C语言实现统计字符个数

#include<stdio.h>
int main()
{
    int sz[10]={0},zm[26]={0},z[26]={0},i,space=0,e=0,t=0;
    char c;
    printf ( "请输入一段字符，统计其中各字符的数量\n" );
    while ((c= getchar ())!= '\n' )
    {
        if (c<= 'z' &&c>= 'a' )
            zm[c- 'a' ]++;
        else if (c<= 'Z' &&c>= 'A' )
            z[c- 'A' ]++;
        else if (c<= '9' &&c>= '0' )
            sz[c- '0' ]++;
        else if (c== ' ' )
            space++;
        else
            e++;
    }
    printf ( "\n\n" );
    for (i=0;i<=9;i++)
    {
        t++;
        printf ( " %d的个数为%d   " ,i,sz[i]);
        if (t%3==0)
            printf ( "\n" );
    }
    t=0;
    printf ( "\n\n\n" );
    for (i=0;i<=25;i++)
    {
        t++;
        printf ( " %c的个数为%d   " ,i+97,zm[i]);
        if (t%3==0)
            printf ( "\n" );
    }
    t=0;
    printf ( "\n\n\n" );
    for (i=0;i<=25;i++)
    {
        t++;
        printf ( " %c的个数为%d   " ,i+65,z[i]);
        if (t%3==0)
            printf ( "\n" );
    }
    t=0;
    printf ( "\n\n\n" );
    printf ( " 空格的个数为%d\n\n" ,space);
    printf ( " 其他字符的个数为%d\n" ,e);
    return 0;
}