PAT-中国大学MOOC-陈越、何钦铭-数据结构基础习题集 00-自测5. Shuffling Machine (20) （简单模拟）【二星级】
题目链接：http://www.patest.cn/contests/mooc-ds/00-%E8%87%AA%E6%B5%8B5
题面：
00-自测5. Shuffling Machine (20)
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employautomatic shuffling machines. Your task is to simulate a shuffling machine.
The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:
S1, S2, ..., S13, H1, H2, ..., H13, C1, C2, ..., C13, D1, D2, ..., D13, J1, J2
where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer K (<= 20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.
Sample Input:2 36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47Sample Output:
S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5
题目大意：
原牌顺序是1-54，给定一个位置映射关系，问k次操作后，最后每个位置分别是哪张牌。
解题：
并不是真正的洗牌，只要记录下映射关系，开一个新数组，存下来，再赋值回去。操作k次后，最后输出即可。
代码：
#include
#include
#include
#include
using namespace std;
//pos_card下标为位置，内部存储值为牌的代号，oper记录操作，tmp临时存储
int pos_card[55],oper[55],tmp[55];
//输出打印函数
void print(int x)
{
if(x<=13)
cout<<"S"<>k;
//初始化
for(int i=1;i<=54;i++)
pos_card[i]=i;
//操作序列
for(int i=1;i<=54;i++)
cin>>oper[i];
//循环k次
for(int i=1;i<=k;i++)
{
for(int j=1;j<=54;j++)
tmp[oper[j]]=pos_card[j];
for(int j=1;j<=54;j++)
pos_card[j]=tmp[j];
}
//第一个特殊输出
print(pos_card[1]);
for(int i=2;i<=54;i++)
{
cout<<" ";
print(pos_card[i]);
}
cout<