1. 查找最晚入职员工的所有信息
查找最晚入职员工的所有信息
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
无
emp_no | birth_date | first_name | last_name | gender | hire_date |
---|---|---|---|---|---|
10008 | 1958-02-19 | Saniya | Kalloufi | M | 1994-09-15 |
select *
from employees
order by hire_date desc limit 0,1
2. 查找入职员工时间排名倒数第三的员工所有信息
查找入职员工时间排名倒数第三的员工所有信息
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
无
emp_no | birth_date | first_name | last_name | gender | hire_date |
---|---|---|---|---|---|
10005 | 1955-01-21 | Kyoichi | Maliniak | M | 1989-09-12 |
select *
from employees
order by hire_date desc limit 2,1
3. 查找当前薪水详情以及部门编号dept_no
查找各个部门当前(to_date='9999-01-01')领导当前薪水详情以及其对应部门编号dept_no
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
无
emp_no | salary | from_date | to_date | dept_no |
---|---|---|---|---|
10002 | 72527 | 2001-08-02 | 9999-01-01 | d001 |
10004 | 74057 | 2001-11-27 | 9999-01-01 | d004 |
10005 | 94692 | 2001-09-09 | 9999-01-01 | d003 |
10006 | 43311 | 2001-08-02 | 9999-01-01 | d002 |
10010 | 94409 | 2001-11-23 | 9999-01-01 | d006 |
select s.*, d.dept_no
from salaries as s, dept_manager as d
where s.to_date = '9999-01-01'
and d.to_date = '9999-01-01'
and s.emp_no = d.emp_no
4. 查找所有已经分配部门的员工的last_name和first_name
查找所有已经分配部门的员工的last_name和first_name
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
无
last_name | first_name | dept_no |
---|---|---|
Facello | Georgi | d001 |
省略 | 省略 | 省略 |
Piveteau | Duangkaew | d006 |
select e.last_name, e.first_name, d.dept_no
from employees as e, dept_emp as d
where d.emp_no = e.emp_no
5. 查找所有员工的last_name和first_name以及对应部门编号dept_no
查找所有员工的last_name和first_name以及对应部门编号dept_no,也包括展示没有分配具体部门的员工
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
无
last_name | first_name | dept_no |
---|---|---|
Facello | Georgi | d001 |
省略 | 省略 | 省略 |
Sluis | Mary | NULL(在sqlite中此处为空,MySQL为NULL) |
select e.last_name,e.first_name,d.dept_no
from employees as e
left join dept_emp as d
on e.emp_no = d.emp_no
6. 查找所有员工入职时候的薪水情况
查找所有员工入职时候的薪水情况,给出emp_no以及salary, 并按照emp_no进行逆序
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
无
emp_no | salary |
---|---|
10011 | 25828 |
省略 | 省略 |
10001 | 60117 |
select e.emp_no, s.salary
from employees e, salaries s
where e.emp_no = s.emp_no
and e.hire_date = s.from_date
order by e.emp_no desc
7. 查找薪水涨幅超过15次的员工号emp_no以及其对应的涨幅次数t
查找薪水涨幅超过15次的员工号emp_no以及其对应的涨幅次数t
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
无
emp_no | t |
---|---|
10001 | 17 |
10004 | 16 |
10009 | 18 |
select emp_no, count(emp_no) as t
from salaries
group by emp_no
having t > 15
8. 找出所有员工当前薪水salary情况
找出所有员工当前(to_date='9999-01-01')具体的薪水salary情况,对于相同的薪水只显示一次,并按照逆序显示
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
无
salary |
---|
94692 |
94409 |
88958 |
88070 |
74057 |
72527 |
59755 |
43311 |
25828 |
select distinct salary
from salaries
where to_date = "9999-01-01"
order by salary desc
9. 获取所有部门当前manager的当前薪水情况,给出dept_no, emp_no以及salary,当前表示to_date='9999-01-01'
获取所有部门当前manager的当前薪水情况,给出dept_no, emp_no以及salary,当前表示to_date='9999-01-01'
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
无
dept_no | emp_no | salary |
---|---|---|
d001 | 10002 | 72527 |
d004 | 10004 | 74057 |
d003 | 10005 | 94692 |
d002 | 10006 | 43311 |
d006 | 10010 | 94409 |
select d.dept_no, d.emp_no, s.salary
from salaries as s
join dept_manager as d
on d.emp_no = s.emp_no
where d.to_date = '9999-01-01'
and s.to_date = '9999-01-01'
select d.dept_no, d.emp_no, s.salary
from salaries as s, dept_manager as d
where d.to_date = '9999-01-01'
and s.to_date = '9999-01-01'
and d.emp_no = s.emp_no
10. 获取所有非manager的员工emp_no
获取所有非manager的员工emp_no
CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
无
emp_no |
---|
10001 |
10003 |
10007 |
10008 |
10009 |
10011 |
select emp_no
from employees
where emp_no not in (select emp_no from dept_manager)