Practice 1:
输入一个正整数n,求1+2+3+......+n的和。
#include
#include
int main()
{
int i,n,sum;
printf("Enter n:");
scanf("%d",&n);
sum=0;
for(i=1;i<=n;i++)
{
sum=sum+i;
}
printf("Sum of numbers from 1 to %d is %d\n",n,sum);
return 0;
}
Practice 2:
输入一个正整数n,求1-1/3+1/5-1/7+......共n项之和。
#include
#include
int main(void)
{
int denominator,flag,i,n;
double item,sum;
printf("Enter n:");
scanf("%d",&n);
flag=1;
denominator=1;
sum=0;
for(i=1;i<=n;i++)
{
item=flag*1.0/denominator;
sum=sum+item;
flag=-flag;
denominator=denominator+2;
}
printf("sum=%f\n",sum);
return 0;
}
从键盘输入一个正整数,计算n!。
#include
#include
int main(void)
{
int sum=1,i,n;
printf("Enter n:");
scanf("%d",&n);
for(i=n;i>=1;i--)
{
sum=sum*i;
}
printf("sum的值为%d",sum);
return 0;
}
简单的猜数游戏。输入你所猜的整数(假定1~100内),与计算机产生的被猜数比较。若相等;显示猜中,显示与被猜数的大小关系。
#include
#include
int main(void)
{
int mynumber=38;
int yournumber;
printf("Input your number:");
scanf("%d",&yournumber);
if(yournumber==mynumber)
{
printf("OK!you are right!\n");
}
else
if(yournumber>mynumber)
printf("Sorry!your number is bigger than my number!\n");
else
printf("Sorry!your number is smaller than my number!\n");
return 0;
}
输入一个正整数n,再输入n个学生的成绩,计算平均分,并统计不及格成绩的学生人数。
#include
#include
int main()
{
int count,i,n;
double grade,total;
printf("Enter n:");
scanf("%d",&n);
total=0;
count=0;
for(i=1;i<=n;i++){
printf("Enter grade#%d:",i);
scanf("%lf",&grade);
total=total+grade;
if(grade<60){
count++;
}
}
printf("Grade average=%.2f\n",total/n);
printf("Number of failures=%d\n",count);
return 0;
}
求解简单的四则运算表达式,输入一个形式如“操作数 运算符 操作数”的四则运算表达式,输出运算结果。
#include
#include
int main()
{
double value1,value2;
char op;
printf("Type in an expression:");
scanf("%lf%c%lf",&value1,&op,&value2);
if(op=='+')
printf("=%.2f\n",value1+value2);
else if(op=='-')
printf("=%.2f\n",value1-value2);
else if(op=='*')
printf("=%.2f\n",value1*value2);
else if(op=='/')
printf("=%.2f\n",value1/value2);
else printf("Unknown operator\n");
return 0;
}
输入10个字符,统计其中英文字母、数字字符和其他字符的个数。
#include
#include
int main()
{
int digit,letter,other;
char ch;
int i;
digit=letter=other=0;
printf("Enter 10 characters:");
for(i=1;i<=10;i++)
{
ch=getchar();
if((ch>='a'&&ch<='z')||(ch>='A'&&ch<='Z'))
letter++;
else if(ch>='0'&&ch<='9')
digit++;
else other++;
}
printf("letter=%d,digit=%d,other=%d\n",letter,digit,other);
return 0;
}
practice 8:
求解简单表达式。输入一个形式如“操作数 运算符 操作数”的四则运算表达式,输出运算结果,要求使用switch语句编写。
#include
#include
int main()
{
double value1,value2;
char op;
printf("Type in an expression:");
scanf("%lf%c%lf",&value1,&op,&value2);
switch(op){
case '+':
printf("=%.2f\n",value1+value2);
break;
case '-':
printf("=%.2f\n",value1-value2);
break;
case '*':
printf("=%.2f\n",value1*value2);
break;
case '/':
printf("=%.2f\n",value1/value2);
break;
default:
printf("Unknown operation\n");
break;
}
return 0;
}
practice 9: