求模逆元算法的C/C++实现

#include 
/*
  Name:  
  Copyright: 
  Author: @dujianjian
  Date: 01/11/12 11:26
  Description: 递归 
*/

//三元组gcd(a,b) == ax +by == d; 
 struct gcdstruct{  
        int d;
        int x;
        int y;
        };
gcdstruct EXTENDED_EUCLID(int a,int b)
{
    gcdstruct aa,bb;
    if(b==0){
             aa.d = a;
             aa.x = 1;
             aa.y = 0;
             return aa;
            }
    else{
         bb = EXTENDED_EUCLID(b,a%b); 
         aa.d = bb.d;
         aa.x = bb.y;
         aa.y = bb.x - bb.y * (a/b);
         }
    return aa;
    } 
    
 /*
  Name: 
  Copyright: 
  Author: @dujianjian
  Date: 01/11/12 20:33
  Description: 
               ax == 1 (mod m),求x 
*/
   
    
 long inverse(long a,long m)
 {
      long x;
      gcdstruct aa;
      aa = EXTENDED_EUCLID(a,m);
      return aa.x;
      
      }   
  int main(){
      int a,m;
      a = 3;
      m = 11;
      printf("a = %d,m = %d,x = %d\n",a,m,inverse(a,m));
      getchar();
      return 0;
      }  

示例结果：