hdu1877

HDU1877 又一版 A+B【进制】

又一版A+BTimeLimit:2000/1000MS(Java/Others)MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):17619AcceptedSubmission(s):6915ProblemDescription输入两个不超过整型定义的非负10进制整数A和B(voidreverse(chars[],intlen){int
海岛Blog·2020-09-13 00:37

hdu1877 又一版 A+B (栈)

E-又一版A+BCrawlinginprocess...CrawlingfailedTimeLimit:1000MSMemoryLimit:32768KB64bitIOFormat:%I64d&%I64uSubmitStatusPracticeHDU1877Appointdescription:SystemCrawler(2016-05-10)Description输入两个不超过整型定义的非负10
甄情·2020-09-13 00:31

hdu1877 又一版 A+B

#include#include#includeusingnamespacestd;intmain(){intA,B,m;chars[1005];while(cin>>m,m){cin>>A>>B;memset(s,0,sizeof(s));itoa(A+B,s,m);cout<
Flynn_curry·2020-09-13 00:12

HDU1877

#includeintrt(intc[],intn,intr){inti;for(i=0;n>=r;i++){c[i]=n%r;n=n/r;}c[i]=n;returni;}intmain(){inti,p,n,a,b;while(scanf("%d",&n),n!=0){intc[1000];scanf("%d%d",&a,&b);p=rt(c,a+b,n);for(i=p;i>=0;i--)p
Arthur-Ji·2020-08-13 11:59

关于已解决HDU题解链接

HDU1040AsEasyAsA+BHDU1062TextReverseHDU1094A+BforInput-OutputPractice(VI)HDU1228A+BHDU1720A+BComingHDU1870愚人节的礼物HDU1877
m0_38056893·2020-07-28 03:10

hdu1877 又一版 A+B (栈)

E-又一版A+BCrawlinginprocess...CrawlingfailedTimeLimit:1000MS    MemoryLimit:32768KB    64bitIOFormat:%I64d&%I64uSubmitStatusPracticeHDU1877Appointdescription:SystemCrawler(2016-05-10)Description输入两个不超过整
su20145104009·2016-05-11 10:00

训练赛总结

A（HDU1877）题目地址：http://acm.hdu.edu.cn/showproblem.php?
qq_25605637·2016-04-18 15:00

[置顶] C与C++中很少犯的错误，犯了后却很难找出的错误

1.continue，break类的错误（HDU1877）：#include usingnamespacestd; intmain() { inta,b,m,sum; while(cin>>m,m) {
huatian5·2016-04-05 21:00

hdu1877

#includeusingnamespacestd;longa,b,m;longs[20];//记录转化后的每一位voidchang(longn,longm){//转化函数 for(inti=0;i=0;i--)  cout>m>>a>>b&&m) {  chang(a+b,m); } return0;}
fangzhiyang·2012-02-06 09:00
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