Codeforces 742B-Arpa’s obvious problem and Mehrdad’s terrible solution

Arpa’s obvious problem and Mehrdad’s terrible solution
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

There are some beautiful girls in Arpa’s land as mentioned before.

Once Arpa came up with an obvious problem:

Given an array and a number x, count the number of pairs of indices i, j (1 ≤ i < j ≤ n) such that , where  is bitwise xoroperation (see notes for explanation).

Codeforces 742B-Arpa’s obvious problem and Mehrdad’s terrible solution_第1张图片

Immediately, Mehrdad discovered a terrible solution that nobody trusted. Now Arpa needs your help to implement the solution to that problem.

Input

First line contains two integers n and x (1 ≤ n ≤ 105, 0 ≤ x ≤ 105) — the number of elements in the array and the integer x.

Second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the elements of the array.

Output

Print a single integer: the answer to the problem.

Examples
input
2 3
1 2
output
1
input
6 1
5 1 2 3 4 1
output
2
Note

In the first sample there is only one pair of i = 1 and j = 2 so the answer is 1.

In the second sample the only two pairs are i = 3j = 4 (since ) and i = 1j = 5 (since ).

A bitwise xor takes two bit integers of equal length and performs the logical xor operation on each pair of corresponding bits. The result in each position is 1 if only the first bit is 1 or only the second bit is 1, but will be 0 if both are 0 or both are 1. You can read more about bitwise xor operation here: https://en.wikipedia.org/wiki/Bitwise_operation#XOR.


题意:给出含有n个数的数组a[],求在数组中有多少对 a[i]^a[j]==x。

解题思路:若a xor b=c,则c xor b=a 且c xor a=b,用map来记录x^a[i]的答案在数组a[]中出现过几次

#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 

using namespace std;

#define ll long long

ll a[100009];

int main()
{
    ll n,x;
    while(~scanf("%lld %lld",&n,&x))
    {
        mapp;
        for(int i=0;i

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