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Wiggle
Wiggle
Sort II(摇摆排序)
原题网址:https://leetcode.com/problems/
wiggle
-sort-ii/Givenanunsortedarraynums,reorderitsuchthatnums[0]nums
jmspan
·
2016-04-26 04:49
排序
困难
第K个
鸽笼原理
中位数
间隔
leetcode——324——
Wiggle
Sort II
Givenanunsortedarraynums,reorderitsuchthatnums[0]nums[2]
happyxuma1991
·
2016-04-24 12:00
Wiggle
Sort
题目描述:给出一个无序的数组,在原地将数组排列成符合以下规律:nums[0]=nums[2]=a[1],所以交换之后,变成a[0]=a[1],并不影响a[0]和a[2]之间的顺序,因此,不需要向“冒泡排序”那样,多次扫描。那么代码就比较简单了:classSolution(object): """ @param{int[]}numsalistofinteger @returnnothing,modi
guoziqing506
·
2016-04-22 16:00
排序
Wiggle
Sort II
思路首先仿照快速排序找出数组的中位数mid,这里平均复杂度O(n),最坏复杂度O(n^2)。对数组下标作映射(假设数组长度为6):0=>1 1=>3 2=>5 3=>0 4=>2 5=>4则把大于mid的数分配给1,3,5,小于mid的数分给0,2,4,完成注意:为了防止有相邻两个数都等于中位数的问题,这里有一个分配的技巧:1、对于0,2,4,将数组元素小于mid的放在前面,这样中位数只会出现在最
zly9923218
·
2016-03-30 12:00
LeetCode
Lintcode:
wiggle
-sort
Lintcode:
wiggle
-sort没啥特别的,另一种形式的冒泡排序。先把答案做出来,下一步想想怎么优化,留个坑先。
u012225151
·
2016-03-17 14:00
Wiggle
Sort 解题报告
题目链接: https://leetcode.com/problems/
wiggle
-sort/Givenanunsortedarray nums,reorderit in-place suchthat
qq508618087
·
2016-03-13 03:00
LeetCode
array
sort
LintCode
Wiggle
Sort II
问题描述:Givenanunsortedarraynums,reorderitsuchthatnums[0]nums[2]=0;i--){nums[i]=nums[i/2];}for(i=0;i
ziyue225
·
2016-03-04 17:54
刷题心得
Wiggle
Sort II
Givenanunsortedarraynums,reorderitsuchthatnums[0]nums[2]&nums){ if(nums.empty()) return; vectoraa=nums; sort(aa.begin(),aa.end()); if(nums.size()%2!=0) for(inti=0;i
u014568921
·
2016-03-03 11:00
LeetCode
Wiggle
Sort II
Givenanunsortedarraynums,reorderitsuchthatnums[0]nums[2]&nums){ intn=nums.size(); if(ntemp(n,0); intj=n-1; for(inti=1;i
brucehb
·
2016-03-01 23:00
Wiggle
Sort
WiggleSortGivenanunsortedarray nums,reorderit in-place suchthat nums[0]=nums[2]&a){ boolinc=true; for(inti=0;ia[i]&&!inc)) swap(a[i],a[i+1]); inc=!inc; } return; }
我有一个小尾巴
·
2016-02-18 13:00
leetcode笔记:
Wiggle
Sort
一.题目描述Givenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]=nums[2]=nums[i-1]当下标i是偶数时,nums[i]&nums){ if(nums.size()&nums){ if(nums.size()nums[i-1])) swap(nums[i],nums[i-1]); } } };四.小结后续有题
liyuefeilong
·
2016-02-14 14:00
LeetCode
Algorithm
C++
sort
greedy
LeetCode
Wiggle
Sort II
原题链接在这里:https://leetcode.com/problems/
wiggle
-sort-ii/Givenanunsortedarray nums,reorderitsuchthat nums
Dylan_Java_NYC
·
2016-02-12 00:00
LeetCode
Wiggle
Sort
原题链接在这里:https://leetcode.com/problems/
wiggle
-sort/当i是奇数时,若nums[i]nums[i-1],互换。
Dylan_Java_NYC
·
2016-02-11 10:00
LeetCode "
Wiggle
Sort II" !!
https://leetcode.com/discuss/77133/o-n-o-1-after-median-virtual-indexingPleasenotethe"interleaved"versionofpartial..niceidea..
Tonix
·
2016-02-03 12:00
LeetCode "
Wiggle
Sort II" !!
https://leetcode.com/discuss/77133/o-n-o-1-after-median-virtual-indexingPleasenotethe"interleaved"versionofpartial..niceidea..
Tonix
·
2016-02-03 12:00
[LeetCode]
Wiggle
Sort 摆动排序
Givenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]&nums){ sort(nums.begin(),nums.end()); if(nums.size()=nums[2]=nums[i-1]当i为偶数时,nums[i]&nums){ if(nums.size()nums[i-1])){ swap(nums[
Grandyang
·
2016-02-02 13:00
[LeetCode]
Wiggle
Sort II 摆动排序
Givenanunsortedarray nums,reorderitsuchthat nums[0]nums[2]nums[2]&nums){ vectortmp=nums; intn=nums.size(),k=(n+1)/2,j=n; sort(tmp.begin(),tmp.end()); for(inti=0;i&nums){ #defineA(i)nums[(1+2*i)%
Grandyang
·
2016-01-18 13:00
[LeetCode 324]
Wiggle
Sort II
Givenanunsortedarray nums,reorderitsuchthat nums[0]nums[2]median){ swap(nums,vi(len,i++),vi(len,j++)); }elseif(nums[vi(len,j)]=e)returnnums[s]; intm=partition(nums,s,e); if(m==k)returnnums[m]; elseif(
sbitswc
·
2016-01-13 17:00
LeetCode
quickselection
leetcode
Wiggle
Sort II
]nums[2]>1,t=nums.length; for(inti=0;i leetcodeWiggleSortII原文地址:http://www.hrwhisper.me/leetcode-
wiggle
-sort-ii
murmured
·
2016-01-01 11:00
[LeetCode][JavaScript]
Wiggle
Sort II
WiggleSortIIGivenanunsortedarray nums,reorderitsuchthat nums[0]nums[2]
Liok_Unbelievable
·
2015-12-31 14:00
[LeetCode280]
Wiggle
Sort
Givenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]nums[i+1].比如例子,我们一直check每个nums[i]发现都满足,直到我们知道了nums[3]=1doesntsatisfynums[3]>nums[2],就把它们swap,为什么不会破坏前面的check?因为我们已经check过nums[2]nums[2]
u012175043
·
2015-11-26 05:00
LeetCode
LeetCode[13] -
Wiggle
Sort
第一遍想太多.其实做一个fall-through就能把问题解决,原因是因为:这样的fall-through每次在乎两个element,可以一口气搞定,无关乎再之前的elements。特别的一点:flag来巧妙的掌控山峰和低谷的变化。又是神奇的一幕啊!这样子的奇观,见过就要知道了,没见过的时候有点摸不着头脑。/*Givenanunsortedarraynums,reorderitin-placesu
张土汪
·
2015-11-03 05:01
*LeetCode-
Wiggle
Sort
又是不知道怎么想规律是每两个两个之间是小于每对之间是大于 所以就根据i的奇偶性来判断两个连续数字见的关系并且可以发现swap不会影响前面的正确因为一对之间的关系应该是大于假如是小于需要swap那么只会给前面换过去一个更大的所以不用担心publicclassSolution{ publicvoidwiggleSort(int[]nums){ for(inti=0;inums[i+1]) swap(n
bsbcarter
·
2015-10-17 09:00
LeetCode 题解(273) :
Wiggle
Sort
题目:Givenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]&nums){ if(nums.size()nums[j]){ intt=nums[i]; nums[i]=nums[j]; nums[j]=t; } }else{ reverse=false; if(nums[i]nums[j]: nums[i],nums[j]
u011029779
·
2015-10-11 04:00
Algorithm
LeetCode
面试题
leetcode 280:
Wiggle
Sort
WiggleSortTotalAccepted:1291TotalSubmissions:3008Difficulty:MediumGivenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]nums[i-1])){ inttemp=nums[i]; nums[i]=nums[i-1]; nums[i-1]=temp; } }
xudli
·
2015-09-26 07:00
[LeetCode#280]
Wiggle
Sort
Problem:Givenanunsortedarray nums,reorderit in-place suchthat nums[0]=nums[2]=nums[2]=nums[i+1] Note:iisanoddnumber. Solution1: publicclassSolution{ publicvoidwiggleSort(int[]nums){ Arrays.sort
airforce
·
2015-09-20 12:00
Leetcode:
Wiggle
Sort
QuestionGivenanunsortedarraynums,reorderitin-placesuchthatnums[0]=nums[2]nums[ind+1])or(notflagandcur
ayst123
·
2015-09-12 10:00
[LeetCode]
Wiggle
Sort
ProblemDescription:Givenanunsortedarray nums,reorderit in-place suchthat nums[0]=nums[2]=nums[i-1];If i iseven,then nums[i]&nums){ 4intn=nums.size(); 5for(inti=1;inums[i-1])) 7swap(nums[i],nums[i-1
jcliBlogger
·
2015-09-10 12:00
[Usaco2002 Open]
Wiggle
Numbers摆动数
[Usaco2002Open]WiggleNumbers摆动数时间限制:1Sec内存限制:128MB题目描述摇摆数是像下面的数:3748,67,869,32435465768,它们每个数每位数码的变化是:上升,下降,上升,下降,…,或者:下降,上升,下降,上升,…,上面4个数表示如下:3423456a[i-1] thenbegininc(ans);j:=0;end elsebreak else i
slongle_amazing
·
2015-06-26 21:00
Google Interview -
Wiggle
Sort
Thewiggleproblem,givenanarrayofintegersarrangethemsuchthatalternateelementsarelargeandsmall.(2,5,3,6,...)voidsort_array(int[]s){ intn=s.length; if(n==0)return; booleanflag=true; intcurrent=s[0];
yuanhisn
·
2015-05-28 09:00
Google Interview -
Wiggle
Sort
Write a function to convert the array into alternate increasing decreasing numbers: a[0] <= a[1] >= a[2] <= a[3] >=... Note: You should solve it in place and one pass. Solution
yuanhsh
·
2015-04-27 11:00
interview
Google Interview -
Wiggle
Sort
Write a function to convert the array into alternate increasing decreasing numbers: a[0] <= a[1] >= a[2] <= a[3] >=... Note: You should solve it in place and one pass. Solution
yuanhsh
·
2015-04-27 11:00
interview
15.2.4 在 F# 中创建简单的行为
清单15.6实现两个行为值(
wiggle
和time),和一个用于创建常量行为的函数(forever)。
hadstj
·
2011-12-13 17:44
职场
values
休闲
forever
ae
wiggle
表达式震颤效果祥解
原文链接:http://www.liurongxing.com/ae-
wiggle
.html=======================================我们经常在AE里制作文字特效,运用好表达式能获得很震憾的效果
shuzilang
·
2009-05-12 15:00
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