HDU 5754 Life Winner Bo （博弈组合，思维）

Life Winner Bo

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 3009    Accepted Submission(s): 1093

Problem Description

Bo is a "Life Winner".He likes playing chessboard games with his girlfriend G.

The size of the chessboard is  N×M.The top left corner is numbered (1,1) and the lower right corner is numberd  (N,M).

For each game,Bo and G take turns moving a chesspiece(Bo first).At first,the chesspiece is located at  (1,1).And the winner is the person who first moves the chesspiece to  (N,M).At one point,if the chess can't be moved and it isn't located at  (N,M),they end in a draw.

In general,the chesspiece can only be moved right or down.Formally,suppose it is located at  (x,y),it can be moved to the next point  (x′,y′) only if  x′≥x and  y′≥y.Also it can't be moved to the outside of chessboard.

Besides,There are four kinds of chess(They have movement rules respectively).

1.king.

2.rook(castle).

3.knight.

4.queen.

(The movement rule is as same as the chess.)

For each type of chess,you should find out that who will win the game if they both play in an optimal strategy.

Print the winner's name("B" or "G") or "D" if nobody wins the game.

 

Input

In the first line,there is a number  T as a case number.

In the next  T lines,there are three numbers type, N and  M.

"type" means the kind of the chess.

T≤1000,2≤N,M≤1000,1≤type≤4

 

Output

For each question,print the answer.

 

Sample Input

41 5 52 5 53 5 54 5 5

 

Sample Output

GGDB

 

根据棋子的不同一共有四种博弈

前三种的np图

#include 
#include 
#include 
#include 
#include
#define ans (sqrt(5)+1)/2
using namespace std;
int main(int argc, char *argv[])
{
	int t;
	scanf("%d",&t);
	while(t--)
	{
		int s,m,n;
		scanf("%d %d %d",&s,&n,&m);
		if(s==1)
		{
			if(n%2==0||m%2==0)
			{
				printf("B\n");
			}
			else
			{
				printf("G\n");
			}
		}
		if(s==2)  
        {  
            if(n==m)  
                printf("G\n");  
            else  
                printf("B\n");  
        }  
		  if(s==3)
        {
           n--;
           m--;
           if(n>m)
           {
		   	swap(n,m);
		   }
		   
		   if(n==m&&n%3==0)
           {
		   	printf("G\n");
		   }
		   else if(m%3==2&&m-n==1)
		   {
		   	printf("B\n");
		   }
		   else
 			{
				printf("D\n");
			}
        }
		if(s==4)
		{
			m--;
			n--;
			if(n