杭电 2057 A + B Again【十六进制】【三目运算符】

A + B Again

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 23035    Accepted Submission(s): 9990

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A +1A 12 1A -9 -1A -12 1A -AA

 

Sample Output

0 2C 11 -2C -90

【不好意思复制粘贴了。。。】
#include int main(){ __int64 a,b; // 由于定义的数字最多有16位长度，所以定义为int64 while(scanf( " %I64X%I64X ",&a,&b)!= EOF) printf(a+b>= 0? " %I64X\n ": " -%I64X\n ",a+b> 0?a+b:-a-b); // 完全是考察输出格式的为题，三目运算符的绝佳运用。。 return 0 ;}