Repeating 第10页

Longest Substring Without Repeating Characters

文章目录1.题目详情2.解题方法2.1解法12.2解法21.题目详情Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.给出一个字符串，找到最长的且没有重复字符的子串。Example1:Input:“abcabcbb”Output:3Explanation:Theansweris“abc”,withth

liangyy75·2020-06-24 12:55

1.5 Animation 动画 - Repeating Motion 重复运动

Animateanumber(ex:position,opacity,scale)backandforthrepeatedly.输入口Enable启用Abooleanthatturnstheanimationon/off.开／关的布尔值，意思在开合关之间切换。Duration持续时间Thelength,inseconds,oftheanimationinonedirection.时间长度。Curv

刘板栗·2020-06-24 09:59

LeetCode 3. 无重复字符的最长子串

https://leetcode-cn.com/problems/longest-substring-without-repeating-characters/思路1：构造一个map来保存每个字符最近一次出现的索引

csdn20160806·2020-06-24 08:14

3.Leetcode Longest Substring Without Repeating Characters

题目Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1:Input:“abcabcbb”Output:3Explanation:Theansweris“abc”,withthelengthof3.解题方法借助unordered_set来实现最大连续无重复字符串，基础知识参考我的博客cl

爱宝宝的菜鸟·2020-06-24 07:21

Longest Substring Without Repeating Characters

题目：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1:Input:"abcabcbb"Output:3Explanation:Theansweris"abc",withthelengthof3.Example2:Input:"bbbbb"Output:1Explanation:Th

hope1262946533·2020-06-24 06:10

longest-substring-without-repeating-characters

Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Forexample,thelongestsubstringwithoutrepeatinglettersfor“abcabcbb”is“abc”,whichthelengthis3.For“bbbbb”thelongestsubstringis“b”

ldw662523·2020-06-24 03:26

Longest Substring Without Repeating Characters）...

【LeetCode&剑指offer刷题】字符串题15：48最长不含重复字符的子字符串（3.LongestSubstringWithoutRepeatingCharacters）【LeetCode&剑指offer刷题笔记】目录（持续更新中...）3.LongestSubstrleftngWithoutRepeatingCharactersGivenastring,findthelengthofthe

wikiwen·2020-06-24 01:34

Swift中的集合类型

1.1创建一个空数组varsomeInts=[Int]()1.2创建一个带有默认值得数组varthreeDoubles=Array(repeating:0.0,count:3)//等价于[0.0,0,0,0.0

keisme·2020-06-23 16:21

3.Longest Substring Without Repeating Characters-python

Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given“abcabcbb”,theansweris“abc”,whichthelengthis3.Given“bbbbb”,theansweris“b”,withthelengthof1.Given“pwwkew”,theansw

alg-flody·2020-06-23 02:07

Longest Substring Without Repeating Characters最长不重复子串

LongestSubstringWithoutRepeatingCharactersGivenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given“abcabcbb”,theansweris“abc”,whichthelengthis3.Given“bbbbb”,theansweris

a2320064997·2020-06-22 10:27

Longest Substring Without Repeating Characters

DescriptionGivenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.ExampleExample1:Input:“abcabcbb”Output:3Explanation:Theansweris“abc”,withthelengthof3.Example2:Input:“bbbbb”Output:

SMonkeyKing·2020-06-22 04:45

Longest Substring Without Repeating Characters（C++）

地址：https://leetcode.com/problems/longest-substring-without-repeating-characters/题目：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1

Ethan95·2020-06-21 20:58

Longest Substring Without Repeating Characters (没有重复字符的最长子字符串)

原题：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1:Input:"abcabcbb"Output:3Explanation:Theansweris"abc",withthelengthof3.Example2:Input:"bbbbb"Output:1Explanation:Th

dby_freedom·2020-06-21 19:10

Longest Substring Without Repeating Characters（字符串+思维）

##3.LongestSubstringWithoutRepeatingCharactersDescription：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given“abcabcbb”,theansweris“abc”,whichthelengthis3.Given“bb

David_Jett·2020-06-21 19:32

【LeetCode-面试算法经典-Java实现】【003-Longest Substring Without Repeating Characters（最长非重复子字符串）】

【003-LongestSubstringWithoutRepeatingCharacters（最长非重复子字符串）】原题Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Forexample,thelongestsubstringwithoutrepeatinglettersfor“abcabcbb

Wang-Junchao·2020-06-21 19:05

Longest Substring Without Repeating Characters

3.LongestSubstringWithoutRepeatingCharactersGivenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given"abcabcbb",theansweris"abc",whichthelengthis3.Given"bbbbb",theanswer

雨狮子·2020-06-21 18:22

Longest Substring Without Repeating Characters

LeetCode3.LongestSubstringWithoutRepeatingCharactersSolution1：我的答案该方法中哈希表记录的是字符出现的次数。标准的贪心算法，超过80%的答案；如果哈希表记录字符出现的位置则还能进一步优化。classSolution{public:intlengthOfLongestSubstring(strings){//我猜是贪心算法intn=s.s

Allenlzcoder·2020-06-21 16:34

Longest Substring Without Repeating Characters 没有重复字符的最长子串

hashtable题目描述：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1:Input:"abcabcbb"Output:3Explanation:Theansweris"abc",withthelengthof3.Example2:Input:"bbbbb"Output:1Exp

每天开心成为别人的望尘莫及·2020-06-21 05:09

Longest Substring Without Repeating Characters

题目链接：https://leetcode.com/problems/longest-substring-without-repeating-characters/题目难度：Medium题目描述：Givenastring

听这一刻的晚风·2020-06-21 05:53

Collection Types

创建数组，数组简写[Int]varsomeInts=[Int]()varthreeDoubles=Array(repeating:0.0,count:3)varsixDoubles=threeDoubles

夜雨聲煩_·2020-06-21 02:45

Longest Repeating Character Replacement

packageLeetCode_424/***424.LongestRepeatingCharacterReplacement*https://leetcode.com/problems/longest-repeating-character-replacement

johnny_zhao·2020-06-20 21:00

【LeetCode】3. 无重复字符的最长子串(典型滑动窗口)

题目链接https://leetcode-cn.com/problems/longest-substring-without-repeating-characters/题目描述给定一个字符串，请你找出其中不含有重复字符的最长子串的长度

控球强迫症·2020-05-02 16:00

rust leetcode Longest Substring Without Repeating Characters #3

每日小刷median-of-two-sorted-arraysRuntimeMemory4ms2.6musestd::cmp;usestd::collections::HashMap;usestd::collections::HashSet;implSolution{pubfnall_unique(arr:&Vec,i:usize,j:usize)->bool{letmuthash_set:Has

奔跑的蛙牛·2020-04-29 21:32

Longest Substring Without Repeating Characters

题意：给你一个字符串，找到里面不包含相同字符的最长子串。解题思路：思路一：暴力，（loop1）从第一个字符开始，（loop2）字符数量从1到n，（loop3）判断每个子串是否符合条件。时间复杂度为O(n*n*n)。思路二：slidingwindow，滑动窗口。（loop1）从第一个字符开始，依次处理每个字符，（loop2）判断当前子串是否包含该字符，若包含，则将子串中该字符及前面的去掉，然后在尾部

alexssssu·2020-04-12 15:04

重复定律（Repeating law）

重复定律指的是任何的行为和思维，只要你不断的重复就会得到不断的加强。在你的潜意识当中，只要你能够不断地重复一些人、事、物，它们都会在潜意识里变成事实。重复定律启示启示1：累积小事，成就大事千里之行始于足下，如果不一步步地走，怎么可以行走千里呢？一屋不扫，何以扫天下？如果一个人连自己的屋子都不愿意去扫，他又怎么能够平定天下呢？所以，千万不要有"一口吃成个大胖子"的浮躁想法，那是不切实际，不利于我们实

春雪_a2bf·2020-04-11 20:43

[LeetCode] No.3 Longest Substring Without Repeating Characters

链接：https://leetcode.com/problems/longest-substring-without-repeating-characters/原题:Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples

yuansc·2020-04-11 10:58

Leetcode-第3题:Longest Substring Without Repeating Charact

题目：Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Forexample,thelongestsubstringwithoutrepeatinglettersfor"abcabcbb"is"abc",whichthelengthis3.For"bbbbb"thelongestsubstringis

八刀一闪·2020-04-10 13:52

Longest Substring Without Repeating Characters

funclengthOfLongestSubstring(sstring)int{varsMap[]runefor_,v:=ranges{sMap=append(sMap,v)}iflen(sMap)==0{return0}//max:=0headPoint:=0tailPoint:=0maxHead:=0maxTail:=0fork,_:=rangesMap{max:=maxTail-maxHe

博林木木·2020-04-08 21:32

3.Longest Substring Without Repeating Characters

1.O(n2)可优化intlengthOfLongestSubstring(strings){setset;intmaxnum=0;for(inti=0;iset;intmaxnum=0;inti=0,j=0;while(imap;intres;for(inti=0,j=0;j

林里icer·2020-04-08 18:38

CSS渐变

css渐变分为：1.线性渐变（linear-gradient）2.径向渐变（radial-gradient）3.圆锥渐变（conic-gradient）其中线性渐变与径向渐变还可以使用repeating-linera-gradient

Knight52033·2020-04-07 12:27

【CSS】同色系背景

CSS代码body{background:#983439;background-image:repeating-linear-gradient(30deg,rgba(255,255,255,.1),rgba

Rabbit_svip·2020-04-07 10:48

Longest Substring Without Repeating Characters

最近再刷leetcode,除了链表之外的都用python实现,贴出一些代码,希望指正.问题描述:Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.给定一个字符串,找到其中没有相同字符的最长序列.样例输入:Given"abcabcbb",theansweris"abc",whichthelengthis

ciantian·2020-04-07 03:59

Longest Substring Without Repeating Characters

Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given"abcabcbb",theansweris"abc",whichthelengthis3.Given"bbbbb",theansweris"b",withthelengthof1.Given"pwwkew",theansw

_SANTU_·2020-04-06 14:44

Longest Substring Without Repeating Characters

classSolution(object):deflengthOfLongestSubstring(self,s):""":types:str:rtype:int"""res=0left=0visited=[]foriinxrange(len(s)):ifs[i]notinvisited:visited.append(s[i])else:whiles[left]!=s[i]:visited.rem

阿团相信梦想都能实现·2020-04-06 03:39

Longest Substring Without Repeating Characters

classSolution:deflengthOfLongestSubstring(self,s):""":types:str:rtype:int"""arr=[-1forxinrange(128)]maxx=0now=0foriinrange(len(s)):now+=1ifarr[ord(s[i])]>-1:now=min(now,i-arr[ord(s[i])])maxx=max(maxx,

chaowwwww·2020-04-06 01:32

重复定律（Repeating law）

重复定律指的是任何的行为和思维，只要你不断的重复就会得到不断的加强。在你的潜意识当中，只要你能够不断地重复一些人、事、物，它们都会在潜意识里变成事实。启示1：累积小事，成就大事千里之行始于足下，如果不一步步地走，怎么可以行走千里呢？一屋不扫，何以扫天下？如果一个人连自己的屋子都不愿意去扫，他又怎么能够平定天下呢？所以，千万不要有"一口吃成个大胖子"的浮躁想法，那是不切实际，不利于我们实现目标的。生

春雪_a2bf·2020-04-05 15:58

Longest Substring with At Least K Repeating Characters

FindthelengthofthelongestsubstringTofagivenstring(consistsoflowercaselettersonly)suchthateverycharacterinTappearsnolessthanktimes.Example1:Input:="aaabb",k=3Output:3Thelongestsubstringis"aaa",as'a'isr

我是你的果果呀·2020-04-05 11:07

Longest Substring Without Repeating Characters 无重复字符的最长子串

题目链接tag:Medium；question： Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Example1:Input:"abcabcbb"Output:3Explanation:Theansweris"abc",withthelengthof3.Example2:Input:"bbbbb

xingzai·2020-04-04 13:55

3、Longest Substring Without Repeating Characters（无重复字符的最长字串）

题目Givenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.举例Given"abcabcbb",theansweris"abc",whichthelengthis3.Given"bbbbb",theansweris"b",withthelengthof1.Given"pwwkew",theansweris"

古月大月半·2020-04-04 06:29

Longest Repeating Character Replacement

替换后的最长重复字符。题意是给一个字符串，只有大写字母，允许你替换其中的K个字母，问替换操作完成后能返回的最长字母相同的子串的长度是多少。例子，Example1:Input:s="ABAB",k=2Output:4Explanation:Replacethetwo'A'swithtwo'B'sorviceversa.Example2:Input:s="AABABBA",k=1Output:4Exp

朝鲜冷面杀手·2020-04-04 01:00

Longest Substring with At Least K Repeating Characters

题目来源给一个字符串，以及一个数字k，求该字符串子串中每个字符出现的频次都大于等于k。还是没有想法。看了下讨论区，就是先遍历一遍，得出各个字符的频次，然后再遍历，找到第一个不符合的。然后分割成前后两块，再进行同样的操作。能过，不过时间复杂度还是比价高的，平均复杂度应该是O(nlogn)。代码如下：classSolution{public:intlongestSubstring(strings,in

我叫胆小我喜欢小心·2020-04-03 11:02

Swift学习-数组(来源:菜鸟教程)

创建数组我们可以使用构造语法来创建一个由特定数据类型构成的空数组：varsomeArray=[SomeType]()以下是创建一个初始化大小数组的语法：varsomeArray=[SomeType](repeating

SK丿希望·2020-04-03 08:40

Longest Substring Without Repeating Characters

DescriptionGivenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.给定一个字符串，找到字符串中的最长无重复子串，返回该子串的长度Examples:Given"abcabcbb",theansweris"abc",whichthelengthis3.Given"bbbbb",theansweris

6默默Welsh·2020-04-03 07:10

Swift-子数组最大乘积

核心代码:`funcmultiMaxValue(arr:[Int])->Int{letcount:Int=arr.countvarleft:[Int]=[Int].init(repeating:1,count

FlyElephant·2020-04-01 19:08

倒影box-reflect(可图片可文字)

需要写兼容写法：-webkit-box-reflect：below3px-webkit-(repeating)linear/redial-gradient(...)；1.先写direction定义方向：

独步天下A·2020-03-31 23:00

[LeetCode] 003.Longest Substring Without Repeating Characters (C++/Java)

ProblemdescriptionGivenastring,findthelengthofthelongestsubstringwithoutrepeatingcharacters.Examples:Given"abcabcbb",theansweris"abc",whichthelengthis3.Given"bbbbb",theansweris"b",withthelengthof1.Giv

QyQiaoo·2020-03-31 20:00

Swift-字符串字符是否唯一

funcisUniqueChar(str:String)->Bool{ifstr.characters.count>256{returnfalse}varchars:[Bool]=[Bool].init(repeating

FlyElephant·2020-03-31 20:40

【转】无重复字符的最长子串

转自：https://leetcode-cn.com/articles/longest-substring-without-repeating-characters/解决方案方法一：暴力法思路逐个检查所有的子字符串

davidic·2020-03-30 02:38

LeetCode in JavaScript#3 Longest Substring Without Repeating Characters

LeetCodeLongestSubstringWithoutRepeatingCharactersSolution使用两个变量记录子串的头尾位置当前位置即为子串尾位置无重复字符子串长度=当前位置-(当前位置字符上次出现位置+1)+1一种方法是一步一步的将头移动到当前位置字符上次出现的位置+1但这样会有多余的操作更好的方法是使用哈希表记录字符上次出现的位置直接将头移动到该位置varlengthOf

荼蓼子·2020-03-29 08:59

LeetCode 3 [Longest Substring Without Repeating Characters]

原题给定一个字符串，请找出其中无重复字符的最长子字符串。样例例如，在"abcabcbb"中，其无重复字符的最长子字符串是"abc"，其长度为3。对于，"bbbbb"，其无重复字符的最长子字符串为"b"，长度为1。解题思路窗口类问题-最自然的方法双层for循环，时间复杂度O(n2)解决考虑优化-即那些状态不需要扫描呢？以"abcbcbb"为例第一：left=0,right=3时出现重复，则right

Jason_Yuan·2020-03-28 09:05

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