I/O、内存、网络性能优化命令 iostat , vmstat,netstat

原贴:http://www.cndw.com/tech/server/2006040430550.asp

是在sun网站上看到的,原文是e文,连接如下:
http://www.adminschoice.com/docs/iostat_vmstat_netstat.htm

大概翻译了一下,总觉得好像以前哪位大大贴过类似的
不管了,觉得有点用,大家一起看看
翻译得不好,见笑了……如果有错,请指正哦,先谢了

Input Output statistics ( iostat )

iostat反映了终端、磁盘I/O情况和CPU活动。输出结果的第一行是从系统启动到现在为止的这段时间的结果,接下去的每一行是interval时

间段内的结果。Kernel里有一组计数器用来跟踪这些值。
iostat的默认参数是tdc(terminal, disk, and CPU)。如果任何其他的选项被指定,这个默认参数将被完全替代,例如,iostat -d将只反

映磁盘的统计结果。

语法:

基本语法: iostat interval count

option - 让你指定所需信息的设备,像磁盘、cpu或者终端(-d , -c , -t or -tdc ) 。x 选项给出了完整的统计结果(gives the extended

statistic)。

interval - 在两个samples之间的时间(秒)。

count - 就是需要统计几次

例子:

$ iostat -xtc 5 2
extended disk statistics tty cpu
disk r/s w/s Kr/s Kw/s wait actv svc_t %w %b tin tout us sy wt id
sd0 2.6 3.0 20.7 22.7 0.1 0.2 59.2 6 19 0 84 3 85 11 0
sd1 4.2 1.0 33.5 8.0 0.0 0.2 47.2 2 23
sd2 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0 0
sd3 10.2 1.6 51.4 12.8 0.1 0.3 31.2 3 31


The fields have the following meanings:

disk name of the disk
r/s reads per second
w/s writes per second
Kr/s kilobytes read per second
Kw/s kilobytes written per second
wait average number of transactions waiting for service (Q length)
actv average number of transactions actively
being serviced (removed from the
queue but not yet
completed)
%w percent of time there are transactions waiting
for service (queue non-empty)
%b percent of time the disk is busy (transactions
in progress)




Results and Solutions:

从iostat输出结果中需要注意的值:

Reads/writes per second (r/s , w/s)
Percentage busy (%b)
Service time (svc_t)

如果磁盘显示长时间的高reads/writes,并且磁盘的percentage busy (%b)也远大于5%,同时average service time (svc_t)也远大于30

milliseconds,这以下的措施需要被执行:
1.)调整应用,令其使用磁盘i/o更加有效率,可以通过修改磁盘队列、使用应用服务器的cache

2.)将文件系统分布到2个或多个磁盘上,并使用volume manager/disksuite的条带化特点

3.) 增加系统参数值,如inode cache , ufs_ninode。Increase the system parameter values for inode cache , ufs_ninode , which

is Number of inodes to be held in memory. Inodes are cached globally (for UFS), not on a per-file system basis

4.) 将文件系统移到更快的磁盘/控制器,或者用更好的设备来代替

还有两段等会翻好了再贴……

Virtual Memory Statistics ( vmstat )

vmstat - vmstat反映了进程的虚拟内存、虚拟内存、磁盘、trap(是不是翻译成中断??)和cpu的活动情况

在多cpu系统中,vmstat在输出结果中平均了cpu数量。For per-process statistics .如果没有选项,vmstat显示一行虚拟内存活动的概要

结果,是从系统启动时开始的。

语法:

vmstat interval count

option - 让你指定所需的信息类型,例如 paging -p , cache -c ,.interrupt -i etc.

如果没有指定选项,将会显示进程、内存、页、磁盘、中断和cpu信息

interval - 同iostat

count - 同iostat

例子
The following command displays a summary of what the system
is doing every five seconds.

example% vmstat 5
procs memory page disk faults cpu
r b w swap free re mf pi p fr de sr s0 s1 s2 s3 in sy cs us sy id
0 0 0 11456 4120 1 41 19 1 3 0 2 0 4 0 0 48 112 130 4 14 82
0 0 1 10132 4280 0 4 44 0 0 0 0 0 23 0 0 211 230 144 3 35 62
0 0 1 10132 4616 0 0 20 0 0 0 0 0 19 0 0 150 172 146 3 33 64
0 0 1 10132 5292 0 0 9 0 0 0 0 0 21 0 0 165 105 130 1 21 78




The fields of vmstat's display are
procs
r in run queue
b blocked for resources I/O, paging etc.
w swapped

memory (in Kbytes)
swap - amount of swap space currently available
free - size of the free list

page ( in units per second).
re page reclaims - see -S option for how this field is modified.
mf minor faults - see -S option for how this field is modified.
pi kilobytes paged in
po kilobytes paged out
fr kilobytes freed
de anticipated short-term memory shortfall (Kbytes)
sr pages scanned by clock algorithm

disk ( operations per second )
There are slots for up to four disks, labeled with a single letter and number.
The letter indicates the type of disk (s = SCSI, i = IPI, etc) . The number is
the logical unit number.

faults
in (non clock) device interrupts
sy system calls
cs CPU context switches

cpu - breakdown of percentage usage of CPU time. On multiprocessors this is an a
verage across all processors.
us user time
sy system time
id idle time

结果和解决方案:

A. CPU issues:

下面几列需要被察看,以确定cpu是否有问题

Processes in the run queue (procs r)
User time (cpu us)
System time (cpu sy)
Idle time (cpu id)
procs cpu
r b w us sy id
0 0 0 4 14 82
0 0 1 3 35 62
0 0 1 3 33 64
0 0 1 1 21 78



问题情况:
1.) 如果processes in run queue (procs r)的数量远大于系统中cpu的数量,将会使系统便慢。
2.) 如果这个数量是cpu的4倍的话,说明系统正面临cpu能力短缺,这将使系统运行速度大幅度降低
3.) 如果cpu的idle时间经常为0的话,或者系统占用时间(cpu sy)是用户占用时间(cpu us)两辈的话,系统面临缺少cpu资源

解决方案 :
解决这些情况,涉及到调整应用程序,使其能更有效的使用cpu,同时增加cpu的能力或数量。

B. Memory Issues:
内存的瓶颈取决于scan rate (sr) 。scan rate是每秒时钟对页的扫描 (he scan rate is the pages scanned by the clock algorithm per

second.)如果 scan rate (sr)一直大于200 pages每秒,这时就是内存短缺的现实。

解决方案 :
1. 调整应用和服务器,使其能更好的使用memory和cache
2. 增加系统内存
3. Implement priority paging in s in pre solaris 8 versions by adding line "set priority paging=1" in
/etc/system. Remove this line if upgrading from Solaris 7 to 8 & retaining old /etc/system file.

Network Statistics (netstat)

netstat通过选项来显示不通的网络相关的数据结构(netstat displays the contents of various network-related data structures

in depending on the options selected.)

语法 :

netstat

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