HIbernate--HQL举例+详解(三)

多表查询

准备数据
增加一个LinkMAN实体类,与Customer形成多对一关系。

public class Customer {
	
	private Long cust_id;
	private String cust_name;
	private String cust_source;
	private String cust_industry;
	private String cust_level;
	private String cust_linkman;
	private String cust_phone;
	private String cust_mobile;
	//使用set集合,表达一对多关系
	private Set<LinkMan> linkMens = new HashSet<LinkMan>();
	
	public Customer() {
	}
	public Set<LinkMan> getLinkMens() {
		return linkMens;
	}
	public void setLinkMens(Set<LinkMan> linkMens) {
		this.linkMens = linkMens;
	}
	public Long getCust_id() {
		return cust_id;
	}
	public void setCust_id(Long cust_id) {
		this.cust_id = cust_id;
	}
	public String getCust_name() {
		return cust_name;
	}
	public void setCust_name(String cust_name) {
		this.cust_name = cust_name;
	}
	public String getCust_source() {
		return cust_source;
	}
	public void setCust_source(String cust_source) {
		this.cust_source = cust_source;
	}
	public String getCust_industry() {
		return cust_industry;
	}
	public void setCust_industry(String cust_industry) {
		this.cust_industry = cust_industry;
	}
	public String getCust_level() {
		return cust_level;
	}
	public void setCust_level(String cust_level) {
		this.cust_level = cust_level;
	}
	public String getCust_linkman() {
		return cust_linkman;
	}
	public void setCust_linkman(String cust_linkman) {
		this.cust_linkman = cust_linkman;
	}
	public String getCust_phone() {
		return cust_phone;
	}
	public void setCust_phone(String cust_phone) {
		this.cust_phone = cust_phone;
	}
	public String getCust_mobile() {
		return cust_mobile;
	}
	public void setCust_mobile(String cust_mobile) {
		this.cust_mobile = cust_mobile;
	}
	public Customer(Long cust_id, String cust_name, String cust_level) {
		super();
		this.cust_id = cust_id;
		this.cust_name = cust_name;
		this.cust_level = cust_level;
	}
}
public class LinkMan {

	private Long lkm_id;
	private Character lkm_gender;
	private String lkm_name;
	private String lkm_phone;
	private String lkm_email;
	private String lkm_qq;
	private String lkm_mobile;
	private String lkm_memo;
	private String lkm_position;
	//表达多对一关系
	private Customer customer ;
	
	public Customer getCustomer() {
		return customer;
	}
	public void setCustomer(Customer customer) {
		this.customer = customer;
	}
	public Long getLkm_id() {
		return lkm_id;
	}
	public void setLkm_id(Long lkm_id) {
		this.lkm_id = lkm_id;
	}
	public Character getLkm_gender() {
		return lkm_gender;
	}
	public void setLkm_gender(Character lkm_gender) {
		this.lkm_gender = lkm_gender;
	}
	public String getLkm_name() {
		return lkm_name;
	}
	public void setLkm_name(String lkm_name) {
		this.lkm_name = lkm_name;
	}
	public String getLkm_phone() {
		return lkm_phone;
	}
	public void setLkm_phone(String lkm_phone) {
		this.lkm_phone = lkm_phone;
	}
	public String getLkm_email() {
		return lkm_email;
	}
	public void setLkm_email(String lkm_email) {
		this.lkm_email = lkm_email;
	}
	public String getLkm_qq() {
		return lkm_qq;
	}
	public void setLkm_qq(String lkm_qq) {
		this.lkm_qq = lkm_qq;
	}
	public String getLkm_mobile() {
		return lkm_mobile;
	}
	public void setLkm_mobile(String lkm_mobile) {
		this.lkm_mobile = lkm_mobile;
	}
	public String getLkm_memo() {
		return lkm_memo;
	}
	public void setLkm_memo(String lkm_memo) {
		this.lkm_memo = lkm_memo;
	}
	public String getLkm_position() {
		return lkm_position;
	}
	public void setLkm_position(String lkm_position) {
		this.lkm_position = lkm_position;
	}
}

表中数据如下:
HIbernate--HQL举例+详解(三)_第1张图片
HIbernate--HQL举例+详解(三)_第2张图片

内连接和迫切内连接

  • 内连接
    SQL语句:select * from cst_customer cus,cst_linkman lin where cus.cust_id=lin.lkm_cust_id
    hql语句:from Customer c inner join c.linkMens
    query.list()返回的list里面每部分是数组形式
  • 迫切内连接
    迫切内连接和内连接底层实现一样
    区别:使用内连接返回list每部分是数组,使用迫切内连接返回list每部分是对象。
    hql语句:from Customer c inner join fetch c.linkMens

例子:

//内连接和迫切内连接
@Test
	public void fun1(){
		Session session = HibernateUtils.openSession();
		Transaction tx = session.beginTransaction();
		//----------------------------------------------------
		String hql1 = " from Customer c inner join c.linkMens ";//内连接
		String hql2 = "from Customer c inner join fetch c.linkMens";//迫切内连接
		
		Query query1 = session.createQuery(hql1);
		Query query2 = session.createQuery(hql2);
		
		
		List<Object[]> list1 = query1.list();
		List<Customer> list2 = query2.list();
		
		for(Object[] arr : list1){
			System.out.println(Arrays.toString(arr));
		}
		
		System.out.println(list2);
		//----------------------------------------------------
		tx.commit();
		session.close();
		
	}

运行JUnit测试输出:

Hibernate: 
    select
        customer0_.cust_id as cust_id1_0_0_,
        linkmens1_.lkm_id as lkm_id1_1_1_,
        customer0_.cust_name as cust_nam2_0_0_,
        customer0_.cust_source as cust_sou3_0_0_,
        customer0_.cust_industry as cust_ind4_0_0_,
        customer0_.cust_level as cust_lev5_0_0_,
        customer0_.cust_linkman as cust_lin6_0_0_,
        customer0_.cust_phone as cust_pho7_0_0_,
        customer0_.cust_mobile as cust_mob8_0_0_,
        linkmens1_.lkm_gender as lkm_gend2_1_1_,
        linkmens1_.lkm_name as lkm_name3_1_1_,
        linkmens1_.lkm_phone as lkm_phon4_1_1_,
        linkmens1_.lkm_email as lkm_emai5_1_1_,
        linkmens1_.lkm_qq as lkm_qq6_1_1_,
        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,
        linkmens1_.lkm_memo as lkm_memo8_1_1_,
        linkmens1_.lkm_position as lkm_posi9_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_1_ 
    from
        cst_customer customer0_ 
    inner join
        cst_linkman linkmens1_ 
            on customer0_.cust_id=linkmens1_.lkm_cust_id
Hibernate: 
    select
        customer0_.cust_id as cust_id1_0_0_,
        linkmens1_.lkm_id as lkm_id1_1_1_,
        customer0_.cust_name as cust_nam2_0_0_,
        customer0_.cust_source as cust_sou3_0_0_,
        customer0_.cust_industry as cust_ind4_0_0_,
        customer0_.cust_level as cust_lev5_0_0_,
        customer0_.cust_linkman as cust_lin6_0_0_,
        customer0_.cust_phone as cust_pho7_0_0_,
        customer0_.cust_mobile as cust_mob8_0_0_,
        linkmens1_.lkm_gender as lkm_gend2_1_1_,
        linkmens1_.lkm_name as lkm_name3_1_1_,
        linkmens1_.lkm_phone as lkm_phon4_1_1_,
        linkmens1_.lkm_email as lkm_emai5_1_1_,
        linkmens1_.lkm_qq as lkm_qq6_1_1_,
        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,
        linkmens1_.lkm_memo as lkm_memo8_1_1_,
        linkmens1_.lkm_position as lkm_posi9_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_0__,
        linkmens1_.lkm_id as lkm_id1_1_0__ 
    from
        cst_customer customer0_ 
    inner join
        cst_linkman linkmens1_ 
            on customer0_.cust_id=linkmens1_.lkm_cust_id
//内连接,两部分,以数组形式返回
[per.zhang.domain.Customer@48e64352, per.zhang.domain.LinkMan@200606de]
[per.zhang.domain.Customer@48e64352, per.zhang.domain.LinkMan@750fe12e]
[per.zhang.domain.Customer@f8908f6, per.zhang.domain.LinkMan@3e587920]
[per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.LinkMan@24f43aa3]
[per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.LinkMan@63fd4873]
[per.zhang.domain.Customer@1e11bc55, per.zhang.domain.LinkMan@7544a1e4]
[per.zhang.domain.Customer@1e11bc55, per.zhang.domain.LinkMan@70e0accd]
[per.zhang.domain.Customer@7957dc72, per.zhang.domain.LinkMan@6ab72419]
//迫切内连接 以对象形式返回,linkMan封装到了Customer的Set集合中
[per.zhang.domain.Customer@48e64352, per.zhang.domain.Customer@48e64352, per.zhang.domain.Customer@f8908f6, per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.Customer@2ef8a8c3, per.zhang.domain.Customer@1e11bc55, per.zhang.domain.Customer@1e11bc55, per.zhang.domain.Customer@7957dc72]

外连接和迫切外连接

@Test
	//外连接和迫切外连接
	public void fun2(){
		Session session = HibernateUtils.openSession();
		Transaction tx = session.beginTransaction();
		//----------------------------------------------------
		String hql1 = " from Customer c right join c.linkMens ";//右外连接
		String hql2 = " from Customer c right join fetch c.linkMens ";//迫切右外连接
		
		Query query1 = session.createQuery(hql1);
		Query query2 = session.createQuery(hql2);
		
		
		List<Object[]> list1 = query1.list();
		List<Customer> list2 = query2.list();
		
		for(Object[] arr : list1){
			System.out.println(Arrays.toString(arr));
		}
		
		System.out.println(list2);
		//----------------------------------------------------
		tx.commit();
		session.close();
		
	}

运行JUnit测试输出:

Hibernate: 
    select
        customer0_.cust_id as cust_id1_0_0_,
        linkmens1_.lkm_id as lkm_id1_1_1_,
        customer0_.cust_name as cust_nam2_0_0_,
        customer0_.cust_source as cust_sou3_0_0_,
        customer0_.cust_industry as cust_ind4_0_0_,
        customer0_.cust_level as cust_lev5_0_0_,
        customer0_.cust_linkman as cust_lin6_0_0_,
        customer0_.cust_phone as cust_pho7_0_0_,
        customer0_.cust_mobile as cust_mob8_0_0_,
        linkmens1_.lkm_gender as lkm_gend2_1_1_,
        linkmens1_.lkm_name as lkm_name3_1_1_,
        linkmens1_.lkm_phone as lkm_phon4_1_1_,
        linkmens1_.lkm_email as lkm_emai5_1_1_,
        linkmens1_.lkm_qq as lkm_qq6_1_1_,
        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,
        linkmens1_.lkm_memo as lkm_memo8_1_1_,
        linkmens1_.lkm_position as lkm_posi9_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_1_ 
    from
        cst_customer customer0_ 
    right outer join
        cst_linkman linkmens1_ 
            on customer0_.cust_id=linkmens1_.lkm_cust_id
Hibernate: 
    select
        customer0_.cust_id as cust_id1_0_0_,
        linkmens1_.lkm_id as lkm_id1_1_1_,
        customer0_.cust_name as cust_nam2_0_0_,
        customer0_.cust_source as cust_sou3_0_0_,
        customer0_.cust_industry as cust_ind4_0_0_,
        customer0_.cust_level as cust_lev5_0_0_,
        customer0_.cust_linkman as cust_lin6_0_0_,
        customer0_.cust_phone as cust_pho7_0_0_,
        customer0_.cust_mobile as cust_mob8_0_0_,
        linkmens1_.lkm_gender as lkm_gend2_1_1_,
        linkmens1_.lkm_name as lkm_name3_1_1_,
        linkmens1_.lkm_phone as lkm_phon4_1_1_,
        linkmens1_.lkm_email as lkm_emai5_1_1_,
        linkmens1_.lkm_qq as lkm_qq6_1_1_,
        linkmens1_.lkm_mobile as lkm_mobi7_1_1_,
        linkmens1_.lkm_memo as lkm_memo8_1_1_,
        linkmens1_.lkm_position as lkm_posi9_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_1_,
        linkmens1_.lkm_cust_id as lkm_cus10_1_0__,
        linkmens1_.lkm_id as lkm_id1_1_0__ 
    from
        cst_customer customer0_ 
    right outer join
        cst_linkman linkmens1_ 
            on customer0_.cust_id=linkmens1_.lkm_cust_id
            //外连接,两部分,以数组形式返回
[pers.zhang.domain.Customer@48e64352, pers.zhang.domain.LinkMan@200606de]
[pers.zhang.domain.Customer@48e64352, pers.zhang.domain.LinkMan@750fe12e]
[pers.zhang.domain.Customer@f8908f6, pers.zhang.domain.LinkMan@3e587920]
[pers.zhang.domain.Customer@2ef8a8c3, pers.zhang.domain.LinkMan@24f43aa3]
[pers.zhang.domain.Customer@2ef8a8c3, pers.zhang.domain.LinkMan@63fd4873]
[pers.zhang.domain.Customer@1e11bc55, pers.zhang.domain.LinkMan@7544a1e4]
[pers.zhang.domain.Customer@1e11bc55, pers.zhang.domain.LinkMan@70e0accd]
[pers.zhang.domain.Customer@7957dc72, pers.zhang.domain.LinkMan@6ab72419]
[null, pers.zhang.domain.LinkMan@3aacf32a]
//外连接,以对象形式返回,linkMan封装到了Customer的Set集合中
[cn.itcast.domain.Customer@48e64352, pers.zhang.domain.Customer@48e64352, cn.itcast.domain.Customer@f8908f6, pers.zhang.domain.Customer@2ef8a8c3, cn.itcast.domain.Customer@2ef8a8c3, pers.zhang.domain.Customer@1e11bc55, cn.itcast.domain.Customer@1e11bc55, pers.zhang.domain.Customer@7957dc72, null]

子查询

对于子查询的数据库,Hibernate支持在查询中使用子查询。一个子查询必须被圆括号包围起来(经常是SQL聚集函数的圆括号)。甚至相互关联的子查询(引用到外部查询中的别名的子查询)也是允许的。
select c.cust_id,c.cust_name,c.cust_level
from Customer c
where c.cust_id = (
select l.customer.cust_id
from LinkMan l
where l.lkm_name like ‘联想02’)

例子:

@Test
	//子查询
	public void fun4(){
		Session session = HibernateUtils.openSession();
		Transaction tx = session.beginTransaction();
		//----------------------------------------------------
		//查询linkman的名字为‘联想02’的customer对象的id,名字,和客户等级
		String hql = "select c.cust_id,c.cust_name,c.cust_level "
						+ "from Customer c "
						+ "where c.cust_id = "
							+ "(select l.customer.cust_id "
								+ "from LinkMan l "
								+ "where l.lkm_name like '联想02')";
		
		Query query = session.createQuery(hql);
		
		List<Object[]> list = query.list();
		
		for(Object[] arr : list){
			System.out.println(Arrays.toString(arr));
		}
		//----------------------------------------------------
		tx.commit();
		session.close();
		
	}

运行JUnit测试输出:

Hibernate: 
    select
        customer0_.cust_id as col_0_0_,
        customer0_.cust_name as col_1_0_,
        customer0_.cust_level as col_2_0_ 
    from
        cst_customer customer0_ 
    where
        customer0_.cust_id=(
            select
                linkman1_.lkm_cust_id 
            from
                cst_linkman linkman1_ 
            where
                linkman1_.lkm_name like '联想02'
        )
[2, 联想, 3]

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