MATLAB写的LBM管道小球例子

%%%这个程序是有问题的。也就是借鉴一下，用的话需要自己改！！！

%%还是老样子, QQ群：293267908。

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% cylinder.m: Channel flow past a cylinderical        
%             obstacle, using a LB method            
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Lattice Boltzmann sample, written in C
% Copyright (C) 2006 Jonas Latt
% Address: Rue General Dufour 24,  1211 Geneva 4, Switzerland
% E-mail: [email protected]
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% This program is free software; you can redistribute it and/or
% modify it under the terms of the GNU General Public License
% as published by the Free Software Foundation; either version 2
% of the License, or (at your option) any later version.
% This program is distributed in the hope that it will be useful,
% but WITHOUT ANY WARRANTY; without even the implied warranty of
% MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
% GNU General Public License for more details.
% You should have received a copy of the GNU General Public
% License along with this program; if not, write to the Free
% Software Foundation, Inc., 51 Franklin Street, Fifth Floor,
% Boston, MA  02110-1301, USA.
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

clear

% GENERAL FLOW CONSTANTS
lx         = 250;
ly         = 51;
obst_x = lx/5+1;   % position of the cylinder; (exact
obst_y = ly/2+1;   % y-symmetry is avoided)
obst_r = ly/10+1;  % radius of the cylinder
uMax  = 0.02;      % maximum velocity of Poiseuille inflow
Re     = 100;      % Reynolds number
nu    = uMax * 2.*obst_r / Re;   % kinematic viscosity
omega  = 1. / (3*nu+1./2.);      % relaxation parameter
maxT   = 1000;   % total number of iterations
tPlot  = 5;        % cycles

% D2Q9 LATTICE CONSTANTS
t  = [4/9, 1/9,1/9,1/9,1/9, 1/36,1/36,1/36,1/36];
cx = [  0,   1,  0, -1,  0,    1,  -1,  -1,   1];
cy = [  0,   0,  1,  0, -1,    1,   1,  -1,  -1];
opp = [ 1,   4,  5,  2,  3,    8,   9,   6,   7];
col = [2:(ly-1)];

[y,x] = meshgrid(1:ly,1:lx);
obst = (x-obst_x).^2 + (y-obst_y).^2 <= obst_r.^2;
obst(:,[1,ly]) = 1;
bbRegion = find(obst);

% INITIAL CONDITION: (rho=0, u=0) ==> fIn(i) = t(i)
fIn = reshape( t' * ones(1,lx*ly), 9, lx, ly);

% MAIN LOOP (TIME CYCLES)
for cycle = 1:maxT

    % MACROSCOPIC VARIABLES
    rho = sum(fIn);
    ux  = reshape ( ...
          (cx * reshape(fIn,9,lx*ly)), 1,lx,ly) ./rho;
    uy  = reshape ( ...
          (cy * reshape(fIn,9,lx*ly)), 1,lx,ly) ./rho;
      
    % MACROSCOPIC (DIRICHLET) BOUNDARY CONDITIONS
      % Inlet: Poiseuille profile
    L = ly-2; y = col-1.5;
    ux(:,1,col) = 4 * uMax / (L*L) * (y.*L-y.*y);
    uy(:,1,col) = 0;
    rho(:,1,col) = 1 ./ (1-ux(:,1,col)) .* ( ...
        sum(fIn([1,3,5],1,col)) + ...
        2*sum(fIn([4,7,8],1,col)) );
      % Outlet: Zero gradient on rho/ux
    rho(:,lx,col) = 4/3*rho(:,lx-1,col) - ...
                    1/3*rho(:,lx-2,col);
    uy(:,lx,col)  = 0;
    ux(:,lx,col)  = 4/3*ux(:,lx-1,col) - ...
                    1/3*ux(:,lx-2,col);

    % COLLISION STEP
    for i=1:9
       cu = 3*(cx(i)*ux+cy(i)*uy);
       fEq(i,:,:)  = rho .* t(i) .* ...
         ( 1 + cu + 1/2*(cu.*cu) ...
              - 3/2*(ux.^2+uy.^2) );
       fOut(i,:,:) = fIn(i,:,:) - ...
         omega .* (fIn(i,:,:)-fEq(i,:,:));
    end

    % MICROSCOPIC BOUNDARY CONDITIONS%入口定压，出口封闭
    for i=1:9
         % Left boundary
         fOut(i,1,col) = fEq(i,1,col) + 18*t(i)*cx(i)*cy(i)* ( fIn(8,1,col) -fIn(7,1,col)-fEq(8,1,col)+fEq(7,1,col) );
         % Right boundary
         fOut(i,lx,col) = fEq(i,lx,col) + 18*t(i)*cx(i)*cy(i)* ( fIn(6,lx,col) - fIn(9,lx,col)-fEq(6,lx,col)+fEq(9,lx,col) );
         % Bounce back region
         fOut(i,bbRegion) = fIn(opp(i),bbRegion);
    end

    % STREAMING STEP
    for i=1:9
       fIn(i,:,:) = ...
         circshift(fOut(i,:,:), [0,cx(i),cy(i)]);
    end

    % VISUALIZATION
    if (mod(cycle,tPlot)==0)
        u = reshape(sqrt(ux.^2+uy.^2),lx,ly);
        u(bbRegion) = nan;
        imagesc(u');
        axis equal off; drawnow
    end
end