Java 开发 Integer.parseInt 问题:java.lang.NumberFormatException: For input string...
Stringaddress="20:25:05:05:03:02";StringnumStr=address.replace(":","");intnum;try{num=Integer.parseInt(numStr,16);}catch(Exceptione){e.printStackTrace();num=0;}System.out.println(num);在Java开发中,执行上述代码,