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cmath
立体视觉算法--SAD+DP
lt;cstring> #include <iostream> #include<cv.h> #include<highgui.h> #include <
cmath
·
2015-11-12 23:49
算法
Codeforces Round #192 (Div. 2)
题意:O(-1) 思路:O(-1) 1 #include <iostream> 2 #include <cstdio> 3 #include <
cmath
·
2015-11-12 23:34
codeforces
Poj 2777 Count Color(线段树基础)
此外莫名其妙的TLE #include <iostream> #include <algorithm> #include <
cmath
>
·
2015-11-12 23:31
count
poj-3899-The Lucky Numbers 模拟+数学
#include<iostream> #include<
cmath
> #include<cstdio> #incl
·
2015-11-12 23:25
number
POJ 3684 Physics Experiment
所以,完全可以忽略球的碰撞,就当它去穿过处理就可以了 #include <iostream> #include <
cmath
> #include <algorithm
·
2015-11-12 23:13
exp
POJ 2991 Crane
id=2991 《挑战程序设计竞赛》 人民邮电出版社 #include <iostream> #include <
cmath
> #include <cstdio>
·
2015-11-12 23:12
poj
poj 3368 Frequent values
id=3368 1 #include <cstdio> 2 #include <cstring> 3 #include <
cmath
> 4 #
·
2015-11-12 23:29
value
poj 3308 Paratroopers
#include <cstring> 3 #include <algorithm> 4 #include <queue> 5 #include <
cmath
·
2015-11-12 23:27
oop
poj 3422 Kaka's Matrix Travels
1 #include<cstdio> 2 #include<cstring> 3 #include<queue> 4 #include<
cmath
·
2015-11-12 23:20
Matrix
poj 2195Going Home
id=2195 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4
·
2015-11-12 23:13
home
poj Candies
2 #include<queue> 3 #include<cstring> 4 #include<algorithm> 5 #include<
cmath
·
2015-11-12 23:09
poj
poj A Round Peg in a Ground Hole
id=1584 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4
·
2015-11-12 23:08
round
poj 1113Wall
1 #include<cstdio> 2 #include<cstring> 3 #include<cstdlib> 4 #include<
cmath
·
2015-11-12 23:07
poj
poj Building a Space Station
id=2031 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:06
Build
poj Fishnet
id=1408 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4
·
2015-11-12 23:05
poj
poj Cash Machine
id=1276 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:04
mac
Expanding Rods
id=1 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:03
exp
poj Monthly Expense
id=3273 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:02
exp
poj 2031Building a Space Station
id=2031 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:01
Build
poj Pie
id=3122 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #define
·
2015-11-12 23:01
poj
Curling 2.0
id=3009 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:58
curl
Dungeon Master
1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include<cstdlib
·
2015-11-12 23:56
master
Gold Balanced Lineup
1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include <
·
2015-11-12 23:55
UP
Common Subsequence
1 #include<cstdio> 2 #include<iostream> 3 #include<
cmath
> 4 #include<string
·
2015-11-12 23:49
sequence
Stockbroker Grapevine
id=1125 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:47
broker
Frogger
id=2253 1 #include<cstdio> 2 #include<cstring> 3 #include<
cmath
> 4 #include
·
2015-11-12 23:45
r
HDU 1711 Number Sequence KMP
#include <iostream> #include <cstdio> #include <cstdlib> #include <
cmath
·
2015-11-12 23:43
sequence
SPOJ Lexicographical Substring Search 后缀自动机
disable:4996) #include<cstring> #include<string> #include<iostream> #include<
cmath
·
2015-11-12 22:50
substring
SPOJ LCS2 后缀自动机
disable:4996) #include<cstring> #include<string> #include<iostream> #include<
cmath
·
2015-11-12 22:49
poj
SPOJ LCS 后缀自动机
disable:4996) #include<cstring> #include<string> #include<iostream> #include<
cmath
·
2015-11-12 22:48
poj
读TAOCP的算法形式化定义以及归纳法的一点感受
虽然TAOCP看的章节不多,但是有了前面
CMath
的学习经验,在学习的时候有些自己的体会,与大家分享一下: 关于算法的形式化定义部分讲到了定义的四元组,在这一节的习题第9题,说的是如何用一个计算方法模拟另外一个计算方法
·
2015-11-12 22:08
OCP
用C语言写一个程序,得出当前系统的整形数字长(16位,32位,64位)等,不能使用sizeof()
#include <iostream>#include <
cmath
>using namespace std; int main(){ int num = -1; unsigned
·
2015-11-12 21:14
sizeof
[置顶] HDU 1754 线段树
string> #include<cstring> #include<algorithm> #include<cstdio> #include<
cmath
·
2015-11-12 21:10
HDU
几何模板总结——算法竞赛入门经典(第二版)
2 #include <string> 3 #include <cstdio> 4 #include <cstring> 5 #include <
cmath
·
2015-11-12 21:46
算法
hdu 3045 斜率优化DP
iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<
cmath
·
2015-11-12 21:09
HDU
hdu 4096 判断路径
#include<iostream> #include<cstdio> #include<cstring> #include<
cmath
> #include
·
2015-11-12 21:08
HDU
UVALive 6322 最大匹配
iostream> #include<algorithm> #include<cstring> #include<cstdio> #include<
cmath
·
2015-11-12 21:07
live
hdu 3874 树状数组
#include<iostream> #include<cstdio> #include<algorithm> #include<
cmath
> #
·
2015-11-12 21:06
树状数组
uvalive 6323 状态压缩DP
#include<iostream> #include<cstdio> #include<algorithm> #include<
cmath
> #
·
2015-11-12 21:06
live
hdu 3721 树的直径
iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<
cmath
·
2015-11-12 21:05
HDU
组队练习 2011年福州全国邀请赛
#include <string.h> #include <algorithm> #include <stdio.h> #include <
cmath
>
·
2015-11-12 21:03
POJ_1365_Prime_Land
//懒得解释 #include <iostream> #include <cstring> #include <
cmath
> #include <cstdio
·
2015-11-12 21:28
Prim
2013 ACM/ICPC Asia Regional Changsha Online - E
#include<cstring> 4 #include<algorithm> 5 #include<stdlib.h> 6 #include<
cmath
·
2015-11-12 21:34
online
1396 - Most Distant Point from the Sea
的点 求岛上某点离海最远的距离 解法: 不断的收缩多边形(求半平面交) 直到无限小 二分收缩的距离即可 如图 //大白p263 #include <
cmath
·
2015-11-12 21:42
ant
poj2015
<iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <
cmath
·
2015-11-12 21:50
poj
poj1320
<iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <
cmath
·
2015-11-12 21:49
poj
poj2472
<iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <
cmath
·
2015-11-12 21:43
poj
poj2603
<iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <
cmath
·
2015-11-12 21:38
poj
poj2101
<iostream>#include <cstdio>#include <cstdlib>#include <cstring>#include <
cmath
·
2015-11-12 21:35
poj
数据结构练习(32)n个骰子的点数
#include <iostream> #include <
cmath
> using namespace std; const int MAX_VALUE = 6;
·
2015-11-12 20:01
数据结构
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