除K， 且各位数字之和能够整除K。   思路： 　　数据范围过大2^31 　　2^31 = 2147483648 ~ 2*10^10      各位数字之和不会超过 2 + 9 * 9 = 83 ， 所以 当K >= 83 时 答案
·2015-10-27 12:11

Uva 11361 Investigating Div-Sum Property(数位DP)

大致题意：问在区间[a,b]内有多少个整数满足被K整除，且这个数的每一位上数字的和也被K整除a，b #include #include #include #include #include #include #include #include #include #include #include #include #defineSZ(x)((int)(x).size()) #defineALL(v
kalilili·2015-10-22 11:00

Profiling MySQL queries from Performance Schema

utm_source=tuicool When optimizing queries and investigating performance issues, MySQL comes with built
·2015-10-21 12:22

Number of Rectangles in a Grid

Project Euler 85: Investigating the number of rectangles in a rectangular grid   Number of Rectangles
·2015-10-21 12:32

uva 11361 Investigating Div-Sum Property

各位数之和不会超过100，所以k>100时直接输出0。dp[a][b][c]表示有a位未知，未知各位之和除以K的余数为b,未知位组成的数字除以K的余数位c的个数。#include #include #include usingnamespacestd; inta[15],num[15]; intdp[15][100][100]; intK; voidprework() { a[0]=1; for
u011281853·2014-08-05 09:00

Investigating Your RAM Usage

BecauseAndroidisdesignedformobiledevices,youshouldalwaysbecarefulabouthowmuchrandom-accessmemory(RAM)yourappuses.AlthoughAndroid’sDalvikvirtualmachineperformsroutinegarbagecollection,thisdoesn’tmeanyo
Jerikc·2014-06-04 10:00

uva 11361 - Investigating Div-Sum Property(数位dp)

题目链接：uva11361-InvestigatingDiv-SumProperty题目大意：给出a，b，k，问说在[a,b]这个区间有多少n，满足n整除k，以及n的各个为上的数字之和也整除k。解题思路：数位dp，dp[i][j][x]表示第i为的时候，n整除k余j，n（以及考虑到的位数）的各个位置上的数字之和整除k余x的情况总数，并且每次要计算上限的临界值。#include #include #
u011328934·2014-05-18 20:00

Uva 11361 Investigating Div-Sum Property 解题报告（递推）

INextgenerationcontest–4TimeLimit–4 secsInvestigatingDiv-SumProperty  Anintegerisdivisibleby3ifthesumofitsdigitsisalsodivisibleby3.Forexample,3702isdivisibleby3and12(3+7+0+2)isalsodivisibleby3.Thispro
kbdwo·2014-03-19 21:00

UVA - 11361 Investigating Div-Sum Property

题意：统计大于等于a,小于等于b，每一位之和可以被k整除，且本身也能被k整除的数的数量。思路：用dp[pos][i][j]表示n的还剩pos位的时候和的余数是i，整除的余数是j，每次试着添加一位，更新余数，还要一个标记数来标记是否记忆，注意整形范围内，各个位上的数字和不会超过100#include #include #include #include #include usingnamespace
u011345136·2014-02-14 20:00

UVa 11361 Investigating Div-Sum Property / 数位DP

先上代码以后再说#include #include constintmaxn=110; intdp[maxn][maxn][maxn]; intok(intx,intk) { if(x82) { printf("0\n"); continue; } intc=a,d=1; memset(dp,0,sizeof(dp)); for(inti=0;ib) { //printf("%d\n",d); b
u011686226·2014-01-30 18:00

Investigating Oracle RAC Interconnect Performance

InvestigatingOracleRACInterconnectPerformanceByScottJesse,BillBurton,BryanVongrayThe interconnectinanOracleRACenvironmentisthebackboneofyourcluster.Ahighlyperforming,reliableinterconnectisacrucialingr
haiross·2014-01-09 17:00

CLR Inside Out Investigating Memory Issues

CLRInsideOutInvestigatingMemoryIssuesClaudioCaldato and MaoniStephens ContentsToolsoftheTradeGCPerformanceCountersWindowsPerformanceCountersVerifyinganOOMExceptioninaManagedProcessDeterminingWhatCause
changtianshuiyue·2013-12-25 21:00

investigating the family

#include#include#include#include#include#defineNAME_MAX20struct{   char*filename;   FILE*pfile;}global={"E:\\myfile.bin",NULL};structDate{   intday;   intmonth;   intyear;};typedefstructfamily{   stru
pokerlee·2013-12-17 21:00

vs2010取消显示所有文件 崩溃

这属于vs2010的bug，以下是微软官方对些问题的回应： i am still investigating the problem, but looks like the issue is
·2013-06-27 10:00

UVA 11361 Investigating Div-Sum Propertyt

【题意】给定a,b,p求出thenumberofintegersintherange[A, B]whichisdivisibleby p andthesumofitsdigitsisalsodivisibleby p.1=100时答案一定是0！！（各位数之和最大不超过100）然后设计状态进行数位DP即可。f[i][j][k]表示i位数，这个数modp为j，各位数之和modp为k的方案数。【Codi
HyogaHyoga·2013-01-19 17:00

Investigating Div-Sum Property UVA11361

思路按照训练指南上说的的递推，table[i][j][k]表示i位数各位数字和对给定数取模为j，数字本身对给定数取模为k的数字个数，最后的统计细节需要注意，要从高位到低位统计,个位要单算。#include #include #include #include #include #include #include #include #include #include #include #includ
gyarenas·2013-01-18 09:00

Investigating bug

在虚拟机上的客户SMPOS上，一运行我们的程序就hang住了，别的情况下，如UP，直接在板子上运行SMPOS，都运行良好。查看了几天的代码，才发现我们的程序根本就没实现SMP在虚拟机上的特性，faint啊
zechunwei·2012-05-10 20:00

2010/10/13第一课 Mexican investigator probing lake shooting slain

=================================================== AUSTIN, Texas — A Mexican police commander investigating
surfingForRest·2010-11-09 10:00

Troubleshooting agent_exec garbage collection

seem to be more and more posts on the forums about jobs ‘stuck’ in the Running state and I have been investigating
gexp.fang·2010-08-20 09:00

RIL Proxy Logging --- The Most Important Debugging Tool for Investigating Radio and RIL Issues

----------------------------------------RILproxylogginginMagnetoAKU2: StartingwithMagnetoAKU2,RILproxyloggingfeatureiscomponentizedintoaseparate,optionalDLL,rillog.dll.Thepurposeofthischangeistoreduce
ymzhou117·2010-05-08 22:00

Investigating Internet Business Opportunities_267

InvestigatingInternetBusinessOpportunities ThereareliterallythousandsorperhapsmillionsofInternetbusinessesavailableforentrepreneurstoinvestigateanddevelop.Thequestionis,howdoyouknowwhichonesaregoin
ltnda4fi·2009-12-09 19:31

RH033 Unit 11 Investigating and Managing Processes Part II: Job Control

定时任务设定一次性的定时任务使用“at”，建立周期性任务则使用“crontab”新建任务attimecrontab-e任务列表at�Clcrontab-l详细信息at�Ccjobnumn/a删除任务at�Cdjobnumcrontab-r编辑任务n/acrontab-e两种命令执行结果的输出均以邮件方式通知用户，并不返回至屏幕或其他位置at支持多种复杂的时间定义方式，可以接受HH:MM这样的具体时
bobo504·2009-12-03 15:37

RH033 Unit 11 Investigating and Managing Processes Part II: Job Control

定时任务设定一次性的定时任务使用“at”，建立周期性任务则使用“crontab”新建任务attimecrontab-e任务列表at�Clcrontab-l详细信息at�Ccjobnumn/a删除任务at�Cdjobnumcrontab-r编辑任务n/acrontab-e两种命令执行结果的输出均以邮件方式通知用户，并不返回至屏幕或其他位置at支持多种复杂的时间定义方式，可以接受HH:MM这样的具体时
bobo504·2009-12-03 15:37

RH033 Unit 11 Investigating and Managing Processes Part I: Process Management

什么是进程简单的理解，一个进程就是载入在内存中的一组程序指令，是一个应用程序的运行实例我们通常使用进程号（PID）来对进程进行识别，当然进程同样也包含有UID、GID和SELinux安全上下文等一些从执行者那里继承过来的权限和属性查看进程信息ps：列出进程，默认显示当前终端的进程参数-a：列出所有终端的进程-x：列出那些不依赖终端运行的进程，也就是列出后台进程-u：列出进程拥有者信息-f：树形方式
bobo504·2009-11-17 17:06

RH033 Unit 11 Investigating and Managing Processes Part I: Process Management

什么是进程简单的理解，一个进程就是载入在内存中的一组程序指令，是一个应用程序的运行实例我们通常使用进程号（PID）来对进程进行识别，当然进程同样也包含有UID、GID和SELinux安全上下文等一些从执行者那里继承过来的权限和属性查看进程信息ps：列出进程，默认显示当前终端的进程参数-a：列出所有终端的进程-x：列出那些不依赖终端运行的进程，也就是列出后台进程-u：列出进程拥有者信息-f：树形方式
bobo504·2009-11-17 17:06

Update on the Windows 7 USB/DVD Tool

As you've likely read  and as was originally reported here , we've been investigating a report
love~ruby+rails·2009-11-14 10:00

A great technology is worth investigating

After one year hard work, RTC 2.0 and JF 1.0 have been released last month, it's worth investigating
alexgreenbar·2009-07-14 10:00

Lessons from the test lab: investigating a pleasan

This post describes our recent investigation into an interesting performance problem: benchmarks that we were surprised to find running significantly faster than we expected on new hardware. Along the
willpower·2009-04-16 10:00

Lessons from the test lab: investigating a pleasan

阅读更多Thispostdescribesourrecentinvestigationintoaninterestingperformanceproblem:benchmarksthatweweresurprisedtofindrunningsignificantlyfasterthanweexpectedonnewhardware.Alongthewaywediscussusefulbenchm
willpower·2009-04-16 10:00

RH033 Unit11 Investigating and Managing Processes

ObjectivesUponcompletionofthisunit,youshouldbeableto:ExplainwhataprocessisDescribehowtomanageprocessUsejobcontroltoolsWhatisaProcess?1)AprocessisasetofinstructionsloadedintomemoryNumericProcessID(PID)
jackie.chen·2009-03-30 22:06

Euler Project解题汇总 031 ~ 040

问题31： Investigating combinations of English currency denominations.
Eastsun·2008-07-01 23:00
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