Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 3339 | Accepted: 1462 |
Description
Input
Output
Sample Input
2 1 Ted Bill 25 4 Ray James 40 James Beelzebub 17 Ray Mark 75 Ted Ray 20
Sample Output
DATASET 1 Bill 75 DATASET 2 Ray 80 James 40 Beelzebub 23 Mark 5
题目大意:Ted近年100岁,给出n行,每行有两个字符串和一个数字,第一个字符串为父亲的名字,后面为儿子的名字以及父亲比儿子大多少岁,输出整个家族中除了Ted之外所有人的年龄,按年龄从大到小输出,如果年龄相同,则按照名字字典序从小到大输出。
#include <stdio.h> #include <string> #include <map> #include <algorithm> #include <vector> #include <iostream> #include <queue> using namespace std; typedef struct { int age; string name; }Person; //父亲和儿子名字键值对 multimap<string, string> father_son; //儿子和儿子年龄键值对 map<string, int> son_age; //儿子和儿子比父亲少多少岁键值对 map<string, int> person_toage; //家族中每个成员 vector<Person> Family; bool cmp(const Person &p1, const Person &p2) { if (p1.age == p2.age) { return p1.name < p2.name; } else { return p1.age > p2.age; } } //用BFS遍历得出家族中每个人的年龄 void BFS() { queue<pair<string, int> > Queue; Queue.push(make_pair("Ted", 100)); while(!Queue.empty()) { pair<string, int> p = Queue.front(); Queue.pop(); int nCount = father_son.count(p.first); if (nCount != 0) { //遍历父亲的所有儿子 multimap<string, string>::iterator iter; for (iter = father_son.lower_bound(p.first); iter != father_son.upper_bound(p.first); iter++) { //儿子的年龄等于父亲的年龄减去父子年龄之差 son_age[iter->second] = p.second - person_toage[iter->second]; Person temp; temp.name = iter->second; temp.age = son_age[iter->second]; Family.push_back(temp); //将当前儿子入队,作为后序的父亲 Queue.push(make_pair(iter->second, son_age[iter->second])); } } } } int main() { int nCase, n, age, nDataset = 0; string father, son; cin>>nCase; while(nCase--) { cin>>n; father_son.clear(); son_age.clear(); person_toage.clear(); Family.clear(); son_age.insert(make_pair("Ted", 100)); ++nDataset; for (int i = 0; i < n; i++) { cin>>father>>son>>age; father_son.insert(make_pair(father, son)); person_toage.insert(make_pair(son, age)); } BFS(); sort(Family.begin(), Family.end(), cmp); cout<<"DATASET "<<nDataset<<endl; for (vector<Person>::iterator iter = Family.begin(); iter != Family.end(); iter++) { cout<<iter->name<<" "<<iter->age<<endl; } } return 0; }