PAT 乙级 1081. 检查密码 (15) 【字符串】

题目链接

https://www.patest.cn/contests/pat-b-practise/1081

思路
有一个坑点 可能会输入空格 也就是说 要用 geline 或者 gets()

然后 对于
“………………….” 这种 一串小数点的数据 应该输出什么 我也不知道。。
应该是没有这种数据吧

AC代码

#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 

#define CLR(a) memset(a, 0, sizeof(a))
#define pb push_back

using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair <int, int> pii;
typedef pair  pll;

const double PI  = 3.14159265358979323846264338327;
const double E   = exp(1);
const double eps = 1e-6;

const int INF  = 0x3f3f3f3f;
const int maxn = 1e5 + 5;
const int MOD  = 1e9 + 7;

int legal(string s)
{
    int len = s.size();
    int a = 0, b = 0, c = 0;
    for (int i = 0; i < len; i++)
    {
        if (s[i] >= '0' && s[i] <= '9' ) 
        {
            a = 2;
            continue;
        }
        else if ((s[i] >= 'a' && s[i] <= 'z') || (s[i] >= 'A' && s[i] <= 'Z'))
        {
            b = 3;
            continue;
        }
        else if (s[i] == '.')
            continue;
        else
            return 0;
    }       
    return a + b;
}

int main()
{
    int t;
    cin >> t;
    getchar();
    while (t--)
    {
        string s;
        getline(cin, s);
        int len = s.size();
        if (len < 6)
            printf("Your password is tai duan le.\n");
        else
        {
            int ans = legal(s);
            if (ans == 0)
                printf("Your password is tai luan le.\n");
            else if (ans == 2)
                printf("Your password needs zi mu.\n");
            else if (ans == 3)
                printf("Your password needs shu zi.\n");
            else
                printf("Your password is wan mei.\n");
        }   
    }   
}