phones

“即客”手机纽约横空问世 联想邀世界名人“齐响”乐PONHE

联想乐phoneS2的悄然上市，一时间成为所有人关注的焦点，而联想此次将新款手机与音乐会的巧妙联系，令大家感到新奇的同时，也看到了联想乐phoneS2这款新机的强大。  
康斯坦丁K·2011-11-24 16:12

POJ1195 Mobile phones, 二维树状数组

很典型的二维树状数组题，算是对优美的树状数组进行个总结吧/******************************************************************************* #Author:NeoFung #Email:[email protected] #Lastmodified:2011-11-0618:29 #Filename:POJ1195Mo
neofung·2011-11-06 18:00

将诺基亚N900手机(Maemo系统)中的通讯录导入安卓系统手机

手机(Maemo系统)中的通讯录导入安卓系统手机,步骤如下: 1:安装Nokia PC套件(非OVI,下载链接:http://nds1.nokia.com/files/support/global/phones
sgqt·2011-10-06 19:00

android ContentResolver 多表联合查询

         String[]projection=newString[]{         Phones.
墙头草·2011-09-20 10:00

HTC Sensation XE 10 月 1 日英国上市，Radar 也快来了

分类:智能手机虽然不知道大家对小升级和更改配色的SensationXE有甚么意见（个人就觉得颇讨好），但不管如何，看来港台将不会属于首发地区了--英国的零售商Phones4U已经宣布，将会在10月1日抢先独家推出这第一部
Danny Mak chas·2011-09-18 06:00

android ContentResolver 多表联合查询

  String [] projection= new String[]{ Phones.
zengyan2012·2011-09-05 09:00

android ContentResolver 多表联合查询

阅读更多String[]projection=newString[]{Phones.
zengyan2012·2011-09-05 09:00

Android读取联系人的姓名及号码

       ContentResolvercontentResolver=this.getContentResolver();       Cursorcursor=contentResolver.query(Phones.CONTENT
leilu2008·2011-07-28 15:00

poj-1195 Mobile phones *

/* 难得的1A题~~ 标准的树状数组 * 1195.cpp * 注意坐标从0开始， 应处理成从1开始 * Created on: 2011-7-11 * Author: */ #include < cstdio > using namespace std; const int MAXS = 1024 + 5 ; int map
·2011-07-11 15:00

ContentResolver.query的参数问题 按条件实现模糊查询

]selectionArgs,StringsortOrder) 第三个参数写成你想要的条件，第四个参数设为null.如：Cursorcursor=getContentResolver().query(Phones.CONTENT_URI
zhou699·2011-06-29 16:00

Android之使用ContentResolver对通信录中的数据进行简单操作

.加入读写权限联系人信息Uri：content://com.android.contacts/contacts联系人电话Uri：content://com.android.contacts/data/phones
isiqi·2011-06-09 16:00

Android之使用ContentResolver对通信录中的数据进行简单操作

.加入读写权限联系人信息Uri：content://com.android.contacts/contacts联系人电话Uri：content://com.android.contacts/data/phones
isiqi·2011-06-09 16:00

Android 获取联系人

在对联系人进行操作时需加入以下两个权限  引用content://com.android.contacts/contacts操作的数据是联系人信息Uricontent://com.android.contacts/data/phones
iaiai·2011-06-01 00:00

poj 1195 -- Mobile phones(2维树状数组)

MobilephonesTimeLimit:5000MSMemoryLimit:65536KTotalSubmissions:8215Accepted:3596DescriptionSupposethatthefourthgenerationmobilephonebasestationsintheTampereareaoperateasfollows.Theareaisdividedintosqu
zsc09_leaf·2011-04-24 16:00

sms格式的wappush

WAP Push SMS messages are widely used for pushing polyphonic ringtones and wallpaper images to mobile phones
isiqi·2011-04-05 11:00

poj 1195 Mobile phones

及其类似之前的那俩二维数组的题。 给你改变以及询问。。。啊。。。不解释了。。。不懂的看前俩二维的。。。 WA了好久，刚才看了小说，感觉好好~~~满惭愧的。。。恩。。。 后来发现函数的变量写错了，改了改就A掉了TT。。。 风好大哦。。。前两节我还是不去咧。。。 #include#include#include#include#include#include#include#include#inclu
zxy_snow·2011-03-24 13:00

Android联系人表结

com.android.providers.contactscddatabasescpcontacts.db/sdcard 拷贝到sdcard上，简单看以一下，里面主要的几张表，call，people，phones
ntop·2011-02-27 16:00

[JSR-184][3D编程指南]目录索引

tutorials for mobile devices using M3G (JSR 184) Sony Ericsson announced its first mobile Java 3D-enabled phones
univasity·2011-01-22 21:00

[JSR-184][3D编程指南]目录索引

tutorials for mobile devices using M3G (JSR 184) Sony Ericsson announced its first mobile Java 3D-enabled phones
univasity·2011-01-22 21:00

Samsung mobile phones- Smiling with the modern technology

Samsung mobile phones have brought a lot of handsets within the market.
sbguh·2011-01-04 13:00

Asterisk的SIP type和身份认证

If you want a user (extension) to have multiple phones,
jiagou·2010-12-31 16:00

Asterisk的SIP type和身份认证

If you want a user (extension) to have multiple phones,
javatoyou·2010-12-31 16:00

Asterisk的SIP type和身份认证

If you want a user (extension) to have multiple phones,
jiagou·2010-12-31 16:00

Asterisk SIP media path

In a normal SIP proxy, the server is not involved in the media between the phones.
javatoyou·2010-12-16 23:00

Asterisk SIP media path

In a normal SIP proxy, the server is not involved in the media between the phones.
jiagou·2010-12-16 23:00

Asterisk SIP media path

In a normal SIP proxy, the server is not involved in the media between the phones.
javahigh1·2010-12-16 23:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
javatoyou·2010-12-16 23:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
jiagou·2010-12-16 23:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
javahigh1·2010-12-16 23:00

Android 实现通话监听功能

在Android平台可以通过TelephonyManager和PhoneS
jiang_dlut·2010-12-01 09:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
jiagou·2010-11-22 13:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
javatoyou·2010-11-22 13:00

Asterisk Letting SIP clients connect directly

If you have two SIP phones, the media path can be connected directly be
javahigh1·2010-11-22 13:00

Asterisk SIP media path

Asterisk SIP media path In a normal SIP proxy, the server is not involved in the media between the phones
jiagou·2010-11-13 22:00

Asterisk SIP media path

Asterisk SIP media path In a normal SIP proxy, the server is not involved in the media between the phones
javatoyou·2010-11-13 22:00

MySQL custom ringtones

Cisco phones ). You must place
jiagou·2010-11-13 22:00

MySQL custom ringtones

Cisco phones ). You must place
javatoyou·2010-11-13 22:00

poj1195Mobile phones（二维树状数组）

题意：给一个二维矩阵，边修改点格的手机的改变数目，边查询区间手机的总数目。分析：就是Matrix的相反操作。CPP代码：#include #include using namespace std;int n;int c[1030][1030];int Lowbit(int i){    return i&(-i);}void up(int x,int y,int a){    int i = x,
acronix·2010-10-29 15:00

ContentProvider抓取通讯录数据

旧版本的写法: import android.provider.Contacts; Cursor c = getContentResolver().query(Contacts.Phones.CONTENT_URI
edison_cool911·2010-10-28 14:00

Get CellId and other Imformation from mobile phones via J2ME

原文出处：http://www.easywms.com/easywms/?q=zh-hant/node/3589   Without GPS or Network Operator we can still use the Location Based Service, via the help of CellId(Cell ID the location of Cell Iden
jackle_liu·2010-10-18 14:00

Get CellId and other Imformation from mobile phones via J2ME

阅读更多原文出处：http://www.easywms.com/easywms/?q=zh-hant/node/3589WithoutGPSorNetworkOperatorwecanstillusetheLocationBasedService,viathehelpofCellId(CellIDthelocationofCellIdentitiesofGSM-networks).Googleha
jackle_liu·2010-10-18 14:00

-------------Mobile phones---------树状数组

Mobilephoneshttp://acm.pku.edu.cn/JudgeOnline/problem?id=1195TimeLimit:5000MS MemoryLimit:65536KTotalSubmissions:7178 Accepted:3075DescriptionSupposethatthefourthgenerationmobilephonebasestationsinthe
includeiostream123·2010-09-03 21:00

poj 1195 Mobile phones 二维树状数组

poj1195Mobilephones二维树状数组MobilephonesTimeLimit:5000MSMemoryLimit:65536KTotalSubmissions:7087Accepted:3030DescriptionSupposethatthefourthgenerationmobilephonebasestationsintheTampereareaoperateasfollow
生若有余·2010-08-27 16:00

POJ 1195 Mobile phones【二维树状数组】

    简单的二维树状数组，求一个矩形区域内的和，因为要随时增减，而且可能减的数比原来都大，所以需要保留原来的数组。在求矩形区域和的时候，只要用最大的矩形减去两个小的，再加上那个多减的最小的，就OK了. #include#defineM1300intc[M][M],a[M][M],n;intlowbit(intt){returnt&(t^(t-1));}intsum(intp,intq){intx
ji414341055·2010-07-24 01:00

How to install apk files on your google android phone(zz).

At least 20 new Android based phones are expected in the next year alone.
alian·2010-05-17 10:00

Displaying GIF Images on J2ME Mobile Phones

DisplayingGIFImagesonJ2MEMobilePhonesWithsomephones,youhavetorollyourownGIFdecoderTomThompsonSurprisingly,manyJava-basedmobilephonescouldn'tdisplayGIFimagefiles--untilnow.Tomisatechnicalwriterprovidin
kenera·2010-05-12 16:00

The Relationships Between Classes in Symbian OS C++ for Mobile Phones Volume 3

Asyou’dexpect,classesareusedtorepresentobjects,abstractionsandinterfaces.Relationshipsbetweenclassesareusedtorepresentrelationshipsbetweenobjectsorabstractions.Themostimportantrelationshipsbetweenclas
wxlkeepmoving·2010-05-06 17:00

POJ.1195 Mobile phones【二维树状数组】

POJ.1195Mobilephones【二维树状数组】简单的二维树状数组，求一个矩形区域内的和，因为要随时增减，而且可能减的数比原来都大，所以需要保留原来的数组。在求矩形区域和的时候，只要用最大的矩形减去两个小的，再加上那个多减的最小的，就OK了。1y~~Code： 1 #include 2 #define M 1300 3 int c[M][M],a[M][M],n; 4 int lowbit
M.J的blog·2010-05-03 17:00

Path Intelligence -- Tracking your customers through locating mobile phones whilst indoors.

PathIntelligence http://www.pathintelligence.com/website-aboutus.htm  PathIntelligencehasdevelopedaproprietary,patent-pending,newtechnologythatisabletoaccuratelylocatemobilephoneswhilstindoors.Ourtech
zjnig711·2010-04-23 04:00

Professional Android 2 Development - 0

Mobile phones have never been more popular, and powerful smartphones are now a popular choice for consumers
tangleway·2010-04-22 14:00
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